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Quantum Wavefunction | Quantum physics | Physics | Khan Academy
Khan Academy's beginner introduction to what the quantum wavefunction is, how to use it and where it comes from. Watch for how ψ is turned into probabilities, the recipe that Parts 2 and 3 make exact.
Watch on YouTubeMore from the video vault
Lecture 3: The Wave Function
Allan Adams's MIT 8.04 lecture introduces the wavefunction as the fundamental description of a quantum system, states the probability rule and normalization, shows why a wave of definite momentum is equally likely to be found anywhere, and restates superposition and uncertainty in the language of wavefunctions. A university-level companion to Parts 1 to 3; expectation values arrive in his next lecture.
Watch on YouTubeQuantum Wave Functions: What's Actually Waving?
Nick Lucid asks the question at the heart of Part 1 and Part 6, what exactly is waving, and ties the wavefunction to probability and statistics. A lively second pass on what the wavefunction is, and what it is not.
Watch on YouTube- Quantum Wavefunction | Quantum physics | Physics | Khan Academy — Khan Academy — https://www.youtube.com/watch?v=OFwskHrtYQ4
- Lecture 3: The Wave Function — MIT OpenCourseWare — https://www.youtube.com/watch?v=Ei8CFin00PY
- Quantum Wave Functions: What's Actually Waving? — The Science Asylum — https://www.youtube.com/watch?v=vShpwplJyXk
Today's mission
Dr. Q · cold openPsigor, put the dice away. Yes, I told you to bring them, but tonight we gamble on something far stranger. For two whole chapters I have chalked the Greek letter ψ on every blackboard in this lab as though you knew what it meant, and you have been far too polite to ask. Ask now! ψ is the wavefunction: a complex number attached to every place a particle might be found. It is not the particle smeared out like jam, and it is not a ripple in anything you could touch. In the summer of 1926 Max Born found the recipe that turns it into odds: square its size, measure an area, and you know exactly how often a detector will click there, though never where the next click lands. Fire up the detector. Mwahaha, measurably!
By the end of this session you will be able to:
- Describe the wavefunction ψ as a complex-valued probability amplitude with a magnitude and a phase at every position
- Apply Born's rule to find the probability density, |ψ|², and to calculate probabilities as areas under its curve, including the narrow-window shortcut
- Normalize a simple wavefunction and explain why the total probability must equal 1
- Calculate the expectation value and the spread of a particle's position, and explain why single outcomes are random while statistics are exact
- Distinguish an unobservable global phase from a measurable relative phase, and show how a relative phase moves probability
- Explain why a many-particle wavefunction lives in configuration space rather than ordinary space
Read it — or listen along
6 parts. Press play on any part and the paragraph being read lights up as Dr. Q speaks.
An Arrow at Every Point
Chapter 7 left us a rule and chapter 8 a bargain, both written with a symbol we never properly defined. Electrons arrived as single dots that built interference stripes; squeezed wave packets bulged in momentum. The thing that interferes and bulges is the wavefunction, ψ. For one particle moving along a line, ψ(x) attaches a number to every position x, and the number is complex: it has a real part and an imaginary part or, in the picture of chapter 2, it is an arrow with a length and a direction. The arrow's length is called the magnitude and its direction the phase.
Physicists call ψ(x) the probability amplitude for finding the particle at x. The word amplitude is chosen with care: ψ is not itself a probability but the raw material from which probabilities are made. Complex numbers are needed because the phase carries physical information. A particle with a perfectly definite momentum p is described by arrows of identical length everywhere whose direction turns steadily along x, completing one full turn every de Broglie wavelength λ = h/p. Its real part undulates like a cosine and its imaginary part like a sine, yet its magnitude is the same at every point. The winding phase is the momentum; the constant magnitude says the particle is equally likely to be found anywhere.
Chapter 6 insisted that nothing material ripples in a matter wave. When Erwin Schrödinger published his wave equation in 1926 he hoped otherwise, proposing that the electron really is a continuous cloud of charge with density proportional to |ψ|², spread through space like jam. Max Born recalled in his Nobel lecture that to him and his colleagues in Göttingen this seemed unacceptable, because experimenters could already count particles one at a time with scintillation screens and Geiger counters, and photograph their individual tracks in cloud chambers. Detectors never register three-tenths of an electron. Notice, too, that ψ itself is not a density of anything: for one particle on a line it is measured in metres to the power minus one-half, and only its square has the units of a probability per metre.
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Born's Rule: Square It, Then Take an Area
Born's rule, in its modern form for position, says this. Square the magnitude of the amplitude and you have the probability density, |ψ(x)|²: the probability per unit length of finding the particle near x when its position is measured. To square a complex number's magnitude, add the squares of its real and imaginary parts or, equivalently, multiply it by its complex conjugate, the mirror-image arrow with its angle reversed. Either way the result is a length squared, so a wavefunction that is negative or imaginary somewhere can never produce a negative probability: sign and phase vanish in the squaring.
A density is not yet a probability, any more than a population density of 2,000 people per square kilometre tells you how many people live on your street. You need a size of region. For a narrow window of width Δx around x, the probability of finding the particle there is approximately |ψ(x)|² times Δx. For a wider region, from a to b, slice it into thin strips, find the probability of each, and add them up. In the limit of infinitely thin strips that sum becomes the area under the curve of |ψ|² between a and b, which mathematicians call the integral. Probability, in Born's rule, is area.
Try it on the simplest bound state. An electron trapped between hard walls one nanometre apart, in its lowest-energy state (chapter 11 derives it), has ψ = √(2/L)·sin(πx/L), so its density peaks at the centre at 2 per nanometre. The chance of finding it within 0.05 nm of the centre is therefore about 2 per nanometre × 0.1 nm = 0.20, and the exact area is 0.198. The same squaring recipe governs energy, spin and every other measurable quantity (chapters 14, 15 and 17). One caution: the rule is a postulate of quantum mechanics, not a consequence of Schrödinger's equation, and attempts to derive it from deeper principles, notably within the many-worlds interpretation, remain debated.
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Normalization: It Has to Be Somewhere
Measure the particle's position across the whole line and you will find it somewhere, every single time. The probabilities of all the places must therefore add up to exactly 1: the total area under |ψ|² must equal 1, and a wavefunction that meets this condition is said to be normalized. Solving a wave equation usually gives a shape without fixing its overall size, because any solution multiplied by a constant is still a solution. Normalization fixes the size in two steps: find the total area under the square of your unnormalized shape, then divide the shape by the square root of that area. The square root appears because probabilities, not amplitudes, must total 1.
Here is the recipe on a smooth hump that vanishes at two walls a distance L apart: ψ(x) = A·x(L − x) between the walls and zero outside, with A to be found. The area under x²(L − x)² from 0 to L works out to L⁵/30, so normalization demands A² times L⁵/30 = 1, giving A = √(30/L⁵). For L = 1 nanometre, A is about 5.48 in units of nanometres to the power minus five-halves. The density then peaks at the centre at 1.875 per nanometre, the middle half of the gap holds 79.3 percent of the probability, and each outer quarter 10.35 percent.
Not every wave can be normalized. The endless wave of definite momentum from Part 1 has a density that is the same everywhere, so the area under it is infinite. Physicists use such plane waves as idealizations, limits of very long wave packets, but a real particle is always a normalizable packet. Once normalized, a wavefunction stays normalized: Schrödinger's equation, next chapter's subject, carries ψ forward in time without creating or destroying total probability. Normalization does leave one freedom untouched: multiplying ψ by −1, or by any complex number of size 1, changes no area at all, a loose end Part 5 ties up.
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Random Clicks, Exact Statistics
Born's rule predicts probabilities: nothing less, and nothing more. Prepare a thousand electrons in exactly the same state and measure each one's position. Every measurement returns a single, definite place, and quantum mechanics cannot say in advance which place it will be. Yet the fraction found in any region converges, as runs pile up, onto the area under |ψ|² for that region, just as Akira Tonomura's 1989 electron experiment showed in chapter 7. In standard quantum mechanics the randomness is fundamental, not a record of details we failed to track, although some interpretations dispute that. Einstein never accepted it: on 4 December 1926 he wrote to Born that he, at any rate, was convinced the Old One does not play dice.
The sharpest prediction for an ensemble, a large collection of identically prepared systems, is its average. The expectation value of position, ⟨x⟩, is the average position weighted by the probability density: multiply each position by |ψ|² there and take the total area. It is the long-run mean of many measurements, not a forecast for any single one, and it need not be a place the particle can be found. The second state of the one-nanometre box has a node, a point where |ψ|² vanishes, exactly at the centre, which is also where ⟨x⟩ sits: only 0.65 percent of detections land within 0.05 nm of the average position. The spread is the standard deviation σ: the square root of the mean of the squared positions minus the square of the mean, the very Δx of chapter 8.
How exact are the statistics? The average of N measured positions wanders about ⟨x⟩ by roughly σ/√N, so for a packet with σ = 0.09 nm ten thousand detections pin the mean down to within about 0.0009 nm. Born's rule itself has been put on trial. In 1994 Rafael Sorkin noted that if probabilities come from squaring sums of amplitudes, interference only ever involves pairs of paths, so a three-slit pattern is fixed entirely by the single-slit and two-slit patterns. In 2010 Urbasi Sinha, Gregor Weihs and colleagues sent photons through three slits and bounded any genuinely three-path term below one percent of ordinary two-path interference, and in 2017 Weihs's group in Innsbruck pushed the bound below one part in ten thousand with a five-path interferometer. Born's footnote has held.
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Phase: Invisible Alone, Decisive Together
Multiply a wavefunction everywhere by the same complex number of size 1, such as −1 or i, and every arrow turns through the same angle while keeping its length. This is a change of global phase, and since |ψ|² depends only on lengths, every density, every area and every expectation value stays exactly as it was. No experiment can tell ψ from −ψ; they are two labels for one physical state. The Born Rule Detector's phase-flip button does exactly this, and changes nothing you can measure. Squaring hides the phase of a single amplitude completely.
Relative phase is another matter. When a wavefunction is a sum of two parts, ψ₁ + ψ₂, the density, |ψ₁ + ψ₂|², contains chapter 7's interference term, which depends on the angle between the two arrows at each point. Rotate one part relative to the other and probability moves. Put an electron in the one-nanometre box in the state 0.6ψ₁ + 0.8ψ₂, where ψ₁ and ψ₂ are the two lowest box states and 0.6² + 0.8² = 1 keeps it normalized. The second state is positive in the left half of the box and negative in the right, so it reinforces the first on the left and partly cancels it on the right: 90.7 percent of detections land in the left half. Flip the sign of ψ₂ alone and only 9.3 percent do. Same ingredients, same proportions, opposite outcome.
Phase can also vary from place to place within a single wave, and then it encodes motion. Take a packet whose arrows all point the same way and twist them so that the phase winds one full turn every distance λ along x. At that instant |ψ|² is untouched, but the packet now carries an average momentum of h/λ and sets off moving, while its untwisted twin stays centred and merely spreads. That is why the state of a particle is the full complex ψ, not merely |ψ|²: the density says where the particle may be found now, and the phase says where the density is going.
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Not a Wave in Space: Configuration Space
For a single particle the jam picture is tempting, because ψ(x) can be drawn as a curve over ordinary space. Add a second particle and the picture breaks. Two particles on a line are described not by two waves on that line but by one wavefunction Ψ(x₁, x₂), which assigns an amplitude to every pair of positions: particle one at x₁ and particle two at x₂. It is a function on a plane, not on a line, and |Ψ(x₁, x₂)|² is a joint probability density, the probability per unit area of finding the first particle near x₁ and the second near x₂. In three dimensions two particles need six coordinates and N particles need 3N. The space of all possible arrangements is called configuration space, and that, not the room you are sitting in, is where the wavefunction lives.
Three consequences follow. First, Ψ has no value at a point of ordinary space, only at a whole arrangement, so it cannot be a substance spread through the room. Second, Ψ need not split into one wave per particle; when it does not, the particles are entangled, and what is found for one is correlated with what is found for the other (chapter 20). Third, the bookkeeping explodes. Store Ψ on a grid of 100 points along each axis and one electron needs a million complex numbers, two electrons a million million, and fourteen electrons 10⁸⁴, more than the roughly 10⁸⁰ atoms in the observable universe. That is why quantum chemistry lives on clever approximations, and why Richard Feynman proposed in 1981 to simulate quantum systems with quantum machines.
Experiments read configuration space one sample at a time. Quantum gas microscopes, pioneered by Markus Greiner's group at Harvard in 2009, photograph individual atoms held in a lattice of laser light; each picture is a single draw of where the whole crowd was found together, one point in a space of enormous dimension, and only many pictures reveal the joint probabilities. What Ψ is, physically, remains open. Many-worlds and pilot-wave theorists treat it as real; others regard it as a tool for computing odds. A 2012 theorem by Matthew Pusey, Jonathan Barrett and Terry Rudolph shows, under stated assumptions, that it cannot be a mere summary of ignorance about some deeper state. Whatever it is, Born's rule is how we use it.
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Go deeper on video
19 more videos for this chapter, 14 of them from universities, research institutes and Nobel lectures. The clips under “Watch this part” in the lesson start at the moment that matters.
Key equations
Born's rule: the probability density
Square the size of the amplitude to get the probability per unit length of finding the particle near x. The result is never negative, whatever the sign or phase of psi.
| Symbol | Meaning | Unit |
|---|---|---|
| ρ(x) | probability density for position | 1/m |
| ψ(x) | probability amplitude (wavefunction) of one particle on a line | 1/√m |
| ψ*(x) | complex conjugate of ψ, the same arrow with its phase reversed | 1/√m |
Say it: “rho of x equals the magnitude of psi of x, squared, which is psi-star times psi, the sum of the squares of its real and imaginary parts”
Probability is area
The probability of a region is the area under the density curve across it. For a window narrow enough that the density is nearly constant, the area is simply height times width.
| Symbol | Meaning | Unit |
|---|---|---|
| P | probability, a pure number between 0 and 1 | none |
| a, b | edges of the region | m |
| x₀ | centre of a narrow window | m |
| Δx | width of the narrow window | m |
Say it: “the probability of finding the particle between a and b equals the integral from a to b of the magnitude of psi squared, d x; for a narrow window, it is approximately the density at the window's centre times its width, delta x”
Normalization
The particle is certain to be found somewhere, so the total area under the density must be exactly 1. To normalize a shape, divide it by the square root of the total area under its square.
| Symbol | Meaning | Unit |
|---|---|---|
| |ψ(x)|² | probability density | 1/m |
| dx | width of a thin slice of the line | m |
Say it: “the integral over all x of the magnitude of psi squared equals 1”
Expectation value and spread
The expectation value is the probability-weighted average position, the long-run mean of many measurements on identically prepared particles. Sigma is the spread of those results, the delta x of the uncertainty principle.
| Symbol | Meaning | Unit |
|---|---|---|
| ⟨x⟩ | expectation value (average) of position | m |
| ⟨x²⟩ | average of the squared position | m² |
| σₓ | standard deviation of position results | m |
Say it: “the expectation value of x equals the integral over all x of x times the magnitude of psi squared, d x; sigma x equals the square root of the average of x squared minus the square of the average of x”
Global phase versus relative phase
A global phase theta rotates every arrow equally and changes nothing measurable. A relative phase phi between two parts changes the interference term, and so moves probability from place to place.
| Symbol | Meaning | Unit |
|---|---|---|
| θ | global phase applied to the whole wavefunction | rad |
| φ | relative phase between the two parts | rad |
| ψ₁, ψ₂ | two component amplitudes | 1/√m |
| Re | real part of a complex number | none |
Say it: “the magnitude of e to the i theta times psi, squared, equals the magnitude of psi squared; but the magnitude of psi 1 plus e to the i phi times psi 2, squared, equals the magnitude of psi 1 squared plus the magnitude of psi 2 squared plus twice the real part of e to the i phi times psi 1 star times psi 2”
Two particles: configuration space
Two particles share one wavefunction defined on the plane of all position pairs, not two waves on the line. In three dimensions N particles need 3N coordinates.
| Symbol | Meaning | Unit |
|---|---|---|
| Ψ(x₁, x₂) | joint amplitude for particle one at x₁ and particle two at x₂ | 1/m |
| x₁, x₂ | positions of particles one and two | m |
| dP | probability for a small patch of the plane | none |
Say it: “the probability of finding particle one near x 1 and particle two near x 2 equals the magnitude of capital psi of x 1 and x 2, squared, times d x 1 times d x 2; the double integral over both positions equals 1”
Real numbers, step by step
Cover the steps, try the problem yourself, then reveal the solution one step at a time.
Normalizing a hump between two walls
A particle confined between walls at x = 0 and x = L = 1.0 nm is described by ψ(x) = A·x(L − x) inside and zero outside. Find the normalization constant A, the peak probability density, the probability of finding the particle in the middle half of the gap, and the expectation value and spread of its position.
Step 1: Set up the condition: the total area under |ψ|² must be 1, so A² times the area under x²(L − x)² from 0 to L must equal 1.
Step 2: Expand x²(L − x)² = L²x² − 2Lx³ + x⁴ and take the area term by term: L²·L³/3 − 2L·L⁴/4 + L⁵/5 = L⁵ × (1/3 − 1/2 + 1/5) = L⁵/30.
Step 3: So A² = 30/L⁵ and A = √(30/L⁵). With L = 1 nanometre, A = √30 ≈ 5.48 in units of nanometres to the power minus five-halves.
Step 4: Peak density, at x = L/2: A² × (L/2)² × (L/2)² = (30/L⁵) × (L⁴/16) = 1.875/L = 1.875 per nanometre.
Step 5: Outer quarter, from 0 to L/4: with u = x/L the probability is 30 times the area under u²(1 − u)² from 0 to 1/4, which is 30 × (1/192 − 1/512 + 1/5120) = 0.1035. The far quarter is the same by symmetry, so the middle half holds 1 − 2 × 0.1035 = 0.793.
Step 6: The hump is symmetric about the centre, so ⟨x⟩ = L/2 = 0.50 nm. The average of x² works out to 2L²/7, so σ = L × √(2/7 − 1/4) = L/√28 ≈ 0.189 nm.
A = √(30/L⁵) ≈ 5.48 nm to the power minus five-halves; peak density 1.875 per nanometre; 79.3 percent in the middle half; ⟨x⟩ = 0.50 nm and σ ≈ 0.19 nm
Why it matters: Normalization is nothing more than the demand that the particle be somewhere. This simple hump is also almost exactly the box's true ground state, √(2/L)·sin(πx/L), which chapter 11 derives: once both are normalized, the two curves never differ by more than about 4 percent of the sine's peak height.
Global phase versus relative phase
An electron in a box 1.0 nm wide is in the state ψ = 0.6ψ₁ + 0.8ψ₂, where ψ₁ = √(2/L)·sin(πx/L) and ψ₂ = √(2/L)·sin(2πx/L) are the two lowest box states. Find the probability of detecting it in the left half of the box and its expectation value of position, then repeat for −ψ and for 0.6ψ₁ − 0.8ψ₂. Use these areas: ψ₁² and ψ₂² each have area 0.5 over the left half; ψ₁ψ₂ has area 4/(3π) ≈ 0.4244 over the left half and zero over the whole box; and x·ψ₁ψ₂ has area −16L/(9π²) ≈ −0.1801 nm over the whole box.
Step 1: Square: |ψ|² = 0.36ψ₁² + 0.64ψ₂² + 0.96ψ₁ψ₂. Over the whole box the cross term has zero area, so the total is 0.36 + 0.64 = 1. The state is normalized.
Step 2: Left half: 0.36 × 0.5 + 0.64 × 0.5 + 0.96 × 0.4244 = 0.5 + 0.4074 = 0.907, or 90.7 percent.
Step 3: Expectation value: each squared box state alone averages to L/2, so ⟨x⟩ = 0.5 nm + 0.96 × (−0.1801 nm) = 0.327 nm.
Step 4: Global phase: −ψ has exactly the same density at every point, so the answers are unchanged, 90.7 percent and 0.327 nm.
Step 5: Relative phase: for 0.6ψ₁ − 0.8ψ₂ the cross term changes sign. Left half: 0.5 − 0.4074 = 0.093, and ⟨x⟩ = 0.5 nm + 0.1729 nm = 0.673 nm.
0.6ψ₁ + 0.8ψ₂ and its negative: 90.7 percent in the left half, ⟨x⟩ = 0.327 nm; 0.6ψ₁ − 0.8ψ₂: 9.3 percent, ⟨x⟩ = 0.673 nm
Why it matters: An overall sign is invisible, while a relative sign moves more than 80 percentage points of probability across the box. This is exactly the Born Rule Detector's superposition preset and its flip button. Left alone, the relative phase turns by itself as time passes, so the probability sloshes from side to side, as chapter 11 shows.
Random clicks, exact statistics
In the Born Rule Detector's Gaussian preset, |ψ|² is a bell curve centred at 0.40 nm with standard deviation σ = 0.09 nm. What fraction of detections should fall between 0.31 and 0.49 nm? In a run of 500 detections, how many is that, and how much should the count scatter from run to run? How many detections are needed before the running mean is typically within 0.001 nm of ⟨x⟩?
Step 1: The region from 0.31 to 0.49 nm is the centre plus or minus one standard deviation. Any bell curve holds 68.3 percent of its area there, so the probability is 0.683.
Step 2: Expected count: 500 × 0.683 ≈ 341. The run-to-run scatter follows the binomial rule, the square root of N × p × (1 − p): √(500 × 0.683 × 0.317) ≈ 10.4 detections, about 2.1 percentage points.
Step 3: The running mean wanders about ⟨x⟩ by σ/√N. Setting 0.09 nm ÷ √N = 0.001 nm gives √N = 90, so N = 8,100 detections.
68.3 percent; about 341 ± 10 of 500 detections; about 8,100 detections
Why it matters: No single click is predictable, yet the statistics are as sharp as you care to pay for: precision improves as one over the square root of the number of runs. In the lab's betting game, the fraction measured in 500 detections typically lands within about 2 percentage points of the true probability, so they are a fair check on a ±5-point bet, which the lab scores against the exact area.
What everyone gets wrong
Read the myth, decide whether you believed it, then bust it.
- Myth #1
The wavefunction is the particle itself, smeared out like jam over the region where |ψ|² is large.
TruthThat was Schrödinger's own first hope in 1926, and it fails. Detectors always register whole particles, one dot at a time, never a fraction of an electron. For two or more particles the wavefunction is not even defined at points of ordinary space, only at whole arrangements in configuration space. ψ is a probability amplitude: |ψ|² gives the probability of finding the entire particle in a region, not the amount of particle stored there.
- Myth #2
|ψ|² shows where the particle is right now, before anyone measures it, like a weather radar showing where the rain is.
Truth|ψ|² is the probability density for the outcome of a position measurement. In standard quantum mechanics the particle has no definite position until it is measured, so there is no present location for |ψ|² to map. Even in pilot-wave theory, where particles do have hidden positions, |ψ|² is the spread over many identically prepared runs and never pinpoints one particle. The expectation value, ⟨x⟩, can even fall where the particle is never found.
- Myth #3
Where ψ is negative or imaginary, the probability must be negative or imaginary too.
TruthProbabilities come from |ψ|², the sum of the squares of the real and imaginary parts, which is never negative. For a single amplitude, sign and phase vanish in the squaring. They matter only when amplitudes are added, where they decide whether the parts reinforce or cancel.
- Myth #4
The expectation value, ⟨x⟩, is the most likely place to find the particle.
Truth⟨x⟩ is the long-run average of many measurements, not the peak of |ψ|². In the second state of a one-nanometre box, ⟨x⟩ sits at the centre, where |ψ|² is exactly zero, and only 0.65 percent of detections land within 0.05 nm of it. The most probable position is wherever |ψ|² peaks.
Your turn at the controls
Welcome to the Born Rule Detector. On the dark stage a detector strip one nanometre long sits beneath two plots: the wavefunction ψ itself, orange where it is positive and violet where it is negative, and the probability density, |ψ|², in cyan. Choose a Gaussian packet, the second box state, the superposition 0.6ψ₁ + 0.8ψ₂, or draw your own amplitude with a finger or mouse, and the lab normalizes it on the spot. Press Measure and one electron strikes the strip; press the ×10, ×100 or ×1000 buttons and a magenta histogram rises to meet the cyan curve, while a second plot tracks the running mean of the detected positions as it homes in on ⟨x⟩.
Your tasks
0/5How it connects to the theory
Every control is a line of the lesson. The cyan curve is Born's rule, |ψ|²; the gold band's area is a probability; the lab's automatic rescaling of your doodle is normalization. The magenta histogram is an ensemble of identically prepared electrons, random one by one and exact in bulk, and its scatter shrinks as one over the square root of the number of detections, which is why 500 electrons are a trustworthy check on a ±5-point bet, even though the lab scores the bet against the exact area itself. The two flip buttons separate an unobservable global phase from a measurable relative phase. The one thing the lab cannot show is configuration space: it holds a single electron, and a second would need a whole extra axis.
Born Rule Detector: Measure, Repeat, Discover loads as you scroll down.
Make it stick
When you meet a wavefunction, obey its own command: SQUARE IT. S, Size and phase: ψ is a complex amplitude, an arrow at every point. Q, the Quantity you bet on is |ψ|², a probability per unit length, never ψ itself. U, Unity: normalize so the total area is exactly 1. A, Area: the probability of a region is the area under |ψ|² across it. R, Random clicks, Reliable averages: single outcomes are unpredictable, while ⟨x⟩ and σ emerge exactly from many runs. E, Extra particles, Extra dimensions: N particles live in a 3N-dimensional configuration space. I, Invisible overall phase. T, Telltale relative phase, which moves probability by interference. To use it, say 'square it' whenever you see a ψ, then walk the eight letters as a checklist before you trust any probability.
Think of a casino. The house cannot say whether the next spin of the roulette wheel will win or lose, yet its yearly takings are predictable to the percent, because averages over millions of spins are sharp. Born's rule makes quantum mechanics the perfect casino: each detection is unpredictable, the long-run fractions exact. Where it breaks: a roulette wheel obeys ordinary physics, and its randomness comes from details too fine to track, whereas standard quantum mechanics has no hidden details to track. And casino odds can only add, while quantum amplitudes carry phases, so two routes to the same outcome can cancel and make it less likely than either route alone.
The whole chapter in one lineψ is a complex amplitude; square it for probability density, take areas for odds: single clicks are random, the statistics exact.
Flashcards
Saved on this device. Knew it moves a card up a box; still learning sends it back to box 1. Boxes 4–5 count as mastered.
Play it into long-term memory
Match the vocabulary, then take the Quiz Show. Score 70% or better to tick it off your checklist.
Vocab Match
Match each term to its definition, against the clock.
- 11 pairs in 2 rounds
- 100 points a match, more on a streak
- −25 per mistake · speed bonus each round
- Finish with 3 mistakes or fewer to win
Dr. Q's Quantum Quiz Show
Welcome, contestants! 8 questions, 30 seconds each, and one mad scientist judging you, lovingly. Answer fast for a speed bonus; answer right in a row and your points multiply.
- 100 per answer
- +100 speed bonus
- ×2 streak bonus
Prove it on paper
Answer every question, check your work, and read the explanations — the stretch challenge is for the truly mad.
Work these on paper before checking the answers. Unless told otherwise, ψ describes one particle moving along a line. Tools: probability density |ψ(x)|²; probability of a region = area under |ψ|² across it; narrow-window shortcut P ≈ |ψ(x)|² × Δx; normalization means the total area is 1; ⟨x⟩ = area under x·|ψ|²; σ = √(⟨x²⟩ − ⟨x⟩²); a measured mean has typical error σ/√N; a count of N trials with probability p scatters by √(N·p·(1 − p)). Box states: ψₙ = √(2/L)·sin(nπx/L). Show units at every step.
Part A
Vocabulary
- Wavefunction
- The function ψ that assigns a complex probability amplitude to every possible position, or for many particles to every arrangement; the complete quantum description of a state.
- Probability amplitude
- A complex number whose squared magnitude gives a probability or a probability density.
- Complex conjugate
- A complex number with the sign of its imaginary part reversed, the mirror-image arrow; a number times its conjugate is its squared magnitude.
- Probability density
- Probability per unit length, area or volume; for position it is |ψ(x)|², and only its areas are probabilities.
- Born rule
- The 1926 postulate that probabilities are squared magnitudes of amplitudes; for position, the probability of a region is the area under |ψ|² across it.
- Normalization
- Scaling a wavefunction so that the total area under |ψ|² is exactly 1, because the particle must be found somewhere.
- Expectation value
- The probability-weighted average of a quantity, written ⟨x⟩ for position: the long-run mean of many measurements on identically prepared systems.
- Node
- A point where ψ, and therefore |ψ|², is zero, so the particle is never found there.
- Global phase
- A phase factor multiplying the whole wavefunction; it changes no measurable prediction.
- Relative phase
- The phase difference between the parts of a superposition; it controls their interference and so moves probability.
- Configuration space
- The space of all possible arrangements of a system's particles, with 3N dimensions for N particles in three-dimensional space; many-particle wavefunctions live there.
Part B
Questions
Auto-checked except short answers, which you mark yourself.
- Question 1.Multiple choice
Which quantity is the probability density for finding a particle near position x?
- Question 2.Multiple choice
A normalized wavefunction ψ(x) is given. Which expression gives the probability of finding the particle between x = a and x = b?
- Question 3.Multiple choice
An electron in a box is in the state ψ = 0.6ψ₁ + 0.8ψ₂. Which change alters the measured distribution of its positions?
- Question 4.True or false
A probability density |ψ(x)|² can be greater than 1 per nanometre at some point without anything being wrong.
- Question 5.True or false
The expectation value ⟨x⟩ is always a position at which the particle can actually be found.
- Question 6.True or false
If two wavefunctions have exactly the same |ψ(x)|² at one instant, they must describe the same physical state.
- Question 7.Fill in the blank
Scaling a wavefunction so that the total area under |ψ|² equals 1 is called .
- Question 8.Fill in the blank
The wavefunction of N particles in three-dimensional space is a function on a configuration space with dimensions.
- Question 9.Short answer
Give two pieces of evidence that the wavefunction is not the electron itself, smeared out like jam.
- Question 10.Short answer
A student measures the positions of 10,000 identically prepared electrons and finds that their average lies within 0.001 nm of the predicted ⟨x⟩. Yet she cannot predict where the 10,001st electron will land. Explain why both facts agree with the Born rule.
- Question 11.Calculation
A particle bound to a very narrow, deep well at x = 0 has the wavefunction ψ(x) = A·exp(−|x|/a), with a = 0.20 nm. (a) Find A. (b) Find the probability density at x = 0. (c) Find the probability that the particle is found within a distance a of the well. (d) Use the narrow-window shortcut to estimate the probability of finding it within 0.01 nm of the well, and compare with the exact value 1 − exp(−0.1).
This one asks for more than one value — give each, with its units.
- Question 12.Calculation
An electron is in the ground state of a 1.0 nm box, ψ₁ = √(2/L)·sin(πx/L). (a) What is the probability density at the centre? (b) Use the narrow-window shortcut to estimate the probability of finding it between 0.40 and 0.60 nm. (c) The exact probability is 0.2 + sin(0.2π)/π; evaluate it and explain why the shortcut comes out high. (d) The exact probability of finding it in the first 0.2 nm of the box is 0.2 − sin(0.4π)/(2π); evaluate it.
This one asks for more than one value — give each, with its units.
- Question 13.Calculation
In the lab's Gaussian preset (centre 0.40 nm, σ = 0.09 nm) you bet on the region from 0.22 to 0.58 nm. (a) What is the true probability? (b) In 500 detections, what count do you expect, and how much does it scatter, in detections and in percentage points? (c) By what factor does the scatter in percentage points shrink if you fire 2,000 detections instead? (d) How many detections bring the running mean to within about 0.003 nm of ⟨x⟩?
This one asks for more than one value — give each, with its units.
- Question 14.Calculation
An electron in a 1.0 nm box is in the state ψ = (ψ₁ + c·ψ₂)/√2, where ψ₁ and ψ₂ are the two lowest box states and c is a complex number of size 1. Over the left half of the box, ψ₁² and ψ₂² each have area 0.5 and ψ₁ψ₂ has area 4/(3π). Find the probability of detecting the electron in the left half for c = 1, c = i and c = −1.
This one asks for more than one value — give each, with its units.
Part C · optional, dangerous, extremely rewarding
Mad scientist challenge
Weigh hydrogen's electron cloud. In three dimensions Born's rule uses volume: the probability of finding the electron in a small volume is |ψ|² times that volume, and the total over all space must be 1. Hydrogen's ground state is ψ(r) = N·exp(−r/a₀), where r is the distance from the proton and a₀ = 0.0529 nm is the Bohr radius. (a) Using the volume of a thin spherical shell, 4πr²·dr, and the fact that the area under r²·exp(−2r/a₀) from 0 to infinity is a₀³/4, show that N = 1/√(πa₀³). (b) |ψ|² is greatest at r = 0, right at the proton, yet the most probable distance from the proton is a₀. Show this and resolve the apparent contradiction. (c) The probability of finding the electron within a distance R of the proton is 1 − exp(−2R/a₀)·(1 + 2R/a₀ + 2R²/a₀²). How often is it found within one Bohr radius? (d) The expectation value of the distance is ⟨r⟩ = 1.5a₀. Evaluate it and explain why it differs from the most probable distance. (e) The proton's radius is about 0.84 fm. Estimate the probability that the electron is found inside the proton.
Recap & sign-off
Key takeaways
- The wavefunction ψ(x) is a complex probability amplitude, an arrow with a magnitude and a phase at every position; it is not the particle smeared out like jam
- Born's rule (1926): |ψ(x)|² is a probability density, and the probability of finding the particle in a region is the area under |ψ|² across it
- Normalization makes the total area exactly 1, because the particle is always found somewhere; divide any shape by the square root of the area under its square
- Single outcomes are random but statistics are exact: ⟨x⟩ is the long-run mean, σ the spread, and a measured average converges with typical error σ/√N
- |ψ|² gives the odds of where a measurement will find the particle, not a map of where it is now, and ⟨x⟩ can sit where the particle is never found
- A global phase changes nothing measurable; a relative phase moves probability through interference, and a phase that winds along x means motion
- Many-particle wavefunctions live in configuration space, with 3N dimensions for N particles, so ψ is not a wave in ordinary space
Dr. Q signs offAnd there you have it, my probabilistic protégés: a wave made of possibilities, a footnote that turned it into odds, and a detector that never lies in bulk. But I have shown you only photographs. Every ψ in this chapter was frozen at a single instant, and electrons do not hold still for portraits. Next session I wheel out the engine that makes the wavefunction move: Schrödinger's equation, with an imaginary i welded to its front. Bring a spanner. Dr. Q, signing off.
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Sources & further reading
- NobelPrize.org: The Nobel Prize in Physics 1954 (Max Born, for his statistical interpretation of the wavefunction, and Walther Bothe) · nobelprize.org
- NobelPrize.org: Max Born, Nobel Lecture, The statistical interpretation of quantum mechanics (11 December 1954) · nobelprize.org
- M. Born, Zur Quantenmechanik der Stoßvorgänge, Zeitschrift für Physik 37, 863 (1926) · doi.org
- U. Sinha, C. Couteau, T. Jennewein, R. Laflamme and G. Weihs, Ruling out multi-order interference in quantum mechanics, Science 329, 418 (2010), arXiv preprint · arxiv.org
- HyperPhysics (Georgia State University): Wavefunction properties · hyperphysics.phy-astr.gsu.edu