Unit 1 · The Classical World CracksChapter 3 of 25

Blackbody Radiation & Planck's Desperate Act

The ultraviolet catastrophe, and the 1900 guess that started a revolution

  • 21 min read
  • 31 min listen
  • 16 videos
01Video briefing

Start with the preview

Start here — today's preview. Watch “Quantization of Energy Part 1: Blackbody Radiation and the Ultraviolet Catastrophe” from Professor Dave Explains before (or after) this session. The lab will wait. Mostly.

Today's preview

Quantization of Energy Part 1: Blackbody Radiation and the Ultraviolet Catastrophe

Professor Dave Explains7 min

A crisp seven-minute overview of this whole session: why hot objects glow, how the blackbody curve changes shape as the temperature rises, how the classical prediction runs off to infinity at short wavelengths, and how Planck's energy packets bring it back down. Short explainers compress the history, so let Parts 5 and 8 of the lesson tell you what Planck was actually trying to do. Some sources write frequency with the Greek letter nu, ν, instead of f; E = hν and E = hf are the same equation.

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More from the video vault

Deep dive

What is the Ultraviolet Catastrophe?

Physics Explained40 min

A patient forty-minute derivation that covers the ground of Parts 4 to 7 of this lesson in mathematical detail: the classical calculation of the radiation in a hot cavity, the moment it diverges, and Planck's way out using discrete energies and Boltzmann's statistics. Best watched after the lesson, with a pencil and paper.

Watch on YouTube
Bonus

Why are there no Purple Stars? or Green Stars?

The Science Asylum9 min

Nick Lucid explains why star colours run from red through white to blue but skip green and purple: a blackbody spectrum is so broad that, by the time its peak sits in the green, your eye is receiving every colour at once. A perfect companion to Part 3.

Watch on YouTube
  • Quantization of Energy Part 1: Blackbody Radiation and the Ultraviolet Catastrophe — Professor Dave Explains — https://www.youtube.com/watch?v=7BXvc9W97iU
  • What is the Ultraviolet Catastrophe? — Physics Explained — https://www.youtube.com/watch?v=rCfPQLVzus4
  • Why are there no Purple Stars? or Green Stars? — The Science Asylum — https://www.youtube.com/watch?v=7RPE-_eFBOw
02Cold open

Today's mission

Dr. Q · cold open

Goggles down, Psigor, and crank the furnace! Watch the iron bar on the anvil. First it glows a sullen red, then cherry, then orange, and as I pour in more power it blazes yellow and finally white. Blacksmiths have read temperature from that sequence for thousands of years, yet in 1900 the finest physics on Earth could not explain it. Worse, when theorists finally did the sums with full classical rigour, they predicted that a furnace like this should pour out unlimited ultraviolet light, X-rays and gamma rays: infinite energy from a hot box. Great Planck's ghost! Today you will see exactly why that prediction failed, and why the cure had already been found, in 1900, by a cautious professor in Berlin with an idea he did not want to believe.

By the end of this session you will be able to:

  1. Define a blackbody and explain why its glow depends only on its temperature, using stove elements, stars and the cosmic microwave background as examples
  2. Use Wien's displacement law and the Stefan-Boltzmann law to find peak wavelengths, temperatures and radiated power
  3. Read a star's temperature from its colour, and explain why white-hot is hotter than red-hot
  4. Explain how counting standing-wave modes and giving each one kT produces the Rayleigh-Jeans law and its ultraviolet catastrophe
  5. State Planck's hypothesis E = n·hf and explain how the Boltzmann factor freezes out high-frequency modes
  6. Describe what Planck did, and did not, claim in 1900, and why he called it an act of desperation
03The lesson

Read it — or listen along

8 parts. Press play on any part and the paragraph being read lights up as Dr. Q speaks.

Part 1

Black in Name Only: The Perfect Absorber

Everything warmer than absolute zero glows. The atoms in any material jiggle with thermal motion, their charged parts oscillate as they do, and oscillating charges launch the electromagnetic waves of Chapter 2. The result is thermal radiation: light emitted simply because an object is warm. You are glowing right now, at wavelengths near 10 micrometres in the infrared, invisible to your eyes. How much an ordinary object emits, and at which wavelengths, depends on its material and surface finish, which makes a general theory look hopeless. In 1859 Gustav Kirchhoff found the way through: in thermal equilibrium, meaning a single steady temperature with no net exchange of energy, a surface that absorbs a wavelength well must emit it equally well.

So consider the best absorber imaginable. In 1860 Kirchhoff named it a black body, now usually written blackbody: an idealized object that absorbs all electromagnetic radiation falling on it, at every wavelength and angle. In equilibrium it out-glows any other body at the same temperature, and its spectrum depends on that temperature alone; material and shape drop out. A cavity with a tiny hole comes remarkably close, because light entering the hole is absorbed before it can bounce back out; Otto Lummer and Ferdinand Kurlbaum built an electrically heated one in Berlin in 1898. A glowing stove element is a decent blackbody, the Sun's surface a good one, and the cosmic microwave background, the afterglow of the hot early universe detected by Arno Penzias and Robert Wilson in 1964, the best ever measured. Black describes absorption, not appearance: a hot blackbody can be dazzling.

Watch this part

Part 2

Two Laws Written in Fire: Wien and Stefan-Boltzmann

Plot a blackbody's output against wavelength and you get a lopsided hump. The height of the curve is the spectral radiance: the power emitted per square metre of surface, per unit of solid angle (a measure of a cone of directions), per metre of wavelength. Heat the body and two things happen at once: the curve swells at every wavelength, and its peak slides towards shorter wavelengths. The slide is Wien's displacement law, derived by Wilhelm Wien in 1893: λₘₐₓ·T = b ≈ 2.898×10⁻³ m·K, with T the absolute temperature, so peak wavelength and temperature are inversely proportional. Your skin, near 306 K, peaks around 9.5 μm, which is why thermal cameras look between 8 and 14 μm. The Sun, at 5,772 K, peaks near 502 nm, and the cosmic microwave background, at 2.725 K, near 1.06 mm, squarely in the microwave band.

The swelling is the Stefan-Boltzmann law. Josef Stefan extracted it from measurements in 1879, and his former student Ludwig Boltzmann derived it from thermodynamics and Maxwell's theory in 1884: the total power radiated is P = εσA·T⁴. Here A is the surface area, σ = 5.670×10⁻⁸ W/(m²·K⁴) is the Stefan-Boltzmann constant, and ε, the emissivity, measures how closely a real surface approaches the ideal, from 0 for a perfect mirror to exactly 1 for a blackbody. The fourth power is ferocious: double the absolute temperature and the power rises sixteenfold. A surface at 798 K, just hot enough to glow visibly, radiates about 23 kilowatts per square metre; each square metre of the Sun's surface radiates about 63 million watts.

Watch this part

Part 3

Reading Temperature in Colour: Embers, Bulbs and Stars

Heat an iron poker in a dark room and it stays invisible until about 798 K, or 525 degrees Celsius, the Draper point, measured by John William Draper in 1847. Even then the peak sits near 3.6 μm in the infrared; you see only the faint short-wavelength tail of the curve spilling into the red end of the visible band, which runs from about 380 to 750 nm. Heat it further and the curve adds orange and then yellow, until the visible band is filled fairly evenly and the eye reports white. That settles a stubborn myth: white-hot is hotter than red-hot. Red is merely the first glow of a body barely hot enough to shine; lighting catalogues even invert the physics when they call reddish light warm and bluish light cool. The same curve doomed the incandescent bulb: a tungsten filament near 2,800 K peaks around 1.0 μm, and a blackbody at that temperature puts only about 8 per cent of its output into the visible band.

The colour sequence turns every star into a thermometer light-years away. Betelgeuse, the orange-red shoulder of Orion, has a surface temperature of about 3,600 to 3,800 K, depending on the study, and peaks near 780 nm, at the edge of the infrared. The Sun, at 5,772 K, looks white from space. Sirius, at about 9,800 K, peaks near 295 nm in the ultraviolet and shines blue-white, and Rigel, at about 12,000 K, is bluer still. These are effective temperatures: the temperature of a blackbody of the same size that would radiate the same total power. Astronomers estimate them for millions of stars simply by comparing each star's brightness through blue and yellow filters.

Watch this part

Part 4

Counting Waves in a Hot Box: The Rayleigh-Jeans Law

Now for an explanation. Radiation inside a hot cavity bounces between the walls, and, just as on the guitar string of Chapter 2, only waves that fit survive as standing waves. Each allowed standing-wave pattern is called a mode, and the cavity's radiation is the sum of all its modes. Counting them is pure geometry. In three dimensions, the number of distinct patterns with frequencies below f grows like the volume of a sphere whose radius is proportional to f, that is, as f³. The number of modes in a narrow frequency window therefore grows as f². Including light's two independent polarizations, the count is 8πf²/c³ modes per unit volume per unit frequency. Double the frequency and four times as many modes crowd into each window, and there is no highest-frequency mode at all.

The energy per mode comes from classical statistical mechanics, the theory Maxwell and Boltzmann built to explain heat as random motion. Its equipartition theorem states that in thermal equilibrium every independent quadratic energy term, kinetic or potential, holds on average kT/2, where k = 1.381×10⁻²³ joules per kelvin is Boltzmann's constant. An oscillator stores energy both in motion and in stretch, so it averages kT, and every cavity mode is an oscillator. At room temperature kT is about 4.1×10⁻²¹ joules, or 0.026 electron-volts (eV), where one electron-volt is 1.602×10⁻¹⁹ joules. Multiply the mode count by kT and you have the Rayleigh-Jeans law. Lord Rayleigh argued in June 1900 that long-wavelength radiation should grow as T/λ⁴, and in 1905 he and James Jeans completed the classical formula.

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Part 5

The Ultraviolet Catastrophe

Follow the Rayleigh-Jeans law towards short wavelengths and disaster unfolds. The modes keep multiplying and each still holds kT, so the predicted spectrum climbs without limit through the ultraviolet, X-ray and gamma-ray bands instead of falling to zero, and the total energy, summed over infinitely many modes, is infinite. Taken literally, radiation would drain energy from the walls into ever shorter wavelengths forever. In 1911 Paul Ehrenfest named this the ultraviolet catastrophe; Rayleigh, Jeans and Albert Einstein had each recognized the divergence by 1905. Measure how wrong it is for a body at the Sun's temperature: at 10 μm the classical prediction is only 14 per cent too high, at 500 nm it is 29 times too high, and at 100 nm about 2.7 billion times too high.

Notice the shape of the failure. Classical physics is excellent where wavelengths are long and frequencies low, and fails ever more absurdly as frequency rises. This was no slip in arithmetic: Maxwell's electromagnetism, the mode count and Boltzmann's statistics each had a long record of success, although equipartition had already stumbled over the heat capacities of gases. One assumption had to give, and the culprit was hidden inside equipartition: that an oscillator can hold any amount of energy whatsoever, however small.

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Part 6

Planck's Desperate Act

Max Planck, born in Kiel in 1858 and a professor at the University of Berlin, was a master of thermodynamics and a conservative scientist who had long distrusted Boltzmann's statistical methods. In 1899 he championed Wien's formula. Then measurements in Berlin, first by Otto Lummer and Ernst Pringsheim and then, deeper in the infrared, by Rubens and Kurlbaum, showed it failing at long wavelengths. On Sunday 7 October 1900 Rubens visited Planck and told him that at long wavelengths the radiation grew in proportion to temperature. That evening, by the familiar account, Planck found a formula blending both behaviours. He presented it to the German Physical Society on 19 October, and Rubens soon confirmed that it fitted his measurements at every wavelength.

A formula that fits is not yet physics. To derive it, Planck took what he later called an act of desperation: he adopted Boltzmann's method, in which entropy counts the number of ways energy can be shared among many oscillators. Counting requires countable pieces, so Planck divided the energy of the hypothetical charged oscillators he pictured in the cavity walls, which he called resonators, into finite energy elements. To agree with his formula and with Wien's displacement law, each element had to be proportional to frequency, equal to hf. Read as a physical rule, which is how his successors came to understand it, this means an oscillator of frequency f can hold only 0, hf, 2hf, 3hf and so on: E = n·hf, with n a whole number. He presented the derivation to the Society on 14 December 1900, often called the birthday of quantum theory.

Planck immediately put a number on his new constant. From the Stefan-Boltzmann and Wien constants as measured at the time, he obtained h = 6.55×10⁻³⁴ J·s, about 1 per cent below today's exact value of 6.62607015×10⁻³⁴ J·s, and k = 1.346×10⁻²³ joules per kelvin, within 3 per cent of the modern figure. He was the first to evaluate this constant, which now carries Boltzmann's name although Boltzmann never introduced it, and from it he calculated Avogadro's number and the electron's charge. The worksheet's mad scientist challenge lets you repeat his calculation.

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Part 7

How Packets Tame the Ultraviolet

The key is a rule from Boltzmann's statistics. In thermal equilibrium at temperature T, a state with energy E occurs with relative probability e^(−E/kT), the Boltzmann factor: states costing a few kT are common, and states costing a hundred kT absurdly rare. Classically a mode can hold any energy, however small, so every mode averages kT. With Planck's rule the smallest energy above zero is one packet, hf, and everything hinges on comparing hf with kT. When hf is much smaller than kT, the steps are so fine that the ladder behaves like a ramp, the mode averages almost exactly kT, and Planck's law reproduces Rayleigh-Jeans and the infrared data. When hf is much larger than kT, even one packet is a huge thermal expense, the chance of holding one is about e^(−hf/kT), and the mode almost always sits empty.

Averaging over the ladder gives the mean energy per mode, ⟨E⟩ = hf/(e^(hf/kT) − 1), which slides smoothly from kT down to essentially nothing. There are still infinitely many modes, but the high-frequency ones are frozen out exponentially faster than their number grows, so the total is finite and the curve turns over. At room temperature a green-light packet costs about 96 times kT, and its Boltzmann factor, about 2×10⁻⁴², is why your coffee mug does not glow green; at the Sun's surface the ratio is about 5, and visible modes are well stocked. Planck's law also contains all four earlier results: at long wavelengths it becomes the Rayleigh-Jeans law, at short ones Wien's 1896 formula; its peak gives λₘₐₓ·T = hc/(4.965·k) = 2.898×10⁻³ m·K, and its total gives σT⁴ with σ = 2π⁵k⁴/(15·c²·h³).

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Part 8

The Reluctant Revolutionary

It is often said that Planck discovered that light is made of particles. He did not. He quantized the energy of his wall oscillators as a counting device and treated the radiation as Maxwell's continuous waves. Writing to the American physicist Robert Williams Wood in 1931, he called the step a purely formal assumption, made because he had to obtain a positive result whatever the cost. Historians still debate how literally he meant it; Thomas Kuhn argued in 1978 that Planck did not regard the discontinuity as physical until years later. Others took the packets more seriously than their inventor. In 1905 Einstein proposed that light itself consists of quanta of energy hf, the subject of the next chapter, and Planck resisted: as late as 1911 and 1912 he devised a theory in which oscillators absorbed energy continuously and emitted it only in quanta.

In 1913, recommending Einstein for the Prussian Academy of Sciences, Planck and three colleagues wrote that Einstein “may sometimes have missed the target in his speculations, as, for example, in his hypothesis of light quanta.” Planck nevertheless received the 1918 Nobel Prize in Physics, awarded in 1919, for his discovery of energy quanta, and since 20 May 2019 his constant has defined the kilogram: the SI fixes h at exactly 6.62607015×10⁻³⁴ J·s. Planck wanted to preserve classical physics, not overthrow it, but he followed the data and the mathematics where they led and published what he found. A revolution does not require an eager revolutionary, only an honest one.

Watch this part

04Video shelf

Go deeper on video

13 more videos for this chapter, 8 of them from universities, research institutes and Nobel lectures. The clips under “Watch this part” in the lesson start at the moment that matters.

13 videos · 4 h 58 min

  • Demo · Harvard

    Blackbody Radiation Oven

    Harvard Natural Sciences Lecture Demonstrations

    Harvard's lecture-demonstration team illustrates this section's central claim: blackbody radiators in thermal equilibrium should all emit the same spectrum, and the demo looks inside an oven at high temperature to see it. Watch with Kirchhoff's rule in mind: once everything shares one temperature, material and surface finish stop mattering.

  • Lecture · MIT

    18. Cosmic Microwave Background Spectrum and the Cosmological Constant, Part I

    MIT OpenCourseWare · Alan Guth

    From MIT 8.286 The Early Universe (Fall 2013), the story behind this section's satellite callout: from 23:17 Alan Guth goes from Penzias and Wilson's single frequency to a 1987 rocket result well above the blackbody curve, then to COBE (32:12), its 1990 preprint and the standing ovation for John Mather. At 36:37 he turns to the spectrum's shape, writes it per unit frequency (38:51) and at 40:00 notes the extra factor needed per unit wavelength, section 2's warning in action; the segment ends near 42:40, and the rest of the lecture is about the cosmological constant.

  • Demo · The Ohio State University

    Blackbody Radiation - Stefan-Boltzmann & Wien Laws

    Astronomy 1101: From Planets to the Cosmos Online · Richard Pogge

    A short demonstration of blackbody radiation and of both laws in this section, recorded in 2015 by the Ohio State astronomer Richard Pogge for his Astronomy 1101 course. It has chapters for 'Heating' (0:37) and 'Fade' (1:45); as the source heats and cools, look for both laws together: total output changing steeply with temperature (T⁴), and the colour shifting as the peak moves.

  • Explainer · YouTube

    The Color Temperature Paradox

    minutephysics

    A four-minute minutephysics short on colour temperature, the topic behind this section's aside that lighting catalogues call reddish light 'warm' and bluish light 'cool', although on the blackbody scale red marks the cooler body and blue the hotter one. Watch it with that inversion in mind, then check it against this section's Draper point and tungsten-bulb figures.

  • Explainer · YouTube

    I wish I was taught the birth of Quantum Mechanics this way!

    FloatHeadPhysics

    Mahesh Shenoy builds the Rayleigh-Jeans law by intuition rather than algebra, the same route as this section: standing waves (2:50), Jeans's cube of modes (5:30), the equipartition theorem (9:32), applying it to light (14:35) and counting modes in 3D (16:19). It ends with the ultraviolet catastrophe (18:24), a natural bridge into section 5; rewind to 1:11 for the motivation.

  • Explainer · YouTube

    The ULTRAVIOLET CATASTROPHE

    Physics Girl

    Dianna Cowern's short, friendly account of the Rayleigh-Jeans catastrophe; the start time skips the blackbody intro (0:23) and goes straight to the 'Ultraviolet Catastrophe' chapter, and the final chapter (4:49) jumps ahead to probability clouds. If it presents Planck as setting out to cure the catastrophe, keep this section's history callout in mind: the catastrophe was clearly diagnosed only after Planck's work.

  • Explainer · YouTube

    Max Planck Quantum Theory

    Kathy Loves Physics

    Kathy Loves Physics tells the story of 1900 in Planck's own words, which suits this section's history: Planck and Wien's law (1:47), statistical mechanics and the second law (3:48, 4:50), Boltzmann (6:12) and the quantum of energy (8:12). Notice that her chapter on the ultraviolet catastrophe (8:48) comes after the quantum, not before, and that Einstein enters at 9:43.

  • Explainer · YouTube

    We finally understood where the Planck's constant actually comes from! (My mind is blown)

    FloatHeadPhysics

    Picks up where the Rayleigh-Jeans video above leaves off, starting at the question 'which classical assumption is wrong?' (4:40). Mahesh Shenoy works out a 'new partition theorem' to replace equipartition (6:22, 8:47), shows how quantization fixes the catastrophe (11:04) and arrives at E = hf (16:23): the intuitive version of this section's freeze-out argument. The 'final challenge' at 21:46, why the peak shifts with temperature, links back to Wien's law in section 2.

  • Lecture · UNSW Sydney

    PHYS 3113 Lecture 14 - Blackbody radiation

    UNSW Physics

    From UNSW Sydney's PHYS 3113 Thermal Physics and Statistical Mechanics, the lecture right after one on the statistical mechanics of the harmonic oscillator, which applies that machinery to radiation, working with the partition function of a single mode. It is the statistical-mechanics route to this section's ⟨E⟩ = hf/(e^(hf/kT) − 1), for the deeper learner; keep the lesson's equations beside you.

  • Lecture · Kavli Institute for Theoretical Physics

    The Historical Max Planck ▸ by Brandon Brown

    Kavli Institute for Theoretical Physics · Brandon Brown

    A talk at KITP by the physicist Brandon Brown, author of the biography 'Planck: Driven by Vision, Broken by War', on Planck the historical figure rather than Planck the formula. Use it to put a person behind this section: a conservative master of thermodynamics who still published what the data forced on him.

  • Explainer · Perimeter

    Quantization Explained | Perimeter Institute for Theoretical Physics

    Perimeter Institute for Theoretical Physics · Katie Mack · 2023

    A short episode from Perimeter Institute's Quantum 101 series with Katie Mack. Watch it alongside Chapter 3.

  • Lecture · Royal Institution

    A Brief History of Quantum Mechanics - with Sean Carroll

    The Royal Institution · Sean Carroll · 2020

    Sean Carroll tells the story from Planck and Einstein through Bohr, de Broglie and Schrödinger, then argues that the measurement problem is still open and makes his case for the many-worlds interpretation. Notice where the history ends and his interpretation begins.

  • Series · Perimeter

    Quantum 101

    Perimeter Institute for Theoretical Physics · Katie Mack · 2023

    Ten five-minute episodes hosted by the cosmologist Katie Mack: duality, quantization, uncertainty, superposition, entanglement, probability, tunnelling and quantum computing. The friendliest possible on-ramp, and a quick refresher before any chapter.

Every video for Chapter 3 in the Video Library

05To the blackboard

Key equations

Equation 1

Wien's displacement law

λmax⁡ T=b≈2.898×10−3 m⋅K\lambda_{\max}\, T = b \approx 2.898 \times 10^{-3}\ \text{m}\cdot\text{K}

The peak wavelength of a blackbody spectrum, plotted per unit wavelength, is inversely proportional to the absolute temperature. Hotter bodies peak at shorter wavelengths, so measuring the peak measures the temperature.

What each symbol means
SymbolMeaningUnit
λₘₐₓwavelength at which the spectrum peaksm
Tabsolute temperatureK
bWien's displacement constant, 2.897771955×10⁻³m·K

Say it: “lambda max times T equals b, which is approximately 2.898 times ten to the minus 3 metre-kelvin”

Equation 2

The Stefan-Boltzmann law

P=ε σAT4,σ≈5.670×10−8 W m−2 K−4P = \varepsilon\, \sigma A T^{4}, \qquad \sigma \approx 5.670 \times 10^{-8}\ \text{W}\,\text{m}^{-2}\,\text{K}^{-4}

The total power radiated by a hot surface grows as the fourth power of its absolute temperature, so doubling T multiplies the power by sixteen. The emissivity epsilon is exactly 1 for a blackbody and less than 1 for real surfaces.

What each symbol means
SymbolMeaningUnit
Ptotal radiated powerW
εemissivity, from 0 (perfect mirror) to 1 (blackbody)dimensionless
σStefan-Boltzmann constant, 5.670374419×10⁻⁸W/(m²·K⁴)
Aradiating surface aream²
Tabsolute temperatureK

Say it: “P equals epsilon sigma A T to the fourth, where sigma is approximately 5.670 times ten to the minus 8 watts per square metre per kelvin to the fourth”

Equation 3

The Rayleigh-Jeans law

BλRJ(T)=2 c kTλ4B_\lambda^{\text{RJ}}(T) = \frac{2\, c\, k T}{\lambda^{4}}

The classical prediction: count the cavity modes and give each one an average energy kT. It matches experiment at long wavelengths but grows without limit as the wavelength shrinks, which is the ultraviolet catastrophe.

What each symbol means
SymbolMeaningUnit
B_λspectral radiance: power per area, per solid angle, per wavelength intervalW·sr⁻¹·m⁻³
cspeed of light, 299,792,458 (exact)m/s
kBoltzmann constant, 1.380649×10⁻²³ (exact), often written k_BJ/K
Tabsolute temperatureK
λwavelengthm

Say it: “B lambda, Rayleigh-Jeans, of T equals two c k T over lambda to the fourth”

Equation 4

Planck's quantum hypothesis

En=n hf,n=0,1,2,3,…E_n = n\, h f, \qquad n = 0, 1, 2, 3, \ldots

An oscillator of frequency f can hold energy only in whole packets of size hf. Planck introduced energy elements of size hf in December 1900, as a way of counting how energy is shared among the oscillators in the cavity walls; read as a physical rule, they give this ladder of allowed energies.

What each symbol means
SymbolMeaningUnit
Eₙallowed energy of the oscillatorJ
nnumber of packets: a whole numberdimensionless
hPlanck's constant, 6.62607015×10⁻³⁴ (exact)J·s
foscillator frequencyHz

Say it: “E sub n equals n times h f, where n is zero, one, two, three, and so on”

Equation 5

Average energy of a mode

⟨E⟩=hfehf/kT−1≈{kT,hf≪kThf e−hf/kT,hf≫kT\langle E \rangle = \frac{hf}{e^{hf/kT} - 1} \approx \begin{cases} kT, & hf \ll kT \\ hf\, e^{-hf/kT}, & hf \gg kT \end{cases}

Planck's packets combined with Boltzmann's statistics. Low-frequency modes receive the classical kT, while high-frequency modes are frozen out exponentially, which removes the ultraviolet catastrophe.

What each symbol means
SymbolMeaningUnit
⟨E⟩mean energy of one mode in thermal equilibriumJ
hfsize of one energy packetJ
kTthermal energy scale; about 0.026 eV at 300 KJ

Say it: “the average energy equals h f divided by, e to the power h f over k T, minus one. It is about k T when h f is much smaller than k T, and about h f times e to the minus h f over k T when h f is much larger”

Equation 6

Planck's radiation law

Bλ(T)=2hc2λ5 1ehc/λkT−1B_\lambda(T) = \frac{2 h c^{2}}{\lambda^{5}}\, \frac{1}{e^{hc/\lambda k T} - 1}

The true blackbody spectrum, which fits every measurement. At long wavelengths it reduces to the Rayleigh-Jeans law; its peak gives Wien's displacement law, and its total over all wavelengths gives the Stefan-Boltzmann law.

What each symbol means
SymbolMeaningUnit
B_λspectral radianceW·sr⁻¹·m⁻³
hPlanck's constantJ·s
cspeed of lightm/s
λwavelengthm
kBoltzmann constantJ/K
Tabsolute temperatureK

Say it: “B lambda of T equals two h c squared over lambda to the fifth, times one over, e to the power h c over lambda k T, minus one”

06Worked examples

Real numbers, step by step

Cover the steps, try the problem yourself, then reveal the solution one step at a time.

Example 1

Taking the Sun's temperature from 150 million kilometres

Problem

A blackbody fitted to sunlight peaks at a wavelength of 502 nm. The Sun's radius is 6.957×10⁸ metres. Estimate the Sun's surface temperature and its total power output, then check the result against the sunlight arriving at Earth, 1.496×10¹¹ metres away.

  1. Step 1: Wien's law: T = b ÷ λₘₐₓ = (2.898×10⁻³ m·K) ÷ (5.02×10⁻⁷ metres) ≈ 5,773 K.

  2. Step 2: Power per square metre, from the Stefan-Boltzmann law with ε = 1: σT⁴ = 5.670×10⁻⁸ × (5,773)⁴ ≈ 6.30×10⁷ watts per square metre.

  3. Step 3: Surface area of the Sun: A = 4πR² = 4π × (6.957×10⁸)² ≈ 6.08×10¹⁸ square metres.

  4. Step 4: Total power: L = σT⁴ × A ≈ 6.30×10⁷ × 6.08×10¹⁸ ≈ 3.83×10²⁶ watts.

  5. Step 5: Spread that power over a sphere of radius 1.496×10¹¹ metres: 3.83×10²⁶ ÷ (4π × (1.496×10¹¹)²) ≈ 1,360 watts per square metre.

Answer

About 5,770 K and 3.83×10²⁶ watts, delivering about 1,360 watts per square metre at Earth's distance

Why it matters: Satellites measure about 1,361 watts per square metre at the top of Earth's atmosphere, and the accepted solar luminosity is 3.828×10²⁶ watts. One colour measurement, two blackbody laws and a known distance weigh the output of a star.

Try it yourself first — then check each step.
Example 2

Sirius versus the Sun

Problem

Sirius A has a surface temperature of about 9,845 K and a radius 1.714 times the Sun's. Taking the Sun's temperature as 5,772 K, find how many times more power Sirius A radiates, and where its spectrum peaks.

  1. Step 1: Treat both as blackbodies, so the power is σ × 4πR² × T⁴. In the ratio, σ and 4π cancel: L(Sirius) ÷ L(Sun) = (radius ratio)² × (temperature ratio)⁴.

  2. Step 2: Radius factor: 1.714² ≈ 2.94.

  3. Step 3: Temperature factor: (9,845 ÷ 5,772)⁴ = 1.706⁴ ≈ 8.46.

  4. Step 4: Multiply: 2.94 × 8.46 ≈ 24.9.

  5. Step 5: Peak: λₘₐₓ = b ÷ T = 2.898×10⁻³ ÷ 9,845 ≈ 2.94×10⁻⁷ metres, or 294 nm.

Answer

About 25 times the Sun's power, with the spectrum peaking near 294 nm in the ultraviolet

Why it matters: Measurements put Sirius A at about 25 solar luminosities. Its temperature is only 1.7 times the Sun's, yet that alone multiplies the output of every square metre by more than 8: the fourth power at work. A peak in the ultraviolet, with plenty of blue on the visible side, is why Sirius looks blue-white.

Try it yourself first — then check each step.
Example 3

Why your coffee mug does not glow green

Problem

Compare the cost of one energy packet at the frequency of green light, wavelength 500 nm, with the thermal energy kT at room temperature, 300 K, and at the Sun's surface, 5,772 K. Use the Boltzmann factor e^(−hf/kT) to judge how likely a mode is to hold even one packet.

  1. Step 1: Packet size: hf = hc ÷ λ = (6.626×10⁻³⁴ J·s × 2.998×10⁸ m/s) ÷ (5.00×10⁻⁷ metres) ≈ 3.97×10⁻¹⁹ joules, about 2.48 eV.

  2. Step 2: Room temperature: kT = 1.381×10⁻²³ × 300 ≈ 4.14×10⁻²¹ joules, about 0.0259 eV. The ratio hf ÷ kT ≈ 96, so the Boltzmann factor is e^(−96) ≈ 2×10⁻⁴².

  3. Step 3: Sun's surface: kT ≈ 7.97×10⁻²⁰ joules, about 0.497 eV. Now hf ÷ kT ≈ 4.99, and e^(−4.99) ≈ 0.0068, about 1 in 150.

Answer

At room temperature the odds of a green-light mode holding a packet are about 2×10⁻⁴²; at the Sun's surface they are about 1 in 150

Why it matters: Raising the temperature about nineteenfold improved the odds by a factor of about 3×10³⁹. That exponential sensitivity is why objects begin to glow fairly suddenly once they are hot enough, and why the high-frequency modes that doomed classical physics simply stay empty.

Try it yourself first — then check each step.
Example 4

Measuring the catastrophe

Problem

For a blackbody at 5,772 K, the ratio of the Rayleigh-Jeans prediction to Planck's law at any wavelength is (e^x − 1) ÷ x, where x = hc ÷ (λkT). Evaluate it at 10 μm, 500 nm and 100 nm, using hc ÷ k = 1.439×10⁻² m·K.

  1. Step 1: At 10 μm: x = 1.439×10⁻² ÷ (1.0×10⁻⁵ × 5,772) ≈ 0.249, so the ratio is (e^0.249 − 1) ÷ 0.249 ≈ 1.14.

  2. Step 2: At 500 nm: x = 1.439×10⁻² ÷ (5.0×10⁻⁷ × 5,772) ≈ 4.99, so the ratio is (e^4.99 − 1) ÷ 4.99 ≈ 29.

  3. Step 3: At 100 nm: x ≈ 24.9, so the ratio is about e^24.9 ÷ 24.9 ≈ 2.7×10⁹.

Answer

The classical prediction is 14 per cent too high at 10 μm, about 29 times too high at 500 nm, and about 2.7 billion times too high at 100 nm

Why it matters: When x is small the ratio approaches 1, so classical physics works wherever hc/λ is much smaller than kT. When x is large the ratio explodes exponentially. The catastrophe lives entirely at high frequency.

Try it yourself first — then check each step.
07Myth busters

What everyone gets wrong

Read the myth, decide whether you believed it, then bust it.

  • Myth #1

    Red-hot is hotter than white-hot.

    Truth

    It is the reverse. Red is the first visible glow, appearing near 800 K, when the peak is still deep in the infrared and only the curve's short-wavelength tail reaches the red end of the visible band. As the temperature rises, the peak moves to shorter wavelengths and more of the visible band fills in, giving orange, yellow and finally white, the sign of the hotter object. Blue-white stars are hotter still.

  • Myth #2

    In 1900 Planck believed that light itself was made of particles.

    Truth

    Planck quantized the energy of hypothetical charged oscillators in the cavity walls, as a counting device, and treated light as Maxwell's continuous waves. Einstein proposed light quanta in 1905, and Planck resisted the idea for years, writing in 1913 that Einstein may have missed the target with it.

  • Myth #3

    A blackbody is a cold, dark object.

    Truth

    Black refers to perfect absorption, not to appearance. A hot blackbody glows brilliantly: the Sun is a good approximation to one, and a cavity with a small hole glows white when it is heated enough.

08Interactive lab

Your turn at the controls

Welcome to the Blackbody Furnace, my favourite piece of equipment that has never once exploded. One slider sets the temperature anywhere from 300 K, a warm room, to 30,000 K, as hot as the surface of a fierce blue star, and the screen redraws the Planck spectrum live, on a linear or a logarithmic wavelength axis. A marker tracks the Wien peak, the furnace window shows the colour your eye would see, the readouts give the peak wavelength and the power compared with the Sun's surface, and a line beneath the graph gives the power radiated from each square metre. Flip on the classical overlay to see what Rayleigh and Jeans predicted. Then play Star Matcher.

Your tasks

0/5

How it connects to the theory

Each part of the screen is a piece of the lesson. The bright curve is Planck's radiation law; the dashed red curve is the Rayleigh-Jeans law, 2ckT/λ⁴, which hugs Planck's curve at long wavelengths, where hc/λ is much smaller than kT, and parts company where it is not. The peak marker is Wien's law, λₘₐₓ = b/T, so Star Matcher is Wien's law run backwards: T = b/λₘₐₓ. The power figures are the Stefan-Boltzmann law: σT⁴ for each square metre, and (T ÷ 5,772 K)⁴ for the comparison with the Sun, which is why both multiply by 16 every time you double T. The furnace window shows the visible slice of the curve, weighted by the eye's three colour sensitivities and blended into one colour: red when only the curve's short-wavelength tail reaches the red end of the visible band, white when the band is filled fairly evenly, and bluish white once the peak has moved into the ultraviolet. A 5 per cent tolerance in temperature is very nearly a 5 per cent tolerance in peak wavelength, because the two are inversely proportional. And the reason the Planck curve falls at short wavelengths, instead of climbing like the classical one, is the Boltzmann factor: there, each packet hf costs far more than kT.

Blackbody Furnace: Heat It Until It Glows loads as you scroll down.

Win the challenge to tick “lab won” on your chapter checklist.
Open full-screen lab
09Memory aids

Make it stick

Memory trick

Wien shifts, Stefan soars, Planck prices; red is the warm-up, white is the blaze. Picture a furnace with three gauges. Turn up the heat and Wien shifts the peak to shorter wavelengths, λₘₐₓ = b/T. Stefan soars: the power climbs as T⁴. Planck prices: every packet of energy at frequency f costs hf, while the thermal budget is only about kT, so high frequencies are priced out of reach. On any blackbody problem, recite the three in order. Shift finds the colour or the temperature, soar finds the power, and price explains why the curve falls at short wavelengths instead of exploding. The tail line guards against the myth: red is the first, coolest glow; white means hotter.

Analogy — and where it breaks

Think of each mode as a ball resting at the bottom of a staircase while the floor shakes at random, harder the higher the temperature, with typical kicks worth about kT. Classically every staircase is a smooth ramp, and every ball, on any ramp, rides up to an average energy of kT. Planck turns each ramp into stairs with step height hf. For low-frequency modes the steps are tiny and the stairs feel like a ramp; for high-frequency modes the first step is a cliff many times taller than any typical kick, so the ball almost never leaves the floor. Where it breaks: thermal energy is not a literal shaking floor and a mode is not a ball; the odds come from Boltzmann statistics, not mechanics. And Planck's staircase starts at zero, whereas full quantum mechanics, in Chapter 13, adds a half-step of zero-point energy that does not change the thermal glow.

The whole chapter in one line

Hot objects glow with a temperature-set spectrum; classical physics predicted infinite ultraviolet energy until Planck's packets, E = hf, priced high frequencies out.

Leitner flashcards

Flashcards

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10Games

Play it into long-term memory

Match the vocabulary, then take the Quiz Show. Score 70% or better to tick it off your checklist.

Vocab match · timed

Vocab Match

Match each term to its definition, against the clock.

  • 12 pairs in 2 rounds
  • 100 points a match, more on a streak
  • −25 per mistake · speed bonus each round
  • Finish with 3 mistakes or fewer to win
Live from the lab

Dr. Q's Quantum Quiz Show

Dr. Q, your host

Welcome, contestants! 8 questions, 30 seconds each, and one mad scientist judging you, lovingly. Answer fast for a speed bonus; answer right in a row and your points multiply.

  • 100 per answer
  • +100 speed bonus
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11Worksheet

Prove it on paper

Answer every question, check your work, and read the explanations — the stretch challenge is for the truly mad.

14 questions12 terms1 challenge

Try every question without the lesson first, then check. Use b = 2.898×10⁻³ m·K, σ = 5.670×10⁻⁸ W/(m²·K⁴), h = 6.626×10⁻³⁴ J·s, k = 1.381×10⁻²³ J/K, c = 2.998×10⁸ m/s and 1 eV = 1.602×10⁻¹⁹ J. Show every step in the calculations: in my lab, a number without its reasoning scores nothing.

0/14 answered · saved on this device

Part A

Vocabulary

Blackbody
An ideal object that absorbs all electromagnetic radiation falling on it, at every wavelength and angle; in thermal equilibrium its emission spectrum depends only on its temperature.
Thermal radiation
Electromagnetic radiation emitted by matter because of its temperature, produced by the thermal jiggling of charged particles.
Thermal equilibrium
A state in which a body has a single steady temperature and exchanges no net energy with its surroundings.
Spectral radiance
The power a surface emits per unit area, per unit solid angle and per unit wavelength (or frequency) interval: the height of a blackbody curve.
Wien's displacement law
λₘₐₓ·T ≈ 2.898×10⁻³ m·K: a blackbody's peak wavelength is inversely proportional to its absolute temperature.
Stefan-Boltzmann law
P = εσA·T⁴: the total power a surface radiates grows as the fourth power of its absolute temperature.
Emissivity
The ratio of a surface's thermal emission to that of a blackbody at the same temperature; symbol ε, between 0 and 1.
Mode
One allowed standing-wave pattern of a confined wave, such as the radiation trapped in a cavity.
Equipartition theorem
The classical rule that in thermal equilibrium each independent quadratic energy term holds an average of kT/2, so each oscillator averages kT.
Ultraviolet catastrophe
The classical prediction, from the Rayleigh-Jeans law, that blackbody radiation grows without limit at short wavelengths and has infinite total energy.
Boltzmann factor
The relative probability e^(−E/kT) that a system in thermal equilibrium at temperature T is found in a state of energy E.
Planck's constant
The constant h, exactly 6.62607015×10⁻³⁴ J·s, that sets the size of an energy packet through E = hf.

Part B

Questions

Auto-checked except short answers, which you mark yourself.

  1. Question 1.Multiple choice

    Which property defines an ideal blackbody?

  2. Question 2.True or false

    A blackbody at 6,000 K would look black to your eye.

  3. Question 3.True or false

    In 1900 Planck proposed that light travels through space as a stream of particles.

  4. Question 4.Fill in the blank

    Wien's displacement law states that a blackbody's peak wavelength is inversely proportional to its absolute .

  5. Question 5.Fill in the blank

    Paul Ehrenfest's 1911 name for the classical prediction of unlimited short-wavelength radiation is the catastrophe.

  6. Question 6.Multiple choice

    Four pieces of the same steel glow in a dark forge. Which is hottest?

  7. Question 7.Multiple choice

    In the Rayleigh-Jeans calculation, which assumption leads directly to infinite total energy?

  8. Question 8.Calculation

    The cosmic microwave background has a blackbody spectrum at 2.725 K. At what wavelength does it peak, and in which part of the spectrum is that?

    Give a number and units. 6.63×10⁻³⁴, 6.63e-34 and 6.63 x 10^-34 all work.

  9. Question 9.Calculation

    Human skin is at about 306 K (33 °C). Where does its thermal emission peak, and why do thermal cameras work in the 8 to 14 μm band?

    Give a number and units. 6.63×10⁻³⁴, 6.63e-34 and 6.63 x 10^-34 all work.

  10. Question 10.Calculation

    An electric stove element has a radiating surface area of 0.010 m² and glows at 1,000 K. Treating it as a blackbody (ε = 1), how much power does it radiate? How much would it radiate at 500 K?

    This one asks for more than one value — give each, with its units.

  11. Question 11.Calculation

    A lamp filament is heated from 2,000 K to 3,000 K. Find its peak wavelength at each temperature, and the factor by which its radiated power increases.

    This one asks for more than one value — give each, with its units.

  12. Question 12.Calculation

    One of Planck's oscillators has a frequency of 5.00×10¹⁴ Hz. What is the size of one energy packet in joules and in electron-volts, and how many such packets make up 1.00 J?

    This one asks for more than one value — give each, with its units.

  13. Question 13.Short answer

    In two or three sentences, explain why quantizing oscillator energy in packets of hf removes the ultraviolet catastrophe.

  14. Question 14.Short answer

    Why is Max Planck often called a reluctant revolutionary?

Part C · optional, dangerous, extremely rewarding

Mad scientist challenge

Weigh Planck's constant with a thermometer, as Planck did in 1900. Planck's law predicts two results you have met: the Wien constant is b = hc/(4.965k), and the Stefan-Boltzmann constant is σ = 2π⁵k⁴/(15c²h³). Experiment gives b = 2.898×10⁻³ m·K and σ = 5.670×10⁻⁸ W/(m²·K⁴), and c = 2.998×10⁸ m/s. (a) Use b to find the ratio h/k. (b) Rewrite the formula for σ so that k is expressed in terms of σ, c and h/k, and compute k. (c) Find h. (d) With the gas constant R = 8.314 J/(mol·K), compute Avogadro's number, N = R/k. (e) Planck's 1900 inputs were b = 2.94×10⁻³ m·K and σ ≈ 5.30×10⁻⁸ W/(m²·K⁴), and he obtained h = 6.55×10⁻³⁴ J·s and k = 1.346×10⁻²³ J/K. By what percentage was each of his results off, and why?

12Wrap-up

Recap & sign-off

Key takeaways

  • A blackbody absorbs all radiation that falls on it; in thermal equilibrium its spectrum depends only on its temperature, and stove elements, stars and the cosmic microwave background all come close
  • Wien's law, λₘₐₓ·T ≈ 2.898×10⁻³ m·K, moves the peak to shorter wavelengths as T rises; the Stefan-Boltzmann law, P = εσA·T⁴, makes the power soar as the fourth power of T
  • Colour is a thermometer: red-hot is the coolest visible glow, white-hot is hotter, and stars run from red-orange near 3,000 K to blue-white above 10,000 K
  • Counting cavity modes, which grow as f², and giving each one kT by equipartition yields the Rayleigh-Jeans law: right at long wavelengths, infinite at short ones, the ultraviolet catastrophe
  • On 14 December 1900 Planck assumed that oscillator energy comes in packets, E = n·hf, with h now fixed at exactly 6.62607015×10⁻³⁴ J·s
  • The Boltzmann factor e^(−hf/kT) freezes out modes whose packets cost far more than kT, so the spectrum turns over and the total energy is finite
  • Planck saw quantization as a formal device for oscillators, not a claim that light is made of particles; Einstein took that step in 1905
Dr. Q signs off

And so the furnace cools, the catastrophe is cancelled, and classical physics has its first deep crack: energy, at least inside Planck's oscillators, comes in packets of hf. Planck hoped the packets were mere bookkeeping. Next session a young patent clerk in Bern named Albert Einstein takes them literally and solves a stubborn puzzle: why a dazzling red lamp cannot free a single electron from a zinc plate, while a feeble ultraviolet lamp does it at once. Bring your packets. Dr. Q, signing off.

Your chapter checklist

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