Unit 2 · Wave–Particle DualityChapter 7 of 25

The Double-Slit Experiment

One particle at a time, two paths, and the only mystery

  • 22 min read
  • 38 min listen
  • 20 videos
01Video briefing

Start with the preview

Start here — today's preview. Watch “Quantum mechanics and the double slit experiment” from Fermilab before (or after) this session. The lab will wait. Mostly.

Today's preview

Quantum mechanics and the double slit experiment

Fermilab9 min

Fermilab's Dr. Don Lincoln introduces the big ideas behind the most famous experiment in quantum physics: what waves do at two slits, what particles do, and why quantum objects fit neither picture. It sets you up for Parts 1 to 4; notice the questions it leaves open, because Parts 5 to 7 answer them.

Watch on YouTube

More from the video vault

Deep dive

3. Two-Slit Experiment; Quantum Weirdness

MIT OpenCourseWare51 min

Professor Robert Field's lecture from MIT's 5.61 Physical Chemistry (Fall 2017) works through the two-slit experiment, the evidence that light and matter behave as both waves and particles, and the uncertainty principle. University-level and unhurried, with the two-slit discussion starting about six minutes in: watch it after Part 4, and treat its uncertainty-principle discussion as a preview of chapter 8.

Watch on YouTube
Bonus

The Delayed Choice Quantum Eraser, Debunked

Sabine Hossenfelder13 min

Sabine Hossenfelder takes apart the claim that the delayed-choice quantum eraser rewrites the past, building up from the double slit and entanglement. Watch it after Part 7: her account of why fringes appear only in sorted subsets of the data is exactly the lesson's.

Watch on YouTube
  • Quantum mechanics and the double slit experiment — Fermilab — https://www.youtube.com/watch?v=nmxwVU88Bd8
  • 3. Two-Slit Experiment; Quantum Weirdness — MIT OpenCourseWare — https://www.youtube.com/watch?v=geKBtyDcZZY
  • The Delayed Choice Quantum Eraser, Debunked — Sabine Hossenfelder — https://www.youtube.com/watch?v=RQv5CVELG3U
02Cold open

Today's mission

Dr. Q · cold open

Lock the doors, dim the lights, and hand Psigor the electron gun. Last session we learned that every particle carries a wavelength. Today we test that claim in the cruellest way possible: one electron at a time, aimed at a wall with two slits. Each electron arrives whole, a single pinprick on the screen, exactly like a bullet. Yet thousands of pinpricks, fired so far apart that two almost never share the apparatus, arrange themselves into stripes that only a wave passing through both slits could paint. Then we will try to catch each electron choosing its slit, and watch the stripes vanish. Richard Feynman said this experiment contains the only mystery. Mwahaha — measurably! Let us go and be baffled properly.

By the end of this session you will be able to:

  1. Contrast Feynman's three two-slit experiments, with bullets, water waves and electrons, and explain why electrons fit neither classical picture
  2. Describe how single-particle experiments, from Bologna in 1974 and Hitachi in 1989 to Nebraska in 2013, built interference patterns one dot at a time
  3. Calculate fringe spacing with Δy ≈ λL/d for light and for electrons, and predict how it changes with each variable
  4. Apply the rule 'add the amplitudes, then square' to find bright fringes, dark fringes and fringe visibility, and explain why |ψ₁ + ψ₂|² ≠ |ψ₁|² + |ψ₂|²
  5. Explain how which-path information, recorded anywhere and read by no one, destroys interference, using Bohr's complementarity and Englert's relation D² + V² ≤ 1
  6. Explain what quantum eraser and delayed-choice experiments actually show, and why they neither change the past nor send signals
03The lesson

Read it — or listen along

7 parts. Press play on any part and the paragraph being read lights up as Dr. Q speaks.

Part 1

Bullets, Waves and Electrons

Richard Feynman, introducing quantum mechanics in his Caltech lectures of the early 1960s, began with one experiment, 'impossible, absolutely impossible, to explain in any classical way', which 'has in it the heart of quantum mechanics. In reality, it contains the only mystery.' He staged it three times with the same apparatus: a source, a wall pierced by two narrow slits, and a backstop where a movable detector counts arrivals. Only the projectile changes. Chapter 2 ran the version with light, whose bright and dark bands, called fringes, convinced Thomas Young that light is a wave.

First, bullets from a wobbly machine gun. Bullets arrive in lumps: whole bullets, one at a time, never half of one. Close slit 2 and arrivals pile into a hump behind slit 1, a probability distribution called P₁; close slit 1 and you get the hump P₂. Open both and the result is simply P₁ + P₂. Every bullet passes through one slit or the other, so the chances of arriving by either route add. No interference.

Second, water waves. Now the detector measures intensity, the energy delivered per second, which takes any value and comes in no lumps. With both slits open the intensity is not the sum of the single-slit intensities: ripples from the two slits reinforce where crest meets crest and cancel where crest meets trough, painting alternating bands. As chapter 2 showed, the wave heights, or amplitudes, add first, and the intensity is the square of the total.

Third, electrons, boiled off a hot tungsten wire. The detector clicks, and every click is a whole electron: they arrive in identical lumps, like bullets. Yet thousands of clicks with both slits open trace the bands of the water waves, and the pattern is not P₁ + P₂. Worse, at some places electrons land steadily when only one slit is open but almost never when both are. Opening a second route lowers the chance of arriving, which no bullet could do. Feynman warned that this experiment had 'never been done in just this way': the slits would have to be impossibly small. He was too pessimistic: at Tübingen in 1961, Claus Jönsson had already photographed electron fringes from two, three, four and five slits.

Watch this part

Part 2

One Dot at a Time

The decisive test sends electrons one at a time, so that none can jostle another. Pier Giorgio Merli, Gian Franco Missiroli and Giulio Pozzi filmed it in Bologna in 1974, and in 1989 Akira Tonomura and colleagues at Hitachi published the version every textbook now shows. They used an electron biprism, introduced by Gottfried Möllenstedt and Heinrich Düker in 1955: a filament thinner than a micrometre, at a small positive voltage between two grounded plates. Electron waves passing either side are bent together and overlap, just as waves from two slits do. Their 50,000-volt electrons had a wavelength of 5.4 pm.

The beam was so faint, about a thousand electrons per second, that each one crossed the 1.5-metre instrument in about twelve nanoseconds and the next typically trailed it by more than a hundred kilometres. There was almost never more than one electron inside. A detector of nearly 100 percent efficiency recorded each arrival as a single bright dot. After 10 electrons the dots look random; after 100, still random; after 3,000, faint stripes emerge; by 70,000 the fringes are unmistakable. No single dot shows a fringe. The pattern exists only in the statistics of many independent events.

Two conclusions follow. The fringes cannot come from electrons interfering with each other, because they never meet: whatever interferes belongs to each electron alone. And where any one electron lands is unpredictable; only the probabilities are fixed. In 2013 Roger Bach, Sy-Hwang Liou and Herman Batelaan of the University of Nebraska–Lincoln, with Damian Pope of the Perimeter Institute, performed Feynman's version literally: real slits 62 nm wide and 272 nm apart, electrons of 600 eV and wavelength 50 pm arriving about once a second, and a movable mask to close either slit. One slit gave a broad hump; two gave fringes, built dot by dot over about two hours.

Watch this part

Part 3

Reading the Stripes: Fringe Spacing

Where do the bright fringes fall? Let d be the distance between the slit centres and L the much larger distance to the screen. A point at height y above the centre line is seen from the slits at an angle θ, and the two routes to it differ in length by d sin θ, the path difference. When that is a whole number of wavelengths, mλ with m = 0, ±1, ±2 and so on, the waves arrive in step: a bright fringe. At half-integer numbers of wavelengths they cancel: a dark fringe.

For small angles in radians, sin θ ≈ θ ≈ y/L, so the bright fringes sit at y = mλL/d, evenly spaced by Δy ≈ λL/d. Longer wavelengths and more distant screens spread the stripes; wider slit separations squeeze them. A red laser of 650 nm through slits 0.20 mm apart onto a wall 3.0 metres away gives fringes 9.75 mm apart. Each slit's width, a, adds a broad single-slit diffraction envelope with its first dark points at y ≈ ±λL/a, and roughly 2d/a − 1 fine fringes fit inside its central lobe.

For matter, the wavelength comes from chapter 6: λ = h/p. The Nebraska electrons, at 50 pm, met slits 272 nm apart, so neighbouring fringes were 1.8×10⁻⁴ radians apart, just 0.18 mm on a screen a metre away. Tonomura's fringes were only 700 nm apart where they formed, and electron lenses magnified them 2,000 times to 1.4 mm. That is why electron versions demand a biprism or exquisitely fine slits: tiny wavelengths need tiny slit separations.

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Part 4

Add the Amplitudes, Then Square

Here is the rule that does the work. Quantum mechanics assigns each way an event can happen a probability amplitude: a complex number, pictured as one of chapter 2's rotating arrows, with a length and a direction called its phase. Max Born's 1926 rule, the subject of chapter 9, makes the probability the squared length of the amplitude. Call the amplitudes for reaching a point through slit 1 and through slit 2 ψ₁ and ψ₂. With one slit open, the probability density is |ψ₁|². With both open and nothing distinguishing the routes, the amplitudes add first and the sum is squared: |ψ₁ + ψ₂|².

Squaring a sum is not summing squares. Written out, |ψ₁ + ψ₂|² is |ψ₁|² + |ψ₂|² plus an interference term: twice the product of the arrow lengths times the cosine of φ, the angle between the arrows, which the path difference sets as φ = 2π d sin θ/λ. Where the arrows align, the cosine is 1 and, for equal slits, the probability is four times one slit's value; where they oppose, the cosine is −1 and the probability is zero. Averaged across a fringe the cosine vanishes, leaving twice the one-slit value: probability is redistributed, never created. So |ψ₁ + ψ₂|² ≠ |ψ₁|² + |ψ₂|², and that inequality is the double-slit experiment.

Bullets obey the plain sum because the air and light they scatter on the way record each bullet's route. Feynman reduced the subject to one switch. When an event can happen in several ways that are indistinguishable, meaning nothing in the universe records which way it went, add the amplitudes, then square. When the ways are distinguishable, even in principle, square each and add the probabilities. The stripes' contrast is the fringe visibility V: the difference between the highest and lowest probability across a fringe divided by their sum, 1 for perfect stripes and 0 for none. Unequal slits lower V without destroying it. In an ideal apparatus, only distinguishability destroys it.

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Part 5

Spying on the Slits: Complementarity

Everyone wants to catch the electron in the act. Feynman's version puts a lamp behind the wall: an electron passing a slit scatters a photon, and a flash near slit 1 or slit 2 reveals its route. Every electron is seen at one slit, never both; those seen at slit 1 build P₁, those at slit 2 build P₂, and the total is P₁ + P₂. The fringes are gone. Dim the lamp and only the electrons that slip by unseen still build fringes. Lengthen the light's wavelength beyond about the slit separation, so the flashes blur too much to tell the slits apart, and the fringes return.

Feynman explained this as a kick: light sharp enough to resolve the slits jolts each electron by more than a fringe. As Niels Bohr later recalled their debates at the 1927 Solvay conference, Einstein proposed hanging the slitted screen on springs and reading its recoil to learn each particle's slit. Bohr replied that measuring the recoil so precisely would leave the screen's own position uncertain by more than a fringe, washing the pattern out. Weeks earlier, at Como, Bohr had introduced complementarity: interference and path knowledge are complementary aspects of a quantum object, each revealed by its own experimental arrangement, never both completely in the same one.

Complementarity is not all-or-nothing, and since the 1980s physicists have quantified it. In 1996 Berthold-Georg Englert proved that D² + V² ≤ 1, where V is the visibility and D, the distinguishability, measures how well the best possible reading of the detector could identify the path: 1 for certainty, 0 for a coin toss, with the chance of guessing right equal to half of (1 + D). A detector whose best reading names the correct slit 90 percent of the time has D = 0.8, so V can be at most 0.6. Partial knowledge buys partial stripes. Notice what the inequality never mentions: anyone's awareness of the result.

Watch this part

Part 6

No Observer Required

Is the kick really the culprit? In 1998 Stephan Dürr, Tilman Nonn and Gerhard Rempe split beams of rubidium atoms with standing waves of light and stored which-way information in each atom's internal energy state, a marker that barely touches the atom's motion. The momentum disturbance was far too small to blur the fringes, yet the fringes vanished whenever the marker held path information. The authors traced the loss not to kicks but to correlations between the marker and the atom's motion. A kick is one way to create such a correlation. It is not the essence.

The mechanism, in words: a which-path detector is any physical system that ends in one state, m₁, if the particle took slit 1, and another, m₂, if it took slit 2. Particle and marker then share an entangled state, a superposition of 'slit 1 with m₁' and 'slit 2 with m₂' in which neither part has a description of its own. On the screen, the interference term is multiplied by the overlap γ of the two marker states, whose size runs from 0 to 1. Identical markers, γ = 1, carry no information and the fringes survive; perfectly distinguishable ones, γ = 0, delete the interference term; in between, for equal slits, the visibility equals the size of γ.

None of this needs a scientist or a conscious mind, only a record, anywhere. In 2004 Lucia Hackermüller, Markus Arndt, Anton Zeilinger and colleagues in Vienna laser-heated C₇₀ fullerene molecules flying at 190 m/s into an interferometer whose paths were up to about a micrometre apart. Below about 1,000 kelvin, heat did not disturb their interference. Near 3,000 kelvin each glowing molecule emitted a few visible photons, short enough in wavelength to betray its path, and as the heating rose the visibility fell from its unheated 47 percent to 29, then 7, then 0. The photons vanished into the chamber walls, detected by no one: the environment had made the measurement. This is decoherence, the subject of chapter 22.

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Part 7

Erasers and Delayed Choices, Without Time Travel

If information destroys the fringes, can destroying it restore them? Marlan Scully and Kai Drühl proposed such a quantum eraser in 1982; in 2000 Yoon-Ho Kim, Yanhua Shih, Scully and colleagues built the famous delayed version. Laser light through a double slit struck a crystal at two spots, A and B, either of which could turn one ultraviolet photon into an entangled pair. Each signal photon went to a movable detector, D0, playing the screen. Its twin, the idler, arrived at least 8 nanoseconds later at one of four detectors: D3 or D4 revealed whether the pair came from A or B; D1 or D2, behind a beam splitter mixing the routes, erased that information. Chance made the choice.

The results are subtle and entirely unspooky. The dots at D0 alone never show fringes, whatever the idlers later do. Sorted by their partners, the dots paired with D1 show fringes, those paired with D2 show anti-fringes shifted by half a fringe, and those paired with D3 or D4 show none. Add the D1 and D2 subsets and the stripes cancel back into a featureless hump. The later measurement moved no dot; it only determined how dots already recorded could be sorted to reveal correlations. And since sorting needs the idler records, carried by ordinary means no faster than light, no eraser can send a message, to the past or anywhere else.

John Wheeler's delayed-choice experiment, proposed in 1978, sharpens the point: let a photon enter an interferometer, then decide, while it is inside, whether to recombine the paths, testing for interference, or keep them apart, testing which path it took. In 2007 Vincent Jacques, Alain Aspect, Jean-François Roch and colleagues did it with single photons, a 48-metre interferometer and a quantum random number generator whose choice no light-speed signal could have carried to the photon's entry. Recombined paths gave 94 percent visibility; separate paths were identified with under 1 percent error. The photon did not rewrite its history. It never had a history of the form 'travelled as a wave' or 'travelled as a particle' to rewrite.

Watch this part

04Video shelf

Go deeper on video

17 more videos for this chapter, 11 of them from universities, research institutes and Nobel lectures. The clips under “Watch this part” in the lesson start at the moment that matters.

17 videos · 6 h 57 min

  • Lecture · Royal Institution

    Wave-Particle Duality Explained with Double Slit Experiments | CHRISTMAS LECTURES1999 | Neil Johnson

    The Royal Institution · Neil Johnson

    A clip from Neil Johnson's 1999 Royal Institution Christmas Lectures that explains wave–particle duality with double-slit demonstrations. Use it as a warm-up for Feynman's three runs: for each demonstration, ask whether the result is lumps that add, like bullets, or bands that interfere, like water waves.

  • Demo · Brown University

    7A55.20 Young's Double Slit Interference with single photon particles

    Brown Physics Demos

    Brown University's physics demonstrations show Young's double slit first with light waves, then with single photons: the light version of this section's one-at-a-time test. Look for the section's two conclusions: each photon registers as one localised detection, yet the detections together obey the two-slit pattern.

  • Demo · YouTube

    Interference Demo: Double Slit

    Physics Demos · Boyd F. Edwards

    A Utah State University demonstration: two double slits that share a 0.04 mm slit width but have separations of 0.25 mm and 0.5 mm, and the wider separation gives the more closely spaced fringes. Doubling d should halve the fringe spacing Δy ≈ λL/d, while the broad single-slit envelope, set by the unchanged width, should stay put.

  • Explainer · YouTube

    Intensity in YDSE (Visual method-phasors) I =4Io cos^2(phi/2)| Wave optics | Physics | Khan Academy

    Khan Academy India - English · Mahesh Shenoy

    Khan Academy adds two coherent waves as rotating arrows (phasors) and derives I = 4I₀cos²(φ/2), this section's interference term worked out for light. Read intensity as probability and the two waves as ψ₁ and ψ₂, and you get the lesson's result for equal slits: four times one slit's value where the arrows align, zero where they oppose.

  • Explainer · YouTube

    The biggest lie about the double slit experiment

    Looking Glass Universe

    Mithuna Yoganathan takes apart the popular telling in which watched electrons turn into little bullets that pile up in two lumps. With which-path detectors, she argues, each electron goes through the slit where it was seen, but the dots still follow a wave-shaped single-slit pattern, which is what this section's P₁ and P₂ really look like.

  • Explainer · YouTube

    Did MIT Researchers Just Prove Einstein Wrong?

    Sabine Hossenfelder

    The 2025 MIT experiment from this section's callout, set against Einstein's 1927 double-slit challenge that the section's springs story describes. Hossenfelder asks whether the MIT group really proved Einstein wrong, as they claim: weigh her verdict against the callout's 'Bohr wins again'.

  • Explainer · YouTube

    10 Quantum Myths, Debunked

    Sabine Hossenfelder

    Ten quantum myths counted down to number 1, 'Consciousness Influences the Outcome of Quantum Processes': this section's callout, and where the jump lands. Compare her answer with the section's: what wipes out fringes is a record, anywhere, not a mind. Rewind to 0:10 for the other nine.

  • Lecture · Institute for Quantum Computing

    Quantum Frontiers Lecture: Alain Aspect, From Einstein to Wheeler:wave particle duality for a photon

    Institute for Quantum Computing · Alain Aspect

    Alain Aspect, a co-author of the 2007 single-photon version of Wheeler's delayed-choice experiment in this section, in IQC's Quantum Frontiers Distinguished Lecture Series, on experiments with a true single-photon source that bring out the strangeness of wave–particle duality. You hear the story from one of the people who did the experiments.

  • Explainer · YouTube

    We Were WRONG About the Quantum Eraser! ft. @LookingGlassUniverse​

    PBS Space Time

    PBS Space Time admits it got the delayed-choice quantum eraser wrong, and Mithuna Yoganathan of Looking Glass Universe co-hosts and shows how to do the experiment at home. Hold it to this section's key step: the screen's dots alone never show fringes; only sorting them by their partners' results reveals fringes and anti-fringes, which sum back to a featureless hump.

  • Lecture · MIT

    Lecture 2: Experimental Facts of Life

    MIT OpenCourseWare · Allan Adams · 2013

    The lecture from MIT 8.04 Quantum Physics I (Allan Adams, 2013) that goes with Chapter 7. The whole course is in the Lecture Hall.

  • Lecture · Yale

    19. Quantum Mechanics I: The key experiments and wave-particle duality

    YaleCourses · Ramamurti Shankar · 2010

    The lecture from Yale University PHYS 201 Fundamentals of Physics II (Ramamurti Shankar, 2010) that goes with Chapter 7. The whole course is in the Lecture Hall.

  • Lecture · Oxford

    007 Back to Two-Slit Interference, Generalization to Three Dimensions and the Virial Theorem

    University of Oxford · James Binney · 2009–10

    The lecture from University of Oxford Quantum Mechanics (James Binney, 2009–10) that goes with Chapter 7. The whole course is in the Lecture Hall.

  • Lecture · Royal Institution

    The mind-bending reality of quantum mechanics - with Jim Al Khalili

    The Royal Institution · Jim Al-Khalili · 2025

    A full Royal Institution Discourse from physicist Jim Al-Khalili on why quantum mechanics is both the strangest and the most successful theory in science, from the 1920s pioneers to lasers, MRI and quantum sensing. Watch it after the lesson, and keep asking which claims are experimental facts and which are interpretations.

  • Course · MIT

    Quantum Physics I

    MIT OpenCourseWare · Allan Adams · 2013

    Allan Adams' celebrated course starts from superposition and the experimental facts, builds the wavefunction, operators and the Schrödinger equation, then tours scattering, hydrogen, identical particles and band structure before closing on entanglement and Bell's theorem. Calculus and a little linear algebra are enough to keep up.

  • Course · MIT

    Physical Chemistry

    MIT OpenCourseWare · Robert Field · 2017

    Quantum mechanics as chemists use it, taught by the spectroscopist Robert Field: the photoelectric effect and Compton scattering, boxes and oscillators, hydrogen and many-electron atoms. Strong on spectroscopy, the experimental face of quantization.

  • Course · Yale

    Fundamentals of Physics II

    YaleCourses · Ramamurti Shankar · 2010

    Ramamurti Shankar, author of a classic graduate textbook, gives one of the gentlest rigorous introductions anywhere: seven lectures from the double-slit experiment through measurement, the particle in a box, the time-dependent Schrödinger equation and the postulates.

  • Course · Oxford

    Quantum Mechanics

    University of Oxford · James Binney · 2009–10

    James Binney's Oxford course, given over Michaelmas Term 2009 and Hilary Term 2010 and built on probability amplitudes and Dirac notation from the very first lecture. Highlights: tunnelling and radioactive decay, the EPR argument and Bell's inequality, spin and the Stern–Gerlach experiment, and a full treatment of hydrogen.

Every video for Chapter 7 in the Video Library

05To the blackboard

Key equations

Equation 1

Bright fringes

dsin⁡θm=mλ,ym≈m λLd,m=0,±1,±2,…d\sin\theta_m = m\lambda, \qquad y_m \approx \frac{m\,\lambda L}{d}, \qquad m = 0, \pm 1, \pm 2, \ldots

Waves from the two slits reinforce wherever their path difference is a whole number of wavelengths. For small angles each bright fringe sits m fringe spacings from the centre.

What each symbol means
SymbolMeaningUnit
ddistance between the slit centresm
θangle from the centre line to the point on the screenrad
mfringe order: 0, ±1, ±2 …none
λwavelength (λ = h/p for matter)m
Ldistance from slits to screenm
yheight on the screen above the centre linem

Say it: “d times the sine of theta m equals m lambda, so the m-th bright fringe sits at y m approximately equal to m lambda L divided by d, for m equal to zero, plus or minus one, plus or minus two, and so on”

Equation 2

Fringe spacing

Δy≈λLd\Delta y \approx \frac{\lambda L}{d}

Neighbouring bright fringes are evenly spaced by the wavelength times the screen distance divided by the slit separation. Longer waves and longer throws spread the stripes; wider slit separations squeeze them. Valid when the angles are small.

What each symbol means
SymbolMeaningUnit
Δydistance between neighbouring bright fringesm
λwavelength of the light or matter wavem
Ldistance from slits to screenm
ddistance between the slit centresm

Say it: “delta y is approximately lambda times L divided by d”

Equation 3

Add the amplitudes, then square

P12=∣ψ1+ψ2∣2=∣ψ1∣2+∣ψ2∣2+2 ∣ψ1∣ ∣ψ2∣cos⁡φ  ≠  ∣ψ1∣2+∣ψ2∣2P_{12} = |\psi_1 + \psi_2|^2 = |\psi_1|^2 + |\psi_2|^2 + 2\,|\psi_1|\,|\psi_2|\cos\varphi \;\neq\; |\psi_1|^2 + |\psi_2|^2

When nothing records which slit was used, the two amplitudes add before squaring, and the cross term makes the fringes: for equal slits, four times the single-slit probability where the phases agree and zero where they are opposite.

What each symbol means
SymbolMeaningUnit
P₁₂probability density at a point with both slits open1/m
ψ₁, ψ₂complex probability amplitudes for arriving via slit 1 and slit 2; their squared sizes are the one-slit probability densities1/√m
φphase difference between the two amplitudes, 2π d sin θ/λrad

Say it: “P one-two equals the magnitude of psi one plus psi two, squared, which is the magnitude of psi one squared plus the magnitude of psi two squared plus twice the magnitudes of psi one and psi two times the cosine of phi; this is not equal to the magnitude of psi one squared plus the magnitude of psi two squared”

Equation 4

Interference with a which-path marker

P=∣ψ1∣2+∣ψ2∣2+2 ∣γ∣ ∣ψ1∣ ∣ψ2∣cos⁡φ,0≤∣γ∣≤1P = |\psi_1|^2 + |\psi_2|^2 + 2\,|\gamma|\,|\psi_1|\,|\psi_2|\cos\varphi, \qquad 0 \le |\gamma| \le 1

If a marker ends in a different state for each path, the interference term is multiplied by the overlap gamma of the two marker states. Identical markers leave full fringes; perfectly distinguishable markers give the bullets' rule, P one plus P two. A complex gamma also shifts the fringes sideways.

What each symbol means
SymbolMeaningUnit
γoverlap of the two possible marker states: 1 if identical, 0 if perfectly distinguishablenone
ψ₁, ψ₂amplitudes for the two paths1/√m
φphase difference between the pathsrad

Say it: “P equals the magnitude of psi one squared plus the magnitude of psi two squared plus two times the size of gamma times the magnitudes of psi one and psi two times the cosine of phi, where the size of gamma lies between zero and one”

Equation 5

Visibility and Englert's duality relation

V=Pmax⁡−Pmin⁡Pmax⁡+Pmin⁡,D2+V2≤1V = \frac{P_{\max} - P_{\min}}{P_{\max} + P_{\min}}, \qquad D^2 + V^2 \le 1

Visibility measures the contrast of the fringes. Englert's 1996 inequality makes Bohr's complementarity quantitative: the better any detector could tell the paths apart, the weaker the fringes must be, whether or not anyone reads it.

What each symbol means
SymbolMeaningUnit
Vfringe visibility: 1 for perfect fringes, 0 for nonenone
P max, P minhighest and lowest probability density across a fringe1/m
Ddistinguishability of the paths; the best chance of guessing the path correctly is (1 + D)/2none

Say it: “V equals P max minus P min, divided by P max plus P min; and D squared plus V squared is less than or equal to one”

06Worked examples

Real numbers, step by step

Cover the steps, try the problem yourself, then reveal the solution one step at a time.

Example 1

Stripes from a laser pointer

Problem

Red light of wavelength 650 nm passes through two slits whose centres are 0.20 mm apart; each slit is 0.050 mm wide. The screen is 3.0 metres away. Find the fringe spacing, the positions of the first three bright fringes on one side, and how many bright fringes fit inside the central diffraction envelope.

  1. Step 1: Fringe spacing: Δy = λL ÷ d = (6.50×10⁻⁷ metres × 3.0 metres) ÷ (2.0×10⁻⁴ metres) = 9.75×10⁻³ metres = 9.75 mm.

  2. Step 2: Bright fringes sit at y = m × Δy: 9.75 mm, 19.5 mm and 29.25 mm for m = 1, 2 and 3.

  3. Step 3: Small-angle check: even the third fringe is at θ ≈ 3λ ÷ d = (3 × 6.50×10⁻⁷) ÷ (2.0×10⁻⁴) = 9.75×10⁻³ radians, about 0.56°, so sin θ ≈ θ is excellent.

  4. Step 4: Envelope: the first single-slit dark point is at y = λL ÷ a = (6.50×10⁻⁷ × 3.0) ÷ (5.0×10⁻⁵) = 0.039 metres = 39 mm.

  5. Step 5: That is exactly where the m = 4 bright fringe would fall, 4 × 9.75 mm = 39 mm, so that fringe is missing. Inside the central envelope sit m = 0, ±1, ±2 and ±3: seven bright fringes, matching 2d ÷ a − 1 = 2 × 4 − 1 = 7.

Answer

Δy = 9.75 mm; bright fringes at 9.75, 19.5 and 29.3 mm; seven bright fringes inside the central envelope

Why it matters: The fine stripes are set by the slit separation d, the broad envelope by the slit width a. Here d is exactly four times a, so the fourth fringe lands on a single-slit zero and disappears.

Try it yourself first — then check each step.
Example 2

Electrons through nanoslits

Problem

In the 2013 Nebraska experiment, electrons of kinetic energy 600 eV passed through two slits 272 nm apart and 62 nm wide. Find their de Broglie wavelength and the fringe spacing on a screen 1.0 metre away, ignoring the magnifying lens actually used.

  1. Step 1: Kinetic energy: K = 600 eV = 600 × 1.602×10⁻¹⁹ = 9.61×10⁻¹⁷ joules.

  2. Step 2: Momentum: p = √(2 × m × K) = √(2 × 9.109×10⁻³¹ kg × 9.61×10⁻¹⁷ joules) = 1.32×10⁻²³ kilogram-metres per second.

  3. Step 3: Wavelength: λ = h ÷ p = (6.626×10⁻³⁴) ÷ (1.32×10⁻²³) = 5.01×10⁻¹¹ metres, about 50 pm. Chapter 6's shortcut agrees: 1.226 ÷ √600 = 0.0500 nm.

  4. Step 4: Fringe spacing: Δy = λL ÷ d = (5.01×10⁻¹¹ × 1.0) ÷ (2.72×10⁻⁷) = 1.84×10⁻⁴ metres = 0.18 mm, an angle of 1.8×10⁻⁴ radians.

  5. Step 5: Envelope: λL ÷ a = (5.01×10⁻¹¹ × 1.0) ÷ (6.2×10⁻⁸) = 8.1×10⁻⁴ metres, so with d ÷ a ≈ 4.4 the central lobe holds four bright fringes on each side of the centre, nine in all.

Answer

λ ≈ 50 pm and Δy ≈ 0.18 mm on a screen 1.0 metre away

Why it matters: The electron wavelength is about 13,000 times shorter than red light, so the slits had to be hundreds of times closer together than in a laser demonstration, and the fringes still came out finer.

Try it yourself first — then check each step.
Example 3

Add, then square: unequal slits and a closed slit

Problem

A detector sits at one spot on the screen. With only slit 1 open it counts 9 electrons per minute; with only slit 2 open, 1 per minute. With both open, what count rates are possible, depending on the phase difference at that spot? Compare with the bullet rule and find the fringe visibility. Then, for two equal slits each giving a rate R alone, what happens at a dark fringe when one slit is closed?

  1. Step 1: The amplitude sizes are the square roots of the one-slit rates: √9 = 3 for slit 1 and √1 = 1 for slit 2, in units where squared amplitudes are counts per minute.

  2. Step 2: Arrows in step, φ = 0: (3 + 1)² = 16 per minute. Arrows opposed, φ = 180°: (3 − 1)² = 4 per minute.

  3. Step 3: At φ = 90° the cosine is zero, giving 9 + 1 = 10 per minute: the bullet rule P₁ + P₂, which a classical particle would give at this spot whatever the phase.

  4. Step 4: Visibility: V = (16 − 4) ÷ (16 + 4) = 12 ÷ 20 = 0.6. Unequal slits weaken the stripes but cannot erase them.

  5. Step 5: Equal slits: bright fringe (√R + √R)² = 4R, dark fringe (√R − √R)² = 0. Close one slit and the dark-fringe spot jumps from 0 to R.

Answer

Between 4 and 16 per minute (10 at φ = 90°), against 10 per minute for bullets whatever the phase; V = 0.6. At a dark fringe, closing a slit raises the rate from zero to R

Why it matters: Amplitudes, not probabilities, are what add. That is how opening a second route can make an arrival less likely, something no classical particle could ever do.

Try it yourself first — then check each step.
Example 4

The price of a leaky detector

Problem

Read in the best possible way, a which-path detector names the correct slit for 90 percent of the particles. Using Englert's relation D² + V² ≤ 1, find the distinguishability and the largest possible fringe visibility. If the detector is an ideal marker whose two states have overlap γ, which γ does this, and what happens when γ = 0?

  1. Step 1: The best chance of guessing right is (1 + D) ÷ 2, so 0.90 = (1 + D) ÷ 2, giving D = 2 × 0.90 − 1 = 0.80.

  2. Step 2: Englert: V² ≤ 1 − D² = 1 − 0.64 = 0.36, so V ≤ √0.36 = 0.60.

  3. Step 3: For an ideal marker and equal slits, V equals the size of γ and D = √(1 − γ²), so the relation holds with equality: γ = 0.60 gives D = √(1 − 0.36) = 0.80.

  4. Step 4: With γ = 0 the marker states are perfectly distinguishable: D = 1 and V = 0, and the pattern is P₁ + P₂, the bullets' rule.

Answer

D = 0.80 and V ≤ 0.60; an ideal marker with overlap γ = 0.60 achieves exactly this; γ = 0 gives D = 1 and no fringes

Why it matters: Complementarity is a sliding scale, not a switch: every scrap of path knowledge a detector could supply is paid for in fringe visibility, whether or not anyone ever reads it.

Try it yourself first — then check each step.
07Myth busters

What everyone gets wrong

Read the myth, decide whether you believed it, then bust it.

  • Myth #1

    The particle splits in half, and one half goes through each slit.

    Truth

    Every detection ever made finds a whole particle. Put a detector at each slit and exactly one fires, registering the full charge, never half; on the screen each electron arrives as one dot. What passes through both slits is the probability amplitude, which is not a piece of the particle. Whether a definite particle also travels one route is a question of interpretation: in pilot-wave theory it does, guided by a wave that passes through both slits.

  • Myth #2

    A human must watch for the pattern to vanish: the fringes disappear because someone becomes aware of the path.

    Truth

    Fringes vanish whenever any physical system holds a record that could distinguish the paths, read or unread. In 2004 hot C₇₀ molecules lost their fringes by emitting a few thermal photons into the walls of a vacuum chamber, seen by no one. The cause is entanglement with a marker or the environment, called decoherence. No experiment has ever shown consciousness playing a role.

  • Myth #3

    The quantum eraser changes the past: a later choice reaches back and decides whether earlier particles went through one slit or both.

    Truth

    The pattern of the first-detected photons never changes, whatever happens later; on its own it is always a featureless hump. Fringes appear only in subsets sorted afterwards using the partner photons' results, and complementary subsets, fringes and anti-fringes, add back to the hump. Because sorting needs those results, carried by ordinary signals, nothing travels backward in time and no message can be sent.

  • Myth #4

    The interference pattern forms because many particles in the beam bump into, or interfere with, one another.

    Truth

    Tonomura's electrons arrived about a thousand per second, typically more than a hundred kilometres apart, so there was almost never more than one in the instrument; the Nebraska electrons came about once a second. The fringes built up anyway. Each particle's amplitude interferes with itself, and the stripes are the statistics of many independent events.

08Interactive lab

Your turn at the controls

Welcome to the Double-Slit Simulator, a firing range for single quanta. Fire particles one at a time at a pair of slits and watch each land as a single dot on the detector screen, then switch on the theory overlay to see the probability curve the dots are secretly obeying. Sliders set the wavelength, the slit separation and width, and the distance to the screen; switches close either slit or turn on a which-path detector at the slits.

Your tasks

0/4

How it connects to the theory

Every dot is drawn at random from the add-then-square rule of Part 4, P = |ψ₁ + ψ₂|², with each slit's amplitude shaped by its width; the overlay is the same curve, and its fringe spacing follows Δy ≈ λL/d. Closing a slit deletes one amplitude. The which-path detector entangles each particle with a marker, driving the overlap γ to zero and deleting the interference term, which leaves P₁ + P₂, the bullets' rule of Part 1. That looks like one broad hump rather than two separate humps, because each narrow slit spreads its particles so widely that the two single-slit patterns overlap almost completely. Nobody in the program is watching: the detector only records.

Double-Slit Simulator: Fire One Particle at a Time loads as you scroll down.

Win the challenge to tick “lab won” on your chapter checklist.
Open full-screen lab
09Memory aids

Make it stick

Memory trick

Think DOTS, because dots are all a double-slit screen ever shows you. D is for Dots: every particle lands whole, as one dot, never half. O is for Order of operations: add the amplitudes first, square second, and the cross term paints the stripes. T is for Tape measure: Δy ≈ λL/d, so a longer wavelength or a longer throw spreads the stripes and a wider slit separation squeezes them. S is for Snitch: if anything anywhere, a photon, a gas molecule, an atom's internal state, keeps a record of the path, the stripes are gone, whether or not anyone reads it. Then seal it with a rhyme: if the world can know, the stripes won't show. Face any double-slit question by walking the letters in order: where do the dots land, what adds, how far apart, and who snitched?

Analogy — and where it breaks

Shine unpolarized laser light through two slits, each covered by a polarizing filter like the lens of polarized sunglasses, so both slits pass equal brightness whatever the filters' angles. With the filters aligned, light from the two slits can cancel and the stripes are crisp. Turn one filter a quarter turn so the polarizations are perpendicular: now each slit's light carries a built-in label saying where it came from, perpendicular polarizations cannot cancel, and the stripes melt into a smooth hump. Turn it part way and the stripes are partial, with visibility equal to the cosine of the angle between the filters, just like the marker overlap γ. Where it breaks: classical light is a real field spread across both slits, while each quantum particle is detected whole at one point. And in quantum mechanics the label need not ride on the particle you detect at all. It can sit in a separate system, a stray photon or a partner photon, which is why erasing it means sorting the partner's results, not repainting the screen.

The whole chapter in one line

Each particle lands as one dot, but indistinguishable paths add amplitudes into stripes; leave any record of the path anywhere, and the stripes vanish.

Leitner flashcards

Flashcards

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10Games

Play it into long-term memory

Match the vocabulary, then take the Quiz Show. Score 70% or better to tick it off your checklist.

Vocab match · timed

Vocab Match

Match each term to its definition, against the clock.

  • 12 pairs in 2 rounds
  • 100 points a match, more on a streak
  • −25 per mistake · speed bonus each round
  • Finish with 3 mistakes or fewer to win
Live from the lab

Dr. Q's Quantum Quiz Show

Dr. Q, your host

Welcome, contestants! 8 questions, 30 seconds each, and one mad scientist judging you, lovingly. Answer fast for a speed bonus; answer right in a row and your points multiply.

  • 100 per answer
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11Worksheet

Prove it on paper

Answer every question, check your work, and read the explanations — the stretch challenge is for the truly mad.

14 questions12 terms1 challenge

Work these on paper before checking the answers. Use Δy ≈ λL/d, d sin θ = mλ, λ = h/p, P = |ψ₁ + ψ₂|² and D² + V² ≤ 1. Take h = 6.626×10⁻³⁴ J·s, electron mass 9.109×10⁻³¹ kg and 1 eV = 1.602×10⁻¹⁹ joules. Use the small-angle approximation and show units at every step.

0/14 answered · saved on this device

Part A

Vocabulary

Fringe
One of the bright or dark bands of an interference pattern.
Fringe spacing
The distance between neighbouring bright fringes on the screen, Δy ≈ λL/d for small angles.
Path difference
The difference in distance from the two slits to a point on the screen, d sin θ; whole numbers of wavelengths give bright fringes.
Probability amplitude
A complex number assigned to each way an event can happen; the probability is its squared magnitude.
Interference term
The part of |ψ₁ + ψ₂|² beyond |ψ₁|² + |ψ₂|²: twice the product of the amplitudes' sizes times the cosine of their phase difference.
Indistinguishable alternatives
Ways an event can happen that leave no record anywhere of which one occurred; their amplitudes add before squaring.
Which-path information
Any physical record, read or unread, that could reveal which slit a particle went through.
Complementarity
Bohr's principle of 1927 that wave-like interference and particle-like path knowledge cannot both be fully displayed in one experimental arrangement.
Fringe visibility
The contrast of an interference pattern, (highest − lowest) ÷ (highest + lowest) probability; 1 for perfect fringes, 0 for none.
Entanglement
A joint state of two systems, such as a particle and a which-path marker, that cannot be described as separate states of each.
Decoherence
The loss of interference that occurs when a system becomes entangled with its environment, which carries away which-path information.
Quantum eraser
An experiment that recovers interference in sorted subsets of the data by measuring partner systems in a way that cannot reveal the path.

Part B

Questions

Auto-checked except short answers, which you mark yourself.

  1. Question 1.Multiple choice

    In Feynman's comparison, what do electrons have in common with bullets?

  2. Question 2.Multiple choice

    A double-slit setup produces fringes 6.0 mm apart. The slit separation is doubled and the screen is moved to three times its original distance. What is the new fringe spacing?

  3. Question 3.Multiple choice

    A which-path detector at the slits records each electron's slit on a hard drive, but the file is deleted unread before anyone looks. What does the screen show?

  4. Question 4.True or false

    In Tonomura's 1989 experiment, the fringes formed because electrons in the beam interfered with one another.

  5. Question 5.True or false

    Opening a second slit can reduce the number of particles arriving at certain points on the screen.

  6. Question 6.True or false

    In the 2007 realization of Wheeler's delayed-choice experiment, the choice whether to recombine the two paths was made so that no light-speed signal could have told the photon about it before it entered the interferometer, and the results still agreed with ordinary quantum mechanics.

  7. Question 7.Fill in the blank

    For indistinguishable alternatives, quantum mechanics says to add the probability first and square afterwards.

  8. Question 8.Fill in the blank

    Bohr's name for the principle that interference and which-path knowledge cannot both be fully displayed in one experimental arrangement is .

  9. Question 9.Short answer

    Using evidence from real experiments, explain why it is wrong to say that each electron splits in half at the slits.

  10. Question 10.Short answer

    Hot C₇₀ molecules lose their interference fringes even though no detector watches the slits. Explain what removes the interference and why no observer is required.

  11. Question 11.Calculation

    Green laser light of wavelength 532 nm passes through two slits 0.10 mm apart. Find the fringe spacing on a screen 1.5 metres away, and the distance from the central bright fringe to the third bright fringe.

    This one asks for more than one value — give each, with its units.

  12. Question 12.Calculation

    A student shines a 633 nm helium-neon laser through an unknown double slit onto a wall 2.5 metres away and measures 40 mm from the central bright fringe to the tenth bright fringe on one side. What is the slit separation?

    Give a number and units. 6.63×10⁻³⁴, 6.63e-34 and 6.63 x 10^-34 all work.

  13. Question 13.Calculation

    In Tonomura's experiment, 50,000-volt electrons travel at about 1.24×10⁸ m/s, roughly 41 percent of the speed of light, and arrive at about 1,000 per second. Find the average distance between successive electrons, the time each spends crossing the 1.5-metre instrument, and the fraction of the time that any electron is inside it.

    This one asks for more than one value — give each, with its units.

  14. Question 14.Calculation

    At one point on a screen, slit 1 alone gives a probability density of 4 units and slit 2 alone gives 1 unit. With both slits open and nothing recording the path, find the largest and smallest possible values, the bullet-rule value, and the fringe visibility. What is the largest distinguishability a which-path detector could then have without lowering the visibility below this value?

    This one asks for more than one value — give each, with its units.

Part C · optional, dangerous, extremely rewarding

Mad scientist challenge

Feynman's lamp. Electrons of 600 eV (wavelength 50.1 pm) pass two slits 272 nm apart and land on a screen 1.0 metre away. (a) Find the fringe spacing and the angle between neighbouring fringes. (b) To see which slit each electron uses, you scatter light off it; roughly, light can tell the slits apart only if its wavelength is shorter than the slit separation. Using 200 nm ultraviolet light, estimate the sideways kick a scattered photon can give an electron, as an angle, and the resulting smear on the screen. Do the fringes survive? (c) Repeat for gentle 1,000 nm infrared light. Can that light tell the slits apart? (d) Show that the ratio of kick angle to fringe angle is simply d divided by the light's wavelength, and explain why this makes Feynman's lamp a no-win device. (e) Why do physicists now say the kick is not the deepest reason the fringes vanish?

12Wrap-up

Recap & sign-off

Key takeaways

  • Feynman's comparison: bullets arrive in lumps and their probabilities add, waves interfere; electrons do both, arriving as lumps but distributing like waves
  • Sent one at a time, in Bologna (1974), at Hitachi (1989) and in Nebraska (2013), each particle lands whole as one dot, and the stripes are the statistics of many independent dots
  • Bright fringes fall where d sin θ = mλ, spaced by Δy ≈ λL/d: wider with longer wavelengths and screen distances, narrower with wider slit separations
  • For indistinguishable paths, add the amplitudes, then square: |ψ₁ + ψ₂|² ≠ |ψ₁|² + |ψ₂|², and with equal slits the cross term makes bright fringes four times one slit's value and dark fringes of zero
  • Which-path information destroys fringes in proportion to how well it could distinguish the paths: D² + V² ≤ 1, Bohr's complementarity made quantitative
  • The culprit is entanglement with any marker or environment, even a stray photon nobody detects; no conscious observer and no readout are required
  • Quantum erasers and delayed-choice experiments recover fringes only in subsets sorted by partner results; the unsorted pattern never changes, so nothing is sent to the past or anywhere else
Dr. Q signs off

So the electron is neither bullet nor ripple: it lands like a lump and adds like a wave, and the moment the universe keeps a receipt for its path, the stripes are gone. Science is the only madness with receipts! Next session we chase Feynman's lamp to the bottom. Why can no one know the path and keep the stripes? Why can nothing be pinned down perfectly? Werner Heisenberg has an answer, and it is not clumsy instruments. Dr. Q, signing off.

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