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Start here — today's preview. Watch “Atomic spectra | Physics | Khan Academy” from Khan Academy before (or after) this session. The lab will wait. Mostly.
Atomic spectra | Physics | Khan Academy
A clear, chaptered tour of almost everything this session covers: discrete energy levels, the Bohr model and its energy-level diagram, excitation and de-excitation, hydrogen's spectrum, and how absorption lines identify the elements in distant stars. Its short look at orbital shapes previews chapter 16. Watch the energy-level diagram from about 5:37 and keep it in mind for the lab.
Watch on YouTubeMore from the video vault
What is the Bohr model of the atom?
A patient blackboard walk from Thomson's plum pudding and Rutherford's alpha scattering, through the instability of the nuclear atom, to Bohr's postulates, the quantization of angular momentum, the size of the atom, the energy levels and the visible hydrogen spectrum. Watch it after Part 5 and follow the algebra that turns L = nħ into Eₙ = −13.6 eV/n².
Watch on YouTubeHow Do We Know What Stars Are Made Of?
Matt O'Dowd tells how Cecilia Payne decoded stellar spectra in the 1920s and found that stars are made mostly of hydrogen and helium, against the expectations of the leading astronomers of her day. The perfect companion to Part 2.
Watch on YouTube- Atomic spectra | Physics | Khan Academy — Khan Academy — https://www.youtube.com/watch?v=N0lBsW3ZzN8
- What is the Bohr model of the atom? — Physics Explained — https://www.youtube.com/watch?v=_Gt7mo8SNkA
- How Do We Know What Stars Are Made Of? — PBS Space Time — https://www.youtube.com/watch?v=hp2Ek1cA1LE
Today's mission
Dr. Q · cold openLights off, goggles on, and welcome back to the lab. On my bench hums a slim glass tube of hydrogen gas with a few thousand volts across it, glowing an eerie pinkish violet. Pretty. Now look at it through this diffraction grating, a slide ruled with thousands of fine grooves that spreads light out by wavelength. No rainbow appears. Instead: one crisp red line, one blue-green, one blue-violet, one faint violet, and darkness everywhere between. A barcode! In 1835 the philosopher Auguste Comte declared that we would never learn what the stars are made of. Within twenty-five years, barcodes like this one had proved him spectacularly wrong. Today we ask why atoms sing only these notes, and a 27-year-old Dane gives an answer so strange that it worked. Great Planck's ghost, let's begin.
By the end of this session you will be able to:
- Explain how emission and absorption line spectra act as fingerprints of the elements, and how astronomers use them to learn what stars are made of
- Describe Rutherford's 1911 nuclear atom and explain why classical physics predicts that it should collapse within about 10⁻¹¹ seconds while radiating a continuous smear of light
- State Bohr's three postulates of 1913 and use them to obtain hydrogen's energy levels, Eₙ = −13.6 eV/n², and orbit radii that grow as n squared
- Calculate the wavelength of the photon emitted or absorbed in any hydrogen transition, using energy differences or the Rydberg formula, and sort the lines into the Lyman, Balmer and Paschen series
- Distinguish the ground state, excited states and ionization, and explain why a quantum leap is the smallest possible change rather than a giant one
- Evaluate what Bohr's model gets right and where it fails, including atoms with more than one electron and the fact that its orbits are not real paths
Read it — or listen along
8 parts. Press play on any part and the paragraph being read lights up as Dr. Q speaks.
Barcodes Written in Light
Pass light through a prism, or through a diffraction grating ruled with thousands of fine grooves, and its wavelengths fan out into a spectrum. A hot, dense object, such as a lamp filament or the surface of the Sun, gives a continuous spectrum, the smooth blackbody rainbow of chapter 3. A hot, thin gas gives an emission spectrum, also called a line spectrum: a few bright lines at sharply defined wavelengths, with darkness between them. Each element has its own pattern. Sodium glows with a pair of yellow lines at 589.0 and 589.6 nm, the colour of old sodium street lamps, and lithium turns a flame crimson. Measuring such patterns is spectroscopy, and it let chemists name the elements in a sample with a flame and a prism.
The pattern also works in reverse. In 1814 the Bavarian lens maker Joseph von Fraunhofer mapped more than 500 fine dark lines crossing the Sun's spectrum. In 1859 Gustav Kirchhoff and Robert Bunsen at Heidelberg found their origin: when sunlight passed through a sodium flame, the dark D lines grew darker still. A cool gas in front of a hotter source absorbs precisely the wavelengths it emits when hot. The result is an absorption spectrum, dark lines on a bright continuous background at the same wavelengths as the element's emission lines, so emission and absorption are two readings of one fingerprint. With it the pair soon discovered two new metals, cesium and rubidium, named from the Latin for the sky-blue and deep-red colours of their lines.
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Reading the Stars
Comte had written in 1835 that although we might learn the shapes, distances and motions of the stars, we could never study their chemical composition. Barely twenty-five years later Kirchhoff matched the Sun's dark lines, one by one, to laboratory spectra of sodium, iron, magnesium, calcium and more, showing that the cooler solar atmosphere contains them. Fraunhofer's C and F lines turned out to be hydrogen's. Today astronomers read the composition of stars, nebulae, distant galaxies and even the atmospheres of planets orbiting other stars. Shifted lines reveal motion too, through the Doppler effect.
A barcode is not a recipe, though, because the strength of a line depends on temperature as well as on abundance. In 1925 Cecilia Payne, a doctoral student at Harvard College Observatory, combined measured line strengths with Meghnad Saha's 1920 theory of how hot gases ionize, and concluded that stars are made overwhelmingly of hydrogen and helium. The astronomer Henry Norris Russell told her the result was clearly impossible, and she hedged it in print; four years later Russell reached the same conclusion by another route. The Sun is roughly three-quarters hydrogen and one-quarter helium by mass. Why temperature matters so much, Bohr's atom will explain in Part 6.
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Rutherford's Nucleus and an Atom That Should Not Exist
By 1909 physicists knew that atoms contain lightweight, negatively charged electrons, discovered by J. J. Thomson in 1897, but not how the balancing positive charge is arranged; Thomson guessed it was spread through the atom like a pudding. That year Hans Geiger and Ernest Marsden, in Ernest Rutherford's laboratory in Manchester, fired alpha particles, the fast helium nuclei shot out by radioactive atoms, at thin metal foils. Most sailed straight through, but about one in 8,000 striking a platinum foil bounced back by more than 90°. Rutherford later compared it to firing a 15-inch shell at a piece of tissue paper and having it come back and hit you.
In 1911 Rutherford explained why. All of an atom's positive charge and nearly all its mass sit in a nucleus between 10⁻¹⁵ and 10⁻¹⁴ metres across, tens of thousands of times smaller than the atom itself: a pea on the centre spot of a stadium. The natural guess was a miniature solar system, with electrons circling the nucleus like planets round the Sun, held by electric attraction instead of gravity.
Classical physics condemned that picture at once. A charge moving in a circle is accelerating, and Maxwell's electromagnetism says that accelerating charges radiate electromagnetic waves, which carry energy away. An orbiting electron would spiral inward and strike the nucleus in about 1.6×10⁻¹¹ seconds, and as its orbit shrank its circling frequency would rise smoothly, broadcasting a continuous smear of light, never a crisp line. Classical theory cannot even set an atom's size, because the electron's charge and mass and the strength of the electric force cannot be combined into a length. Yet every hydrogen atom is stable, identical and about a tenth of a nanometre across, and it shines only in sharp lines.
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Balmer's Riddle and Bohr's Three Rules
The clue had been waiting since 1885, when Johann Balmer, a mathematics teacher at a girls' school in Basel, found that hydrogen's four visible lines, at about 656, 486, 434 and 410 nm, obey a simple formula: λ = B·n²/(n² − 4), where B is 364.56 nm and n is 3, 4, 5 or 6. The formula predicted a fifth line near 397 nm, which, a colleague told him, had already been observed, along with further lines photographed in the spectra of white stars. Around 1890 the Swedish physicist Johannes Rydberg recast such patterns in the form used today, 1/λ = R × (1/n₁² − 1/n₂²), where n₁ and n₂ are whole numbers and R is the Rydberg constant. It worked superbly, and nobody knew why whole numbers should rule the light of an atom.
Niels Bohr, a young Danish theorist, spent four months of 1912 in Rutherford's laboratory and left convinced of two things: the nucleus was real, and classical physics could not govern the electrons around it. Early in 1913 a Copenhagen colleague, Hans Marius Hansen, asked how his ideas would account for spectral lines. 'As soon as I saw Balmer's formula,' Bohr later recalled, 'the whole thing was immediately clear to me.' His paper, published in July 1913 when he was 27, rests on three bold rules.
First, stationary states: the electron can occupy only certain allowed orbits, and while it stays in one it does not radiate, whatever Maxwell says, so each state has a fixed energy. Second, quantization: in the form textbooks keep, which Bohr also stated, the electron's angular momentum, its mass times its speed times its orbital radius, must be a whole-number multiple of the reduced Planck constant ħ = h/2π: L = m·v·r = nħ, with n = 1, 2, 3 and so on. Third, quantum jumps: light is emitted or absorbed only when the electron jumps between stationary states, with a frequency f fixed by the rule that h·f equals the difference between the two states' energies. Bohr himself distrusted Einstein's light quanta until the mid-1920s, but in today's language each jump emits or absorbs a single photon: chapter 4's photon wired into the atom. The rule cuts the classical link between the frequency of the light and the motion of the electron.
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Climbing Hydrogen's Ladder
Now turn the rules loose on hydrogen, one electron bound to one proton. Two conditions hold at once: the proton's electric pull must supply exactly the inward force that keeps the electron on its circle, and the angular momentum must equal nħ. Together they give radii that grow as the square of n: rₙ = n²a₀, where a₀, the Bohr radius, is built from ħ, the electron's mass and charge and the electric constant ε₀, and equals 0.0529 nm. Planck's constant has supplied the missing length, and it is the right one. The next orbits have radii of 0.212 and 0.476 nm, and in the lowest the electron moves at 2.19×10⁶ metres per second, about the speed of light divided by 137.
Adding the kinetic energy to the electric potential energy gives each state's energy: Eₙ = −13.6 eV/n². The ladder reads −13.6 eV for n = 1, then −3.40, −1.51, −0.85, −0.54 and −0.38 eV, its rungs crowding together toward zero. The lowest rung is the ground state, where an undisturbed atom stays indefinitely. Higher rungs are excited states, reached by excitation: absorbing a photon of exactly the right energy, or a hard enough collision. Excited states are fleeting, typically lasting billionths of a second before the electron drops and a photon departs. Give a ground-state atom 13.6 eV or more and the electron escapes altogether. That is ionization, and 13.6 eV is hydrogen's ionization energy; above zero, a free electron may have any energy at all.
In 1914 James Franck and Gustav Hertz caught such rungs in the act: electrons fired through mercury vapour lost energy only in chunks of about 4.9 eV, mercury's first excitation energy, and the vapour then emitted ultraviolet light at 253.7 nm, whose photons carry just that energy. They at first mistook the 4.9 eV for mercury's ionization energy, but the discovery earned them the 1925 Nobel Prize in Physics.
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Decoding the Barcode: Lyman, Balmer, Paschen
Bohr's third rule turns the ladder into a spectrum. When the electron drops from an upper rung n₂ to a lower rung n₁, the photon carries off 13.6 eV × (1/n₁² − 1/n₂²). A photon's energy is h·c/λ, so dividing by h·c gives Rydberg's formula and explains his constant: R = 13.6 eV ÷ (h·c) ≈ 1.097×10⁷ per metre. Bohr built R from nothing but the electron's mass and charge and Planck's constant, joined in today's SI form by ε₀ and the speed of light. In 1913, in the frequency form then used, his value came out at 3.1×10¹⁵ per second against a measured 3.290×10¹⁵, agreement within the uncertainties of the day.
Group the lines by the rung they land on and the barcode sorts itself into series. Drops to n = 1 make the Lyman series, all ultraviolet, from 121.6 nm down to a series limit at 91.2 nm. Drops to n = 2 make the Balmer series, the only one reaching the visible: 656 nm red from n = 3, 486 nm blue-green from n = 4, 434 nm blue-violet from n = 5 and 410 nm violet from n = 6, with more lines crowding toward a limit at 365 nm in the ultraviolet. Drops to n = 3 make the infrared Paschen series, found by Friedrich Paschen in 1908, from 1,876 nm down to 820 nm.
Absorption is the same rule run backwards, and it settles the puzzle from Part 2. An atom absorbs a photon only if its energy exactly matches a gap from the atom's present rung to a higher one, or is at least the energy needed to ionize it. In cool atomic hydrogen, such as the thin gas between the stars, essentially every atom is in the ground state, so the gas absorbs only ultraviolet Lyman lines and is transparent to visible light. Balmer absorption needs atoms already in n = 2, which requires a gas at thousands of degrees. That is why Balmer lines are strongest in stars with surfaces near 10,000 K: cooler stars hold too few atoms in n = 2, and hotter ones have ionized most of their hydrogen.
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The Smallest Leap in the Universe
In everyday speech a quantum leap is a giant advance, which gets the physics backwards. A quantum leap is the smallest change an atom can make: a jump between allowed states, with no allowed states in between. The electron that makes hydrogen's red line drops from a Bohr orbit of 0.476 nm to one of 0.212 nm, less than a third of a nanometre, releasing 1.89 eV, about 3.0×10⁻¹⁹ joules. Lifting a one-gram paperclip by one millimetre would take some thirty trillion such leaps. What makes the leap remarkable is discreteness, not size: measure the energy of hydrogen's electron and you find −3.40 eV or −1.51 eV, never anything in between.
Bohr's rules say only what goes into a jump and what comes out, not how or when it happens. Rutherford spotted the gap at once, asking Bohr in March 1913 how an electron decides what frequency to emit, as if it knew beforehand where it would stop. In quantum mechanics, which jump an excited atom makes, and when, is a matter of probability, and chapter 10 shows that the change itself unfolds smoothly.
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What Bohr Got Right, and Where the Orbits Dissolve
The successes were stunning. Bohr's model gave hydrogen's size, its ionization energy, every line of every series, and the Rydberg constant from fundamental constants. It even explained why laboratory tubes showed about a dozen Balmer lines while some stars showed 33: high orbits are so swollen that in a laboratory gas they would overlap neighbouring atoms, whereas thin stellar atmospheres leave room for them. The model fits any ion with a single electron, with the nuclear charge Z multiplying every energy by Z². So Bohr identified a puzzling series that Edward Pickering had reported in the star ζ Puppis in 1896 as the light of helium with one electron removed. When Alfred Fowler objected that the wavelengths were off by a hair, Bohr let the nucleus move too, both bodies circling their common centre of mass, and the agreement became nearly perfect. Einstein reportedly called it an enormous achievement.
The failures were just as instructive. The model could not handle helium, with only two electrons, let alone heavier atoms. Arnold Sommerfeld's refinements of 1916, with elliptical orbits and relativity, could not fix that, nor predict how bright each line should be. Bohr also gave hydrogen's ground state one unit of angular momentum, ħ, where quantum mechanics gives zero. Deepest of all, the orbits are not real paths: as chapter 8 will show, the uncertainty principle forbids an electron a sharply defined position and momentum at the same time. In 1925 and 1926 the quantum mechanics of Heisenberg, Schrödinger and Born replaced orbits with orbitals, clouds of probability, and recovered Bohr's energies without his improvised rules. Bohr, who won the 1922 Nobel Prize in Physics for this work, had built a brilliant bridge: the right energies for hydrogen, the wrong picture of the atom.
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Go deeper on video
15 more videos for this chapter, 11 of them from universities, research institutes and Nobel lectures. The clips under “Watch this part” in the lesson start at the moment that matters.
Key equations
Bohr's quantization rule
Of all the circular orbits classical mechanics allows, Bohr kept only those whose angular momentum is a whole-number multiple of h-bar. The whole number n labels the allowed states and is now called the principal quantum number.
| Symbol | Meaning | Unit |
|---|---|---|
| L | orbital angular momentum of the electron | J·s |
| m | electron mass, 9.109×10⁻³¹ | kg |
| v | speed of the electron in its orbit | m/s |
| r | radius of the orbit | m |
| n | principal quantum number: 1, 2, 3, … | dimensionless |
| ħ | reduced Planck constant h/2π, 1.055×10⁻³⁴ | J·s |
Say it: “L equals m v r, which equals n times h-bar, where n is 1, 2, 3 and so on”
Bohr orbit radii
Balancing the electric attraction against the quantization rule fixes the size of each allowed orbit. The radii grow as the square of n, so the fourth orbit is sixteen times wider than the first, and Planck's constant sets the scale of every atom.
| Symbol | Meaning | Unit |
|---|---|---|
| rₙ | radius of the nth Bohr orbit | m |
| a₀ | Bohr radius, 5.29×10⁻¹¹ | m |
| ε₀ | electric constant (vacuum permittivity), 8.854×10⁻¹² | F/m |
| e | elementary charge, 1.602×10⁻¹⁹ | C |
Say it: “r n equals n squared times a naught, where a naught, the Bohr radius, equals 4 pi epsilon naught h-bar squared over m e squared, about 0.0529 nanometres”
Hydrogen energy levels
The total energy of the electron in the nth stationary state. It is negative because the electron is bound; zero means free and at rest far away. The levels crowd together toward zero as n grows, and 13.6 electron-volts is the energy needed to ionize hydrogen from its ground state.
| Symbol | Meaning | Unit |
|---|---|---|
| Eₙ | energy of level n: −13.6, −3.40, −1.51, −0.85, … | eV |
| 13.6 eV | hydrogen's ionization energy, 2.18×10⁻¹⁸ | J |
| n | principal quantum number | dimensionless |
Say it: “E n equals minus 13.6 electron-volts divided by n squared”
Photon energy on a quantum jump
Bohr's third postulate. An atom emits or absorbs light only in jumps between stationary states, one photon per jump, and the photon carries exactly the energy difference. With energies in electron-volts, the wavelength in nanometres is about 1240 divided by that difference.
| Symbol | Meaning | Unit |
|---|---|---|
| f | frequency of the emitted or absorbed light | Hz |
| λ | wavelength of the light | m |
| E_upper, E_lower | energies of the two stationary states | J (or eV) |
| hc | Planck's constant times the speed of light, 1239.84 | eV·nm |
Say it: “h f, which equals h c over lambda, equals the upper energy minus the lower energy”
The Rydberg formula
The wavelength of every hydrogen line. The lower level n 1 names the series: 1 for Lyman in the ultraviolet, 2 for Balmer in the visible, 3 for Paschen in the infrared. As n 2 grows without limit, the lines crowd toward the series limit.
| Symbol | Meaning | Unit |
|---|---|---|
| λ | wavelength of the spectral line | m |
| R | Rydberg constant, about 1.097×10⁷ | m⁻¹ |
| n₁ | lower level, where the electron lands | dimensionless |
| n₂ | upper level, where the electron starts | dimensionless |
Say it: “1 over lambda equals R times the quantity 1 over n 1 squared minus 1 over n 2 squared, with n 2 greater than n 1”
The Rydberg constant from first principles
Bohr's triumph: a number measured by spectroscopists since the 1880s, rebuilt from the electron's mass and charge, Planck's constant, the electric constant and the speed of light. The small subscript infinity marks the idealization of an infinitely heavy nucleus; for real hydrogen, whose proton recoils slightly, the value is smaller by about one part in 1837.
| Symbol | Meaning | Unit |
|---|---|---|
| R∞ | Rydberg constant for an infinitely heavy nucleus, 1.0973731568×10⁷ | m⁻¹ |
| h | Planck constant, 6.62607015×10⁻³⁴ (exact) | J·s |
| c | speed of light in vacuum, 299,792,458 (exact) | m/s |
Say it: “R infinity equals m e to the fourth over 8 epsilon naught squared h cubed c, which equals 13.6 electron-volts divided by h c, about 1.097 times ten to the seventh per metre”
Real numbers, step by step
Cover the steps, try the problem yourself, then reveal the solution one step at a time.
Hydrogen's red line, two ways
An electron in a hydrogen atom drops from n = 3 to n = 2. Find the photon's energy, wavelength and frequency, first from the energy levels and then from the Rydberg formula.
Step 1: Energy levels: E₃ = −13.6 eV ÷ 9 = −1.51 eV, and E₂ = −13.6 eV ÷ 4 = −3.40 eV.
Step 2: The photon carries the difference: ΔE = −1.51 eV − (−3.40 eV) = 1.89 eV.
Step 3: Wavelength from the 1240 rule of chapter 4: λ = 1240 ÷ 1.89 ≈ 656 nm, which is red light.
Step 4: Rydberg check: 1/λ = (1.097×10⁷ per metre) × (1/4 − 1/9) = (1.097×10⁷) × 0.1389 = 1.524×10⁶ per metre, so λ = 6.563×10⁻⁷ metres, or 656 nm.
Step 5: Frequency: f = c ÷ λ = (2.998×10⁸ m/s) ÷ (6.563×10⁻⁷ metres) = 4.57×10¹⁴ hertz.
ΔE ≈ 1.89 eV, λ ≈ 656 nm (red) and f ≈ 4.57×10¹⁴ hertz: the first Balmer line, called hydrogen-alpha
Why it matters: The two routes agree because the Rydberg formula is nothing but the energy difference divided by h·c. NIST's measured value is 656.28 nm in air, or 656.46 nm in vacuum; the remaining few tenths of a nanometre come mainly from the recoil of the proton, a correction the worksheet challenge explores.
Exact keys only: absorption from the ground state
Hydrogen atoms in the ground state are bathed in ultraviolet photons of four energies: 10.2 eV, 11.0 eV, 12.09 eV and 15.0 eV. Which photons are absorbed, and what happens to the atoms?
Step 1: The atom starts at −13.6 eV. A photon can be absorbed only if the atom's new energy lands exactly on an allowed level, or above zero.
Step 2: 10.2 eV: −13.6 + 10.2 = −3.40 eV, exactly level n = 2. Absorbed, exciting the atom to n = 2. Its wavelength is 1240 ÷ 10.2 ≈ 121.6 nm, the first Lyman line.
Step 3: 11.0 eV: −13.6 + 11.0 = −2.60 eV, which falls between n = 2 at −3.40 eV and n = 3 at −1.51 eV. There is no level there, so the photon passes straight through.
Step 4: 12.09 eV: −13.6 + 12.09 = −1.51 eV, exactly level n = 3. Absorbed, at 1240 ÷ 12.09 ≈ 102.6 nm.
Step 5: 15.0 eV: more than the ionization energy of 13.6 eV, so the electron is torn free and leaves with the remaining 15.0 − 13.6 = 1.4 eV as kinetic energy.
Photons of 10.2 eV and 12.09 eV are absorbed, raising atoms to n = 2 and n = 3; the photon of 11.0 eV passes through untouched; the photon of 15.0 eV ionizes the atom, freeing an electron with 1.4 eV of kinetic energy
Why it matters: Absorption between bound states is a lock that accepts only exact keys. Above the ionization energy the lock vanishes, because a free electron can carry away any amount of energy, just as in the photoelectric effect: pay the toll, keep the change.
Counting the lines from n = 4
A sample of hydrogen is excited so that many of its atoms are in level n = 4. List every line the sample can emit as the atoms cascade down, with photon energy and wavelength, and say which lines are visible.
Step 1: Levels: E₄ = −0.85 eV, E₃ = −1.51 eV, E₂ = −3.40 eV and E₁ = −13.6 eV. Any downward pair is possible, so there are 4 × 3 ÷ 2 = 6 lines.
Step 2: Landing on n = 3: from 4 to 3 the photon carries 0.661 eV, and 1240 ÷ 0.661 ≈ 1,876 nm, infrared, the first Paschen line.
Step 3: Landing on n = 2: from 4 to 2, 2.55 eV and 486 nm, blue-green; from 3 to 2, 1.89 eV and 656 nm, red. Both are Balmer lines, and both are visible.
Step 4: Landing on n = 1: from 4 to 1, 12.75 eV and 97.3 nm; from 3 to 1, 12.09 eV and 102.6 nm; from 2 to 1, 10.2 eV and 121.6 nm. All three are ultraviolet Lyman lines.
Step 5: Each atom takes only one route. The longest, 4 to 3 to 2 to 1, emits three photons whose energies, 0.661 + 1.89 + 10.2 eV, add up to the 12.75 eV of the direct jump.
Six lines: 1,876 nm in the infrared; 656 nm and 486 nm in the visible; and 121.6, 102.6 and 97.3 nm in the ultraviolet. Only two are visible
Why it matters: A glowing gas shows every line at once because it holds billions of atoms, each taking its own random route down the ladder. In general, n levels allow n × (n − 1)/2 different lines, which is why spectra look so rich.
Inside Bohr's ground state
Using L = m·v·r = nħ with n = 1 and the Bohr radius a₀ = 5.29×10⁻¹¹ metres, find the electron's speed, its kinetic energy and how many times per second it circles in Bohr's model. Then compare the circling frequencies in levels n = 3 and n = 2 with the frequency of the red light from Example 1, which comes from a jump between those two levels.
Step 1: Speed: v = ħ ÷ (m·a₀) = (1.055×10⁻³⁴ J·s) ÷ (9.109×10⁻³¹ kilograms × 5.29×10⁻¹¹ metres) = 2.19×10⁶ m/s, about the speed of light divided by 137.
Step 2: Kinetic energy: one-half times m times v² = 0.5 × (9.109×10⁻³¹ kilograms) × (2.19×10⁶ m/s)² = 2.18×10⁻¹⁸ joules, which is 13.6 eV.
Step 3: The electric potential energy is twice as large and negative, −27.2 eV, so the total is 13.6 − 27.2 = −13.6 eV, the ground-state energy.
Step 4: Orbital frequency: v ÷ (2π·a₀) = (2.19×10⁶ m/s) ÷ (2π × 5.29×10⁻¹¹ metres) = 6.6×10¹⁵ revolutions per second.
Step 5: Since v falls as 1/n and r grows as n², the circling frequency falls as 1/n³: about 6.6×10¹⁵ ÷ 27 ≈ 2.4×10¹⁴ per second in n = 3 and 6.6×10¹⁵ ÷ 8 ≈ 8.2×10¹⁴ per second in n = 2. The red light, at 4.57×10¹⁴ hertz, matches neither.
v ≈ 2.19×10⁶ m/s, kinetic energy ≈ 13.6 eV and an orbital frequency of about 6.6×10¹⁵ per second in the ground state; the red light's 4.57×10¹⁴ hertz matches neither the n = 3 orbital frequency, about 2.4×10¹⁴ per second, nor the n = 2 one, about 8.2×10¹⁴ per second
Why it matters: In classical physics a circling charge radiates at its circling frequency. In Bohr's atom the frequency of the light is set by an energy difference instead, through h·f = ΔE. That single break with classical physics is the heart of the model. Only for jumps between neighbouring levels at very large n do the two frequencies converge, an agreement Bohr turned into his correspondence principle, met again in chapter 11.
What everyone gets wrong
Read the myth, decide whether you believed it, then bust it.
- Myth #1
Electrons orbit the nucleus like planets orbit the Sun.
TruthA planet can circle at any distance with any energy, and it does not radiate its energy away. An electron in an atom can have only certain discrete energies, and a charged electron truly circling the nucleus would radiate and spiral inward within about 10⁻¹¹ seconds. Bohr's circular orbits were a stepping stone that gave correct energies for hydrogen, but quantum mechanics replaces them with orbitals, clouds of probability with no trajectory. In hydrogen's ground state the electron has no orbital angular momentum at all.
- Myth #2
A quantum leap is a big leap.
TruthIt is the smallest possible change in an atom's state: a jump between allowed energies with nothing in between. The jump that makes hydrogen's red line releases 1.89 eV, about 3×10⁻¹⁹ joules, across less than a third of a nanometre. What makes it quantum is discreteness, not size; the everyday meaning of a giant breakthrough gets the physics backwards.
- Myth #3
Dark absorption lines are wavelengths that atoms simply delete from the light.
TruthThe atoms do absorb those photons, but an excited atom soon gives the energy back, re-emitting the same wavelength or a cascade of smaller photons in random directions, or passing it to neighbours in collisions. Much of the light is scattered out of the beam rather than destroyed, so the lines look dark against the brilliant background behind them without being perfectly black. Look at the same gas from the side, against a dark sky, and you see bright emission lines at the same wavelengths.
- Myth #4
Bohr's model was wrong, so it is useless.
TruthFor hydrogen and other one-electron ions, its energy levels are correct, and the Bohr radius, the Rydberg constant and the series formulas are used every day in physics, chemistry and astronomy. What it gets wrong is the picture, definite circular paths, and every atom with more than one electron. It is scaffolding that was taken down once quantum mechanics was built, not a mistake to forget.
Your turn at the controls
Welcome to the Quantum Leap Lab. On screen is hydrogen's energy ladder: levels n = 1 to 6 on a true linear scale from −13.60 eV up to −0.38 eV, a column of evenly spaced floor buttons so every level is easy to tap, and an ∞ button at 0 eV, the ionization limit. Beside it sits Bohr's 1913 picture of the atom, labelled as the historical model it is. Tap a higher floor and the electron leaps up by swallowing a photon worth exactly the gap; tap a lower one and it leaps down, emitting one. Every photon lands at its vacuum wavelength on the spectrometer strip: in colour if your eyes could see it, in the hatched near-ultraviolet margin just past violet, or in the far-ultraviolet and infrared side panels. Your mission: make hydrogen glow with Balmer's barcode.
Your tasks
0/4How it connects to the theory
Each floor in the lab is Bohr's Eₙ = −13.6 eV/n², and each jump obeys his third postulate: the photon's energy equals the gap between two levels, and its wavelength is λ = h·c/ΔE, about 1240 divided by ΔE in electron-volts, which is the Rydberg formula in disguise. The four visible lines all end on n = 2, which is why Balmer could fit them with one formula in 1885; jumps that end on n = 1 fall in the ultraviolet and jumps that end on n = 3 in the infrared, the Lyman and Paschen series. Absorption demands the exact gap, so an atom waiting in n = 2 absorbs 656, 486, 434 or 410 nm on its way up to n = 3, 4, 5 or 6: a star's Balmer absorption barcode, built one jump at a time. Six levels allow fifteen distinct lines. The lab includes the one refinement Bohr himself added in 1913, letting the proton recoil, so its strip matches the measured vacuum wavelengths, 656.5, 486.3, 434.2 and 410.3 nm, to about 0.01 nm; tables measured in air, such as NIST's 656.28 nm for Hα, read about 0.03 percent shorter.
Quantum Leap Lab: Make Hydrogen Glow loads as you scroll down.
Make it stick
Light Beams Pass, floor by floor. Lyman, Balmer and Paschen are the series that land on floors 1, 2 and 3, in that order, and a rhyme gives their colours: land on One, the ultraviolet run; land on Two, from red to blue; land on Three, too red to see. For the visible barcode, remember two palindromes: 656 red and 434 blue-violet, with 486 blue-green between them and 410 violet at the end. To use it, find the floor where the electron lands, name the series and its band of light, then pin down the exact line with ΔE = 13.6 eV × (1/n₁² − 1/n₂²) and λ ≈ 1240/ΔE in nanometres.
Hydrogen is a strange hotel. Its single guest, the electron, may stay only on numbered floors, and the lift never stops between them. The floors crowd closer and closer together toward the roof, and stepping off the roof means leaving the hotel entirely: ionization. Riding down, the guest pays the difference in floor energies as one photon; riding up, it must hand in a photon worth exactly the fare, or take a hard enough shove in a collision. Where it breaks: the floors are energies, not places, so there is no guest standing at a definite spot and no lift shaft to travel through. The electron is a cloud of probability, not a tiny lodger with a room number and a route. And a real lift can jam between floors; an atom never can.
The whole chapter in one lineAtoms hold electrons only at discrete energies; jumping between them emits or absorbs a photon of exactly the difference, writing each element's spectral barcode.
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Vocab Match
Match each term to its definition, against the clock.
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Dr. Q's Quantum Quiz Show
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Prove it on paper
Answer every question, check your work, and read the explanations — the stretch challenge is for the truly mad.
Work through these on paper before checking the answers. Use Eₙ = −13.6 eV/n², photon energy equal to the difference between levels, the shortcut λ ≈ 1240/ΔE (nanometres and electron-volts), the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²) with R = 1.097×10⁷ per metre, and rₙ = n²a₀ with a₀ = 0.0529 nm. Take 1 eV = 1.602×10⁻¹⁹ joules and g = 9.81 m/s². Show units at every step.
Part A
Vocabulary
- Emission spectrum
- The bright lines at specific wavelengths given off by a hot, thin gas; unique to each element.
- Absorption spectrum
- Dark lines on a continuous spectrum where a cooler gas has absorbed light, at the same wavelengths as its emission lines.
- Spectroscopy
- The measurement and interpretation of spectra, used to identify elements and measure temperature, motion and magnetic fields.
- Nucleus
- The tiny, dense centre of an atom, holding all its positive charge and nearly all its mass; discovered by Rutherford in 1911.
- Stationary state
- In Bohr's model, an allowed state of the atom with a fixed energy, in which the electron does not radiate.
- Ground state
- The lowest-energy state of an atom; for hydrogen, n = 1 at −13.6 eV.
- Excited state
- Any state of an atom above the ground state, reached by absorbing energy and usually lasting only billionths of a second.
- Ionization energy
- The minimum energy needed to remove an electron from an atom; 13.6 eV for hydrogen in its ground state.
- Quantum leap
- A discrete jump of an atom between two allowed states, with no states in between; the smallest possible change, not a giant one.
- Spectral series
- A family of lines produced by jumps that all end on the same level, such as the Lyman (n = 1), Balmer (n = 2) and Paschen (n = 3) series.
- Bohr radius
- The radius of the smallest orbit in Bohr's hydrogen atom, a₀ ≈ 0.0529 nm; in modern theory, the most likely distance of a ground-state electron.
- Rydberg constant
- The constant R ≈ 1.097×10⁷ per metre in the formula for hydrogen's spectral lines; Bohr derived it from fundamental constants.
Part B
Questions
Auto-checked except short answers, which you mark yourself.
- Question 1.Multiple choice
Rutherford's 1911 conclusion from the Geiger–Marsden scattering experiments was that:
- Question 2.Multiple choice
Which transition in hydrogen emits the photon with the shortest wavelength?
- Question 3.Multiple choice
A cloud of cool atomic hydrogen at about 100 K, like the thin gas between the stars, sits between a bright source of continuous light and a spectrometer. Which lines appear dark?
- Question 4.True or false
According to Bohr, an electron in a stationary state radiates light continuously as it circles the nucleus.
- Question 5.True or false
Less energy is needed to ionize a hydrogen atom from its n = 2 level than from its ground state.
- Question 6.True or false
A ground-state hydrogen atom can absorb a photon of any energy between 10.2 eV and 13.6 eV.
- Question 7.Fill in the blank
The lowest-energy state of an atom, in which an undisturbed atom remains indefinitely, is called the state.
- Question 8.Fill in the blank
The family of hydrogen lines produced by jumps down to n = 2, which includes all of hydrogen's visible lines, is the series.
- Question 9.Short answer
Explain why an element produces bright lines in its emission spectrum and dark lines at exactly the same wavelengths in its absorption spectrum.
- Question 10.Short answer
Give two things Bohr's model of hydrogen gets right and two things it gets wrong.
- Question 11.Calculation
Use the Rydberg formula to find the wavelength of the Balmer line produced by a jump from n = 4 to n = 2, and the energy of its photon in electron-volts.
This one asks for more than one value — give each, with its units.
- Question 12.Calculation
Find the series limit of the Balmer series, the shortest wavelength any Balmer line can have, and the photon energy that corresponds to it. Which part of the spectrum is it in?
This one asks for more than one value — give each, with its units.
- Question 13.Calculation
Neutral-atom quantum computers excite atoms into Rydberg states with n of several tens or more. In Bohr's model of hydrogen, find the orbit radius and the energy for n = 100, and the energy needed to ionize the atom from that state.
This one asks for more than one value — give each, with its units.
- Question 14.Calculation
Express the energy of hydrogen's red quantum leap, 1.89 eV, in joules. How many such leaps would supply the energy needed to lift a 1.0-gram paperclip by 1.0 millimetre?
This one asks for more than one value — give each, with its units.
Part C · optional, dangerous, extremely rewarding
Mad scientist challenge
The star that broke the hydrogen code. In 1896 Edward Pickering reported, in the star ζ Puppis, a series of lines (spotted on Harvard's photographic plates by Williamina Fleming, whom he credited) resembling hydrogen's but with extra lines between the Balmer lines; in 1912 Alfred Fowler produced them in a tube of hydrogen mixed with helium. (a) Bohr's model for a single electron bound to a nucleus of charge Ze gives Eₙ = −13.6 eV × Z²/n². Write the levels of singly ionized helium, He⁺ with Z = 2, for n = 1 to 6. (b) Find the wavelengths of the He⁺ lines from n = 5, 6, 7 and 8 down to n = 4. (c) Which of these coincide with hydrogen's Balmer lines, which are new, and why were astronomers fooled into blaming hydrogen? (d) Bohr's reply to Fowler: the electron and nucleus both circle their common centre of mass, which multiplies each Rydberg constant by 1/(1 + m/M), where M is the nuclear mass. Using M/m = 1836 for the proton and 7294 for the helium nucleus, find the ratio of helium's effective constant (including Z² = 4) to hydrogen's, and estimate how far apart hydrogen's 656 nm line and helium's line from 6 to 4 really lie.
Recap & sign-off
Key takeaways
- Every element emits and absorbs light only at its own set of wavelengths, so line spectra are atomic fingerprints; matching them identified the Sun's elements, discovered helium and showed that stars are mostly hydrogen and helium
- Rutherford's 1911 nuclear atom explained Geiger and Marsden's scattering experiment, but classical physics predicted that its orbiting electrons would radiate, spiral into the nucleus in about 10⁻¹¹ seconds and emit a continuous smear of light
- Bohr's 1913 postulates: electrons occupy stationary states that do not radiate; allowed orbits have angular momentum L = nħ; light is emitted or absorbed only in jumps, as one photon carrying exactly the energy difference
- Hydrogen's levels are Eₙ = −13.6 eV/n², with orbit radii that grow as n² from the Bohr radius of 0.0529 nm; the ground state is n = 1 and the ionization energy is 13.6 eV
- Photon energies are level differences, which gives the Rydberg formula with R ≈ 1.097×10⁷ per metre: Lyman lines, ending on n = 1, are ultraviolet; Balmer lines, ending on n = 2, include the visible 656, 486, 434 and 410 nm; Paschen lines, ending on n = 3, are infrared
- A quantum leap is the smallest possible change in an atom's state, a discrete jump between allowed energies with nothing in between; hydrogen's red line carries just 3×10⁻¹⁹ joules, so it is no giant advance
- Bohr's model gets hydrogen's energies right but fails for atoms with more than one electron and for line brightness, and its orbits are not real paths; quantum mechanics replaced them with orbitals in 1925 and 1926
Dr. Q signs offSo the atom is a ladder, and light is the sound of electrons stepping down it, one exact rung at a time. But why those rungs? Bohr simply decreed that angular momentum comes in units of ħ and could not say why nature obeys. Next session a French aristocrat named Louis de Broglie offers an audacious answer: if light can behave like a particle, perhaps an electron can behave like a wave, and only waves that fit neatly around the nucleus survive. Dr. Q, signing off.
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Sources & further reading
- HyperPhysics (Georgia State University): Bohr Model Concepts · hyperphysics.phy-astr.gsu.edu
- HyperPhysics (Georgia State University): Hydrogen Energies and Spectrum · hyperphysics.phy-astr.gsu.edu
- NIST Handbook of Basic Atomic Spectroscopic Data: Strong Lines of Hydrogen · physics.nist.gov
- NobelPrize.org: Niels Bohr, Nobel Prize in Physics 1922, facts and prize motivation · nobelprize.org
- Niels Bohr (1913), On the Constitution of Atoms and Molecules, Philosophical Magazine 26, 1–25, transcription (ChemTeam) · chemteam.info