Unit 3 · The Mathematical MachineryChapter 10 of 25

The Schrödinger Equation

The engine that moves the wavefunction through time

  • 22 min read
  • 32 min listen
  • 23 videos
01Video briefing

Start with the preview

Start here — today's preview. Watch “What is The Schrödinger Equation, Exactly?” from Up and Atom before (or after) this session. The lab will wait. Mostly.

Today's preview

What is The Schrödinger Equation, Exactly?

Up and Atom9 min

A friendly, beginner-level tour in under ten minutes: what the wavefunction is, why atoms have energy levels, and what each piece of the equation means. Watch it first, then let the lesson take each symbol apart.

Watch on YouTube

More from the video vault

Deep dive

What is the i really doing in Schrödinger's equation?

Welch Labs25 min

Retraces how Schrödinger built his equation from de Broglie's matter waves, then uses animated simulations and complex exponentials to show what the i does: it makes the phase of ψ rotate in time. Watch after Part 2 to see the phase spin.

Watch on YouTube
Bonus

Lecture 6: Time Evolution and the Schrödinger Equation

MIT OpenCourseWare82 min

Allan Adams's MIT 8.04 lecture recaps the postulates of quantum mechanics so far, then works through the properties of the Schrödinger equation and how to solve it using energy eigenstates. For students who want the full university treatment.

Watch on YouTube
  • What is The Schrödinger Equation, Exactly? — Up and Atom — https://www.youtube.com/watch?v=QeUMFo8sODk
  • What is the i really doing in Schrödinger's equation? — Welch Labs — https://www.youtube.com/watch?v=uVKMY-WTrVo
  • Lecture 6: Time Evolution and the Schrödinger Equation — MIT OpenCourseWare — https://www.youtube.com/watch?v=TWpyhsPAK14
02Cold open

Today's mission

Dr. Q · cold open

Great Planck's ghost, you came back! Last session we caught the wavefunction in a single frozen frame: a complex amplitude at every point, square its size, and out pop probabilities. But a photograph is not a film. Electrons stream down wires, atoms ring like bells, molecules swing their arms, so something must tell ψ how to change from one instant to the next. Today I wheel out the engine room of quantum mechanics, the equation Erwin Schrödinger wrote down in the winter of 1925 to 1926, and we take it apart bolt by bolt: what every symbol does, why an imaginary number is welded to the front, and why, despite this subject's reputation, the machine itself never rolls a single die. Psigor, stoke the boiler!

By the end of this session you will be able to:

  1. Read the time-dependent Schrödinger equation term by term and say in plain words what each piece does
  2. Explain why the curvature of ψ measures kinetic energy and how the potential V(x) shapes a wavefunction
  3. Derive stationary states by separating variables, arriving at the time-independent equation, and explain why their probability density is frozen even though the particle is not at rest
  4. Use linearity to build superpositions and predict where a free wave packet's centre will be from its group velocity p/m
  5. State the conditions a well-behaved wavefunction must meet and explain how they force quantized energies, as in Schrödinger's 1926 hydrogen solution
03The lesson

Read it — or listen along

7 parts. Press play on any part and the paragraph being read lights up as Dr. Q speaks.

Part 1

From Snapshot to Motion Picture

In the last chapter the wavefunction ψ(x) gave us the full statistical description that quantum mechanics offers of a particle at one instant: square its magnitude and you have a probability density, whose area over any region is the chance of finding the particle there. But a description of one instant is only half of a physical theory. Classical mechanics earns its keep because Newton's second law, F = ma (force equals mass times acceleration), tells you how a state changes: supply a position and a velocity now and it hands you the whole future trajectory. Quantum mechanics needs the same thing for ψ, an equation of motion that turns the wavefunction now into the wavefunction later. That law is the Schrödinger equation, and nearly everything in the rest of this course, from the particle in a box to the qubit, runs on it.

By 1925 the ingredients lay scattered across the bench. Louis de Broglie had proposed in 1924 that every particle carries a wave of wavelength λ = h/p, and Werner Heisenberg, soon joined by Max Born and Pascual Jordan, had just built matrix mechanics, an abstract scheme that predicted spectra without offering any picture. Erwin Schrödinger, a 38-year-old professor at the University of Zurich, wanted the picture. According to Felix Bloch's later recollection, Peter Debye remarked at a Zurich colloquium that if electrons are waves, they ought to obey a wave equation. Over the Christmas holidays of 1925, in the Alpine resort of Arosa, guided by William Rowan Hamilton's analogy between light rays and particle paths, Schrödinger found one, and within weeks he had solved it for hydrogen.

Watch this part

Part 2

Reading the Equation, Term by Term

Here is the equation for one particle of mass m moving along a line, first in words: iħ times the rate at which the wavefunction changes in time equals the Hamiltonian acting on the wavefunction. Three pieces of notation need unpacking. The rate of change is a partial derivative, written with a curly d: the rate at which ψ changes with time while you stand still at one position x, as a weather station records how fast the temperature changes at its own location. The constant ħ is the reduced Planck constant, h divided by 2π, about 1.055×10⁻³⁴ J·s: the exchange rate between angular frequency and energy, E = ħω. And H-hat, a capital H wearing a small hat, is the Hamiltonian operator, named after Hamilton: an operator is a rule that turns one function into another, and this one encodes the particle's total energy.

The Hamiltonian has exactly two parts, mirroring the classical bookkeeping that total energy is kinetic plus potential. The kinetic part takes the second derivative of ψ with respect to position and multiplies it by −ħ²/2m. The potential part multiplies ψ at each point by V(x), the potential energy the particle would have there. Altogether: iħ times the time-rate of change of ψ equals −(ħ²/2m) times its second space-derivative, plus V(x)ψ. Why the imaginary unit i, the square root of −1? Swap the i for a plain minus sign and the equation becomes the diffusion equation that governs heat soaking through a metal bar: ψ would smear out and fade, and total probability would leak away. The i converts that fading into rotation of the phase of ψ in the complex plane, which is why ψ must be complex (Schrödinger himself resisted this at first) and why the total area under |ψ|² stays exactly 1 for all time, a consequence of what physicists call unitarity.

Watch this part

Part 3

Curvature Is Kinetic Energy; the Potential Is the Landscape

The second derivative of a function measures its curvature: how sharply its graph bends at each point. A gently undulating wavefunction has small curvature; one crammed with tight wiggles has large curvature. Because the kinetic term is built from that second derivative, the rule of thumb is wonderfully visual: more bending means more kinetic energy. This is de Broglie's relation in disguise, since many wiggles per metre means a short wavelength, a large momentum p = h/λ, and therefore a large kinetic energy p²/2m. It also explains the uncertainty-principle lesson: squeeze a particle into a small region and its wavefunction is forced to bend sharply, so confinement always costs kinetic energy.

The potential V(x) is the landscape the wave travels across: valleys where a classical ball would settle, hills it must climb, cliffs it bounces off. For a particle of definite energy E, the equation says the curvature of ψ is proportional to (V − E) times ψ. Where the energy exceeds the local potential, the curvature points back toward the axis, so ψ oscillates, with an approximate local wavelength λ = h/√(2m(E − V)) that stretches where the particle is slow and tightens where it is fast. Where V exceeds E, a region forbidden to a classical particle, the curvature points away from the axis and ψ grows or decays exponentially. In a forbidden region that extends forever only the decaying tail is allowed, since a growing one could never be normalized; that tail is the seed of quantum tunnelling, which awaits you in Chapter 12.

Watch this part

Part 4

Stationary States: When the Probability Stands Still

The equation becomes far friendlier when the particle has a definite energy. Guess that ψ(x, t) is a fixed spatial shape φ(x) multiplied by a factor depending only on time, a technique called separation of variables. Substituting the guess shows that the time factor must be a pure phase, a complex number of size 1 circling at angular frequency ω = E/ħ, while the shape must satisfy a simpler rule: the Hamiltonian acting on φ gives back φ multiplied by the energy E. This is the time-independent Schrödinger equation. It is an eigenvalue equation: the operator acting on the special function φ returns the very same function multiplied by a plain number. The function is an eigenfunction (from the German eigen, meaning own or characteristic), the number is its eigenvalue, and here the eigenvalue is the energy.

Now the payoff. The probability density of such a solution is |φ|² times the squared size of the phase factor, and a pure phase always has size 1. So |ψ(x, t)|² = |φ(x)|² at every instant: the probability cloud does not drift, swell or shrink, and every measurable average, such as ⟨x⟩ or the average momentum, is frozen too. These are stationary states, the honest replacement for Bohr's stationary orbits. (Real excited atoms do eventually emit a photon and decay, because they couple to the electromagnetic field, which this single-particle equation leaves out; the ground state is genuinely stable.)

Do not mistake stationary for motionless. Hydrogen's ground state is stationary, yet its electron has an average kinetic energy of 13.6 eV, a typical speed of about 2.2×10⁶ m/s, roughly 0.7 percent of the speed of light; measure the momentum in many identically prepared atoms and you get a broad spread of results. A guitar string sounding a pure note is a good picture: every point vibrates furiously, but the pattern holds its shape. What is stationary is the probability distribution, not the particle. Interpretations differ about what, if anything, the electron is doing between measurements (Chapter 22), but all of them predict that same nonzero spread of momenta.

Watch this part

Part 5

Deterministic, Linear and Dice-Free

Two properties of the equation deserve to be engraved over the laboratory door. The first is determinism. Give it the complete wavefunction at one instant and the potential, and it fixes the wavefunction at every later instant, uniquely, smoothly and continuously, with no randomness anywhere. The randomness of quantum mechanics enters somewhere else: when a measurement is made, the Born rule assigns probabilities to the possible outcomes. How to understand that step physically is the measurement problem, which different interpretations answer differently, as you will see in Chapters 15 and 22. On one point there is no dispute: the Schrödinger equation, as written, rolls no dice.

That puts the phrase quantum jump in perspective. Schrödinger loathed the idea of electrons leaping instantaneously and at random between orbits; Heisenberg later recalled him telling Bohr, in Copenhagen in the autumn of 1926, that if these damned quantum jumps were here to stay he regretted ever getting involved with quantum theory. Under the equation, an atom absorbing light changes state continuously, amplitude flowing smoothly from the lower level to the upper. What looks abrupt and random is the result of a measurement. In 2019 Zlatko Minev, Michel Devoret and colleagues at Yale caught a superconducting artificial atom mid-jump: when a jump starts is random, but once begun it unfolds continuously and coherently, enough to be anticipated and even reversed in flight.

The second property is linearity. Every term contains ψ exactly once, to the first power: no ψ², no square roots of ψ. The consequence is the superposition principle: if ψ₁ and ψ₂ are solutions, so is any combination aψ₁ + bψ₂ with complex constants a and b. Don't panic — superpose! Linearity is why the double-slit amplitudes of Chapter 7 simply add, and it is the master key to the subject: whenever the potential does not change in time, any solution can be assembled from stationary states, each turning its own phase clock, so solving the time-independent equation once solves the time-dependent one for every starting condition.

Superposition is also where motion comes from. Mix two stationary states whose energies differ by ΔE and their phase clocks drift in and out of step, so the probability cloud oscillates at frequency f = ΔE/h. For hydrogen's ground state mixed with its 2p excited state that is 2.47×10¹⁵ hertz, the very frequency of the ultraviolet photon the atom emits when it drops from 2p to the ground state. Bohr had to postulate his frequency rule; Schrödinger's equation produces it as an oscillating cloud of charge.

Watch this part

Part 6

Wave Packets: Group Velocity and Spreading

Now set V = 0 and let a particle fly free. The simplest solution, a plane wave of a single wavelength, has a perfectly definite momentum but is spread uniformly over all of space, so it cannot describe a particle that is here rather than there. A localized particle is a wave packet: a superposition of many plane waves whose wavelengths cluster around a central value, reinforcing one another in one region and cancelling everywhere else, the Fourier trade-off you met in Chapter 8. By linearity, the packet simply evolves as the sum of its ingredients.

Each ingredient wave advances at its own phase velocity, ω/k, which for a free particle is ħk/2m, only half the classical speed. The packet as a whole moves at the group velocity, the speed of the region of constructive interference, given by the derivative dω/dk. For a free particle that is ħk/m = p/m, exactly the classical velocity: the centre glides like a Newtonian particle, a special case of Ehrenfest's theorem (1927), which shows that quantum averages obey classical-looking equations of motion. Phase velocity has no physical meaning in quantum mechanics, since shifting the zero of energy changes it without changing any prediction. In the lab you will see the ripples inside a packet slide backward through its envelope, travelling at half its speed.

Nor does the packet keep its shape. Its ingredients carry a range of momenta, so the fast components pull ahead of the slow ones; this dispersion makes a free packet spread. For a Gaussian packet whose initial width, the standard deviation of |ψ|², is σ₀, the width grows as σ(t) = σ₀·√(1 + (t/τ)²), with a characteristic time τ = 2mσ₀²/ħ. Narrow packets spread fastest, because squeezing σ₀ widens the momentum spread. An electron localized to 0.1 nm, roughly the size of an atom, has a spreading time τ of about 1.7×10⁻¹⁶ seconds and is about 6 nm wide after 10 femtoseconds. A one-gram marble localized to a micrometre has a τ of about 1.9×10¹⁹ seconds, more than forty times the age of the universe, one reason the everyday world looks so reassuringly classical.

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Part 7

Boundary Conditions and the Return of Bohr

Taken alone, the time-independent equation has solutions for any energy you care to try. Physics enters through boundary conditions, the requirements a wavefunction must meet to describe a real particle. A well-behaved wavefunction is single-valued, with one amplitude at each point; finite everywhere; normalizable, meaning the total area under |ψ|² is finite and can be scaled to exactly 1, so a bound particle's ψ must die away far from the well; and continuous, with a continuous slope wherever the potential is finite. At an infinitely high wall, where the particle can never be found, ψ must fall to zero, although its slope may jump.

These modest-sounding demands are what produce quantization. Pick an energy, start a solution as a tiny decaying tail deep in the forbidden region on the left, and integrate across a potential well. For almost every energy the solution emerging on the far side curves away from the axis and races off toward plus or minus infinity, which no real particle can do. Only at special, discrete energies does the tail settle gracefully to zero on both sides; those are the allowed levels. No one has to postulate them, as Bohr did; they fall out of the requirement that ψ behave itself, just as a guitar string pinned at both ends can sound only particular notes.

This is exactly what made Schrödinger famous. In his first 1926 paper he inserted the Coulomb potential energy of an electron and a proton, V(r) = −e²/(4πε₀r), solved the time-independent equation in three dimensions, and demanded well-behaved solutions. Out came Eₙ = −13.6 eV/n², precisely Bohr's levels and therefore the Balmer lines, with more besides: orbitals instead of orbits, a ground state with zero orbital angular momentum where Bohr had insisted on ħ, and a method that extends to molecules and solids. The equation is non-relativistic (Dirac's equation of 1928 refines it), yet for chemistry, materials and most of this course it is the engine. You will dissect hydrogen properly in Chapter 16.

Watch this part

04Video shelf

Go deeper on video

20 more videos for this chapter, 16 of them from universities, research institutes and Nobel lectures. The clips under “Watch this part” in the lesson start at the moment that matters.

20 videos · 9 h 45 min

  • Lecture · CU Boulder

    The Wavefunction turns 100: A look back at Erwin Schrödinger's 1926 quantum revolution

    Physics CU Boulder · Colin West

    A centenary public lecture that assumes no background in maths or physics: Colin West sets Schrödinger's four 1926 papers against their historical backdrop, then unpacks the mathematical and physical innovations they contain. Watch it alongside this section's 'Four papers in six months' callout.

  • Explainer · YouTube

    I finally understood why the universe needs imaginary numbers (My mind is blown!)

    FloatHeadPhysics

    The link starts at 'Where does i come from?' (29:30) and runs through the energy operator to 'Why does it resemble the heat equation (except the i)' (36:47), the same comparison section 2 makes with diffusion. To see the kinetic-energy operator assembled first, rewind to 17:07.

  • Lecture · Yale

    7. Quantum Mechanical Kinetic Energy

    YaleCourses · J. Michael McBride

    McBride splits HΨ = EΨ into a potential part and a kinetic part, and shows that the kinetic part is read from the curvature of ψ, not from ½mv². From 33:24 he plays 'Jeopardy', working back from a guessed ψ to its potential: where ψ curves toward zero the kinetic energy is positive, where it curves away it is negative, which is this section's allowed-versus-forbidden picture.

  • Lecture · MIT

    Stationary states: key equations

    MIT OpenCourseWare · Barton Zwiebach

    Zwiebach defines a stationary state as a product of a function of time and a function of space ('stationary is not the same as static'), shows that expectation values of time-independent observables do not change, and reaches Hψ = Eψ as an eigenfunction equation. He then shows that E must be real or the state could not stay normalized: the rigorous version of section 4.

  • Explainer · YouTube

    The Schrodinger equation made simple | Linearity

    Looking Glass Universe

    Five beginner-friendly minutes on what happens to a quantum state over time, with chapters running from Newtonian mechanics through conservation and time evolution to measurement. Its title names linearity, the property this section calls the master key.

  • Explainer · YouTube

    What Happens During a Quantum Jump?

    PBS Space Time

    Space Time opens with Bohr and Schrödinger and asks whether quantum jumps are real, then turns to experiments that follow single jumps (6:02) and to the quantum Zeno effect (10:19). Watch it after this section's 'damned quantum jumps' story and before Devoret's talk.

  • Lecture · IHP

    Catching and reversing a quantum jump mid-flight

    Institut Henri Poincaré · Michel Devoret

    Michel Devoret, a 2025 physics Nobel laureate, presents the Yale experiment described in this section in a research talk. The link starts at how quantum jumps are observed (4:18), and the payoff is the jump caught mid-flight (34:42) and then reversed (43:20).

  • Demo · YouTube

    Visualization of Quantum Physics (Quantum Mechanics)

    udiprod

    A picture-first, animated demonstration of the simplest case, a free particle, with chapters on the observer effect (4:53), velocity (5:37) and the uncertainty principle (9:06). Watch it before section 6 treats the same free particle with equations.

  • Lecture · MIT

    Time evolution of a free particle wavepacket

    MIT OpenCourseWare · Barton Zwiebach

    Zwiebach's recipe for evolving any free-particle wavefunction: Fourier-transform ψ(x, 0) to φ(k), rewrite it as a superposition of plane waves, then give each its own phase e^(−iω(k)t), which is section 6's 'the packet evolves as the sum of its ingredients' made exact. He ends by setting up a Gaussian at rest whose width starts to change on a time of order ma²/ħ, the τ in this section's spreading formula.

  • Lecture · Yale

    8. One-Dimensional Wave Functions

    YaleCourses · J. Michael McBride

    This section's shooting argument, done on screen: McBride uses the program 'Erwin Meets Goldilocks' to try energies, and ψ races off to infinity for an energy that is 'too hot' or 'too cold' until one is 'just right'. From 31:46 the same rule picks out the allowed energies of the harmonic oscillator, the Morse potential and the Coulomb potential.

  • Lecture · MIT

    Lecture 5: Operators and the Schrödinger Equation

    MIT OpenCourseWare · Allan Adams · 2013

    The lecture from MIT 8.04 Quantum Physics I (Allan Adams, 2013) that goes with Chapter 10. The whole course is in the Lecture Hall.

  • Lecture · MIT

    10. The Time-Dependent Schrödinger Equation

    MIT OpenCourseWare · Robert Field · 2017

    The lecture from MIT 5.61 Physical Chemistry (Robert Field, 2017) that goes with Chapter 10. The whole course is in the Lecture Hall.

  • Lecture · Yale

    24. Quantum Mechanics VI: Time-dependent Schrödinger Equation

    YaleCourses · Ramamurti Shankar · 2010

    The lecture from Yale University PHYS 201 Fundamentals of Physics II (Ramamurti Shankar, 2010) that goes with Chapter 10. The whole course is in the Lecture Hall.

  • Lecture · Oxford

    004 Commutators and Time Evolution (the Time Dependent Schrodinger Equation)

    University of Oxford · James Binney · 2009–10

    The lecture from University of Oxford Quantum Mechanics (James Binney, 2009–10) that goes with Chapter 10. The whole course is in the Lecture Hall.

  • Course · MIT

    Quantum Physics I

    MIT OpenCourseWare · Allan Adams · 2013

    Allan Adams' celebrated course starts from superposition and the experimental facts, builds the wavefunction, operators and the Schrödinger equation, then tours scattering, hydrogen, identical particles and band structure before closing on entanglement and Bell's theorem. Calculus and a little linear algebra are enough to keep up.

  • Course · MIT

    Physical Chemistry

    MIT OpenCourseWare · Robert Field · 2017

    Quantum mechanics as chemists use it, taught by the spectroscopist Robert Field: the photoelectric effect and Compton scattering, boxes and oscillators, hydrogen and many-electron atoms. Strong on spectroscopy, the experimental face of quantization.

  • Course · MIT

    Quantum Physics I

    MIT OpenCourseWare · Barton Zwiebach · 2016

    The same course rebuilt as 115 short segments of roughly ten to twenty minutes, each devoted to one idea, so you can watch exactly the concept a chapter needs. Barton Zwiebach is meticulous: every step on the board is justified.

  • Course · Yale

    Fundamentals of Physics II

    YaleCourses · Ramamurti Shankar · 2010

    Ramamurti Shankar, author of a classic graduate textbook, gives one of the gentlest rigorous introductions anywhere: seven lectures from the double-slit experiment through measurement, the particle in a box, the time-dependent Schrödinger equation and the postulates.

  • Course · Oxford

    Quantum Mechanics

    University of Oxford · James Binney · 2009–10

    James Binney's Oxford course, given over Michaelmas Term 2009 and Hilary Term 2010 and built on probability amplitudes and Dirac notation from the very first lecture. Highlights: tunnelling and radioactive decay, the EPR argument and Bell's inequality, spin and the Stern–Gerlach experiment, and a full treatment of hydrogen.

  • Course · IIT Madras

    Quantum Physics

    nptelhrd · V. Balakrishnan · 2008

    V. Balakrishnan of IIT Madras is one of the most admired physics lecturers anywhere: unhurried, exact and full of physical insight. Thirty-one lectures that build the subject from the uncertainty principle and the failures of classical physics to the full formalism.

Every video for Chapter 10 in the Video Library

05To the blackboard

Key equations

Equation 1

The time-dependent Schrödinger equation

iℏ ∂ψ(x,t)∂t=H^ ψ(x,t)i\hbar\,\frac{\partial \psi(x,t)}{\partial t} = \hat{H}\,\psi(x,t)

Quantum mechanics' equation of motion: the energy operator acting on the wavefunction dictates how fast, and in which direction in the complex plane, ψ changes at every point.

What each symbol means
SymbolMeaningUnit
iimaginary unit, the square root of −1dimensionless
ħreduced Planck constant, h/2π ≈ 1.055×10⁻³⁴J·s
ψ(x,t)wavefunction (probability amplitude) at position x and time t1/√m in one dimension
ttimes
ĤHamiltonian operator: total energy, kinetic plus potentialJ (an energy operator)

Say it: “i h-bar times the partial derivative of psi with respect to time equals H-hat acting on psi”

Equation 2

The Hamiltonian for one particle in one dimension

H^=−ℏ22m ∂2∂x2+V(x)\hat{H} = -\frac{\hbar^{2}}{2m}\,\frac{\partial^{2}}{\partial x^{2}} + V(x)

Total energy as an operator. The first term is kinetic energy, measured by the curvature of ψ; the second multiplies ψ by the potential energy at each point, the landscape the wave moves through.

What each symbol means
SymbolMeaningUnit
mmass of the particlekg
xposition along the linem
∂²/∂x²second derivative with respect to position: curvaturem⁻²
V(x)potential energy at position xJ

Say it: “H-hat equals minus h-bar squared over two m times the second partial derivative with respect to x, plus V of x”

Equation 3

The time-independent Schrödinger equation

−ℏ22m d2φdx2+V(x) φ(x)=E φ(x)⟺H^φ=Eφ-\frac{\hbar^{2}}{2m}\,\frac{d^{2}\varphi}{dx^{2}} + V(x)\,\varphi(x) = E\,\varphi(x) \quad\Longleftrightarrow\quad \hat{H}\varphi = E\varphi

An eigenvalue equation for states of definite energy. Well-behaved solutions exist only for special values of E, and those values are the allowed energy levels.

What each symbol means
SymbolMeaningUnit
φ(x)spatial shape of a stationary state (energy eigenfunction)1/√m
Eenergy eigenvalue: the definite energy of the stateJ (often quoted in eV)

Say it: “minus h-bar squared over two m times the second derivative of phi, plus V times phi, equals E times phi; in short, H-hat phi equals E phi”

Equation 4

A stationary state

ψ(x,t)=φ(x) e−iEt/ℏ⇒∣ψ(x,t)∣2=∣φ(x)∣2\psi(x,t) = \varphi(x)\,e^{-iEt/\hbar} \qquad\Rightarrow\qquad |\psi(x,t)|^{2} = |\varphi(x)|^{2}

A definite-energy state only turns its phase, at angular frequency E/ħ. The phase factor has size 1, so the probability density never changes.

What each symbol means
SymbolMeaningUnit
e^(−iEt/ħ)phase factor rotating around the unit circledimensionless
E/ħangular frequency of the phase rotationrad/s

Say it: “psi of x and t equals phi of x times e to the minus i E t over h-bar; therefore the magnitude of psi squared equals the magnitude of phi squared, at every time”

Equation 5

Group and phase velocity of a free matter wave

vgroup=dωdk=ℏkm=pm,vphase=ωk=ℏk2m=vgroup2v_{\text{group}} = \frac{d\omega}{dk} = \frac{\hbar k}{m} = \frac{p}{m}, \qquad v_{\text{phase}} = \frac{\omega}{k} = \frac{\hbar k}{2m} = \frac{v_{\text{group}}}{2}

The packet's centre travels at the classical speed p/m; the ripples inside it travel at half that speed and have no direct physical meaning.

What each symbol means
SymbolMeaningUnit
kwavenumber, 2π/λrad/m
ωangular frequency, E/ħrad/s
pmomentum, ħkkg·m/s

Say it: “the group velocity equals d omega by d k, which equals h-bar k over m, which is p over m; the phase velocity, omega over k, is half the group velocity”

Equation 6

Spreading of a free Gaussian wave packet

σ(t)=σ01+(tτ)2,τ=2mσ02ℏ\sigma(t) = \sigma_{0}\sqrt{1 + \left(\frac{t}{\tau}\right)^{2}}, \qquad \tau = \frac{2m\sigma_{0}^{2}}{\hbar}

The width barely changes for times much shorter than τ, then grows almost linearly. Light particles in narrow packets spread fastest.

What each symbol means
SymbolMeaningUnit
σ₀initial width (standard deviation of |ψ|²)m
σ(t)width at time tm
τcharacteristic spreading times

Say it: “sigma of t equals sigma naught times the square root of one plus the square of t over tau, where tau equals two m sigma naught squared over h-bar”

06Worked examples

Real numbers, step by step

Cover the steps, try the problem yourself, then reveal the solution one step at a time.

Example 1

Clocking an electron at 10 eV

Problem

An electron wave packet in free space has a central kinetic energy of 10 eV. Find its momentum, de Broglie wavelength, group velocity and phase velocity, then predict how far its centre travels in 1.0 fs.

  1. Step 1: Momentum: p = √(2mE) = √(2 × 9.109×10⁻³¹ kilograms × 10 × 1.602×10⁻¹⁹ joules) = 1.708×10⁻²⁴ kilogram-metres per second.

  2. Step 2: Wavelength: λ = h/p = 6.626×10⁻³⁴ J·s divided by 1.708×10⁻²⁴ kilogram-metres per second = 3.88×10⁻¹⁰ metres, about 0.388 nm.

  3. Step 3: Group velocity: p/m = 1.708×10⁻²⁴ divided by 9.109×10⁻³¹ = 1.876×10⁶ m/s. The phase velocity is half of that, 9.38×10⁵ m/s.

  4. Step 4: Distance travelled by the centre: Δx = 1.876×10⁶ m/s × 1.0×10⁻¹⁵ seconds = 1.88×10⁻⁹ metres, about 1.9 nm.

Answer

p ≈ 1.71×10⁻²⁴ kilogram-metres per second, λ ≈ 0.388 nm, group velocity ≈ 1.88×10⁶ m/s, phase velocity ≈ 9.4×10⁵ m/s; the centre moves about 1.9 nm in 1.0 fs

Why it matters: The centre obeys Newton exactly, as Ehrenfest's theorem promises. The lab's forecast mission asks for the same calculation, in units where ħ = m = 1.

Try it yourself first — then check each step.
Example 2

How fast does a packet spread?

Problem

An electron is localized in a Gaussian packet of width σ₀ = 0.10 nm, about the size of an atom. Find its spreading time τ and its width after 1.0 fs. Then find τ for a 1.0 gram marble localized to σ₀ = 1.0 μm.

  1. Step 1: Electron: τ = 2mσ₀²/ħ = 2 × 9.109×10⁻³¹ × (1.0×10⁻¹⁰)² divided by 1.055×10⁻³⁴ = 1.73×10⁻¹⁶ seconds.

  2. Step 2: After t = 1.0 fs, t/τ = 5.79, so σ = 0.10 nm × √(1 + 5.79²) = 0.10 nm × 5.87 ≈ 0.59 nm. The packet has grown almost sixfold in a millionth of a billionth of a second.

  3. Step 3: Marble: τ = 2 × 1.0×10⁻³ × (1.0×10⁻⁶)² divided by 1.055×10⁻³⁴ = 1.9×10¹⁹ seconds, which is about 6.0×10¹¹ years.

  4. Step 4: The universe is about 1.38×10¹⁰ years old, so the marble's spreading time is roughly 44 times the age of the universe.

Answer

Electron: τ ≈ 1.7×10⁻¹⁶ seconds, width ≈ 0.59 nm after 1.0 fs. Marble: τ ≈ 1.9×10¹⁹ seconds, about 44 ages of the universe

Why it matters: Mass and width enter together as mσ₀²: quantum spreading is dramatic for electrons and utterly negligible for marbles. Note the trade-off too: squeezing a packet tighter makes it spread faster.

Try it yourself first — then check each step.
Example 3

The oscillating hydrogen atom

Problem

A hydrogen atom is prepared in a superposition of its ground state (E₁ = −13.6 eV) and its 2p excited state (E₂ = −3.40 eV). How often does its probability cloud oscillate, and how does that compare with the light the atom emits?

  1. Step 1: Energy difference, using hydrogen's levels to more figures (−13.598 eV and −3.400 eV, which include the small correction for the proton's motion): ΔE = E₂ − E₁ = 10.199 eV, which is 1.634×10⁻¹⁸ joules.

  2. Step 2: Oscillation frequency: f = ΔE/h = 1.634×10⁻¹⁸ joules divided by 6.626×10⁻³⁴ J·s = 2.47×10¹⁵ hertz, and the period, 1/f, is about 0.406 fs.

  3. Step 3: Photon for the same drop: λ = hc/ΔE = 1239.8 eV·nm divided by 10.199 eV ≈ 121.6 nm, the ultraviolet Lyman-alpha line, whose frequency c/λ is the same 2.47×10¹⁵ hertz.

Answer

The cloud oscillates at about 2.47×10¹⁵ hertz (period ≈ 0.41 fs), the same frequency as the Lyman-alpha photon, wavelength 121.6 nm

Why it matters: Bohr simply postulated that emitted light has frequency ΔE/h. In Schrödinger's theory it is the frequency at which the superposed charge cloud oscillates, like a tiny antenna.

Try it yourself first — then check each step.
07Myth busters

What everyone gets wrong

Read the myth, decide whether you believed it, then bust it.

  • Myth #1

    Schrödinger's equation describes random quantum jumps.

    Truth

    The equation is deterministic and continuous: given ψ now, it fixes ψ at every later time with no randomness at all. Chance enters only through measurement and the Born rule. Even transitions between energy levels unfold smoothly as amplitude flows from one state to another, and Schrödinger himself loathed the idea of instantaneous random jumps.

  • Myth #2

    A stationary state means the particle is sitting still.

    Truth

    Only the probability density is frozen. The electron in hydrogen's ground state has an average kinetic energy of 13.6 eV, a typical speed near 2.2×10⁶ m/s, and a broad spread of measured momenta. Think of a guitar string playing a pure note: furious vibration, unchanging pattern.

  • Myth #3

    The ripples of a matter wave move at the particle's speed.

    Truth

    The phase velocity of a free matter wave is only half the particle's speed, and it even changes if you shift the zero of energy, so it is not physical. The packet's centre, which is where you are likely to find the particle, travels at the group velocity p/m.

08Interactive lab

Your turn at the controls

Time to drive the engine yourself. The Wave-Packet Engine solves the time-dependent Schrödinger equation live, in natural units where ħ and m both equal 1, using a time-stepping method that John Crank and Phyllis Nicolson published in 1947 for heat flow. Applied to this equation the method is exactly unitary, so the Norm readout holds at 1.000; it drops only when part of the wave runs off the edge of the stage into an absorbing layer. On screen you see the probability density, the real part of ψ (switch on the imaginary part too), the potential V(x) and a dashed line at the mean energy. Pick one of five landscapes, free space, a hard wall, a step, a harmonic well or a box, then launch a packet and watch every idea from this session move.

Your tasks

0/4

How it connects to the theory

Each frame advances ψ by many small Crank–Nicolson steps of iħ ∂ψ/∂t = Ĥψ. Curvature in Re ψ and Im ψ is kinetic energy; V(x) bends the wave; the steady norm is unitarity, the gift of the i; the centre moving at ħk₀/m is the group velocity, as Ehrenfest's theorem guarantees; the widening is dispersion, following σ₀√(1 + (t/τ)²); and in the harmonic well a frozen |ψ|² beneath an oscillating Re ψ is a stationary state's rotating phase made visible. In the box, a packet started at rest off-centre is mostly a mixture of the two lowest box states, and its slosh is the mad scientist challenge and your preview of Chapter 11.

Wave-Packet Engine: Watch ψ Evolve loads as you scroll down.

Win the challenge to tick “lab won” on your chapter checklist.
Open full-screen lab
09Memory aids

Make it stick

Memory trick

The Engine Rhyme. Recite it with the equation in front of you: 'Bend means kinetic, V is the land; H-hat turns the clock with a steady hand. Add two solutions and the sum still flies; packets cruise at p over m and grow in size. Fix the energy and the cloud stands still, yet the particle moves, and always will.' Line one is the two halves of the Hamiltonian, curvature for kinetic energy and the potential as landscape. Line two is the time-dependent equation, deterministic as clockwork. Line three is linearity, line four is group velocity and spreading, and the last couplet is stationary states plus the myth they kill.

Analogy — and where it breaks

The Schrödinger equation is the physics engine of a video game. Hand it the current frame, ψ everywhere right now, plus the level map, V(x), and it computes every future frame exactly, with no dice rolled; randomness appears only when the player clicks to measure. The analogy breaks in three places. You can never read ψ off the screen in one go, because a measurement returns a single random outcome and disturbs the state. ψ is complex, carrying a phase that no pixel colour could capture. And for several particles ψ lives in a many-dimensional configuration space, not on the flat screen of ordinary space.

The whole chapter in one line

Schrödinger's equation deterministically evolves ψ: curvature is kinetic energy, V is the landscape, and definite-energy states keep |ψ|² frozen.

Leitner flashcards

Flashcards

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10Games

Play it into long-term memory

Match the vocabulary, then take the Quiz Show. Score 70% or better to tick it off your checklist.

Vocab match · timed

Vocab Match

Match each term to its definition, against the clock.

  • 12 pairs in 2 rounds
  • 100 points a match, more on a streak
  • −25 per mistake · speed bonus each round
  • Finish with 3 mistakes or fewer to win
Live from the lab

Dr. Q's Quantum Quiz Show

Dr. Q, your host

Welcome, contestants! 7 questions, 30 seconds each, and one mad scientist judging you, lovingly. Answer fast for a speed bonus; answer right in a row and your points multiply.

  • 100 per answer
  • +100 speed bonus
  • ×2 streak bonus
11Worksheet

Prove it on paper

Answer every question, check your work, and read the explanations — the stretch challenge is for the truly mad.

13 questions12 terms1 challenge

Work through these on paper before checking the answers. Use h = 6.626×10⁻³⁴ J·s, ħ = 1.055×10⁻³⁴ J·s, electron mass mₑ = 9.109×10⁻³¹ kg, 1 eV = 1.602×10⁻¹⁹ J and hc = 1239.8 eV·nm. For calculation questions, show every step and keep three significant figures.

0/13 answered · saved on this device

Part A

Vocabulary

Schrödinger equation
The equation of motion for the wavefunction, iħ ∂ψ/∂t = Ĥψ; it fixes how ψ changes in time.
Hamiltonian
The total-energy operator Ĥ, kinetic plus potential; it drives the time evolution of ψ.
Operator
A rule that turns one function into another, such as 'take the second derivative' or 'multiply by V(x)'.
Partial derivative
The rate of change of a function of several variables with respect to one of them while the others are held fixed.
Curvature
How sharply a graph bends, measured by its second derivative; for ψ it tracks kinetic energy.
Potential energy function
V(x), the energy a particle would have at each position because of the forces on it: the landscape ψ moves through.
Eigenvalue equation
An equation like Ĥφ = Eφ, in which an operator returns the same function multiplied by a number, the eigenvalue.
Stationary state
A definite-energy solution whose probability density and averages do not change in time.
Superposition principle
Because the equation is linear, any weighted sum of solutions is also a solution.
Group velocity
The speed of a wave packet's envelope, dω/dk; for a free particle it equals p/m.
Dispersion
The spreading of a wave packet because its component waves travel at different speeds.
Boundary conditions
Requirements at edges, walls and infinity, such as ψ → 0 or continuity, that select the physically allowed solutions.

Part B

Questions

Auto-checked except short answers, which you mark yourself.

  1. Question 1.Multiple choice

    In iħ ∂ψ/∂t = Ĥψ, what does the Hamiltonian operator Ĥ represent?

  2. Question 2.Multiple choice

    In the same region, wavefunction A has many tight wiggles while wavefunction B is a long, gentle wave. Which statement is correct?

  3. Question 3.True or false

    The time-dependent Schrödinger equation contains a random term that makes ψ jump unpredictably.

  4. Question 4.True or false

    If ψ₁ and ψ₂ both solve the time-dependent Schrödinger equation for the same potential, then 0.6ψ₁ + 0.8iψ₂ is also a solution.

  5. Question 5.Fill in the blank

    A solution of definite energy whose probability density never changes in time is called a state.

  6. Question 6.Fill in the blank

    The centre of a free wave packet moves at the velocity, which equals p/m.

  7. Question 7.Short answer

    Explain why multiplying a spatial shape φ(x) by the phase factor e^(−iEt/ħ) leaves the probability density unchanged in time.

  8. Question 8.Short answer

    Why does requiring ψ to be normalizable lead to discrete energy levels for a particle bound in a well?

  9. Question 9.Short answer

    Hydrogen's ground state is a stationary state. Give two reasons it is nevertheless wrong to say the electron is sitting still.

  10. Question 10.Calculation

    An electron wave packet has a central de Broglie wavelength of 0.50 nm and moves in free space. How far does its centre move in 2.0 fs?

    Give a number and units. 6.63×10⁻³⁴, 6.63e-34 and 6.63 x 10^-34 all work.

  11. Question 11.Calculation

    A free electron plane wave has wavenumber k = 1.0×10¹⁰ m⁻¹. Use the Schrödinger equation's result E = ħ²k²/2m to find its energy in eV and its group velocity.

    This one asks for more than one value — give each, with its units.

  12. Question 12.Calculation

    A hydrogen atom is placed in a superposition of its n = 2 and n = 3 levels (E₂ = −3.40 eV, E₃ = −1.51 eV). At what frequency does its probability cloud oscillate? Compare with the Balmer line from n = 3 to n = 2.

    This one asks for more than one value — give each, with its units.

  13. Question 13.Calculation

    An electron is localized in a Gaussian packet of width σ₀ = 1.0 nm. Find the spreading time τ = 2mσ₀²/ħ and the packet's width after 1.0 ps.

    This one asks for more than one value — give each, with its units.

Part C · optional, dangerous, extremely rewarding

Mad scientist challenge

The sloshing electron. An electron is trapped in a box 1.0 nm wide whose two lowest stationary states have real spatial shapes φ₁(x) and φ₂(x) and energies E₁ = 0.376 eV and E₂ = 1.504 eV (you will derive these in Chapter 11). At t = 0 it is prepared in ψ = (φ₁ + φ₂)/√2. (a) Write ψ(x, t). (b) Show that |ψ|² = ½φ₁² + ½φ₂² + φ₁φ₂ cos(ΔE·t/ħ), where ΔE = E₂ − E₁. (c) Is this a stationary state? Describe what the probability does, given that φ₁ is symmetric about the box's centre and φ₂ is antisymmetric. (d) Find the period of the motion. (e) What photon wavelength carries the same energy difference?

12Wrap-up

Recap & sign-off

Key takeaways

  • The time-dependent Schrödinger equation is quantum mechanics' equation of motion: iħ times the rate of change of ψ equals the Hamiltonian acting on ψ
  • The Hamiltonian is kinetic plus potential energy: the curvature of ψ measures kinetic energy, and V(x) sets the landscape
  • The imaginary unit turns decay into phase rotation, so total probability is conserved
  • Definite-energy solutions solve the time-independent equation; their phase turns at E/ħ, so |ψ|² is frozen, but the particle is not at rest
  • The equation is deterministic and linear: it rolls no dice, any superposition of solutions is a solution, and mixing energies makes |ψ|² oscillate at ΔE/h
  • Free wave packets travel at the group velocity p/m and spread on a timescale τ = 2mσ₀²/ħ
  • Boundary conditions on well-behaved wavefunctions allow only special energies, which is how Schrödinger's 1926 paper reproduced Bohr's hydrogen levels
Dr. Q signs off

Engine room secured! You now command the equation that turns the crank on ψ: deterministic as clockwork, linear as a ledger, with curvature for kinetic energy and V for the terrain. Next session we bolt it into the simplest cage imaginable, two perfectly rigid walls, and watch quantization appear all by itself. Sine-wave shapes, an energy ladder that climbs as n squared, and a lowest energy that is never zero: the particle in a box awaits. Bring a ruler. Psigor, bank the boiler!

Your chapter checklist

Tick these off in any order. It's a guide, not a law of physics — you can mark the chapter complete whenever you're ready.

  • Listen to the whole lesson (not yet)Or read it all — but the voice is more fun.
  • Win the lab challenge (not yet)Wave-Packet Engine: Watch ψ EvolveGo to the lab
  • Score 70% or more on the Quiz Show (not yet)Six to eight questions, no penalties for guessing.Take the quiz
  • Check your worksheet (not yet)Answer, check, and read the explanations.Open the worksheet