Start with the preview
Start here — today's preview. Watch “What is Quantum Tunneling, Exactly?” from Up and Atom before (or after) this session. The lab will wait. Mostly.
What is Quantum Tunneling, Exactly?
A friendly ten-minute tour that builds tunnelling from light: an evanescent wave leaks a short way past a surface that totally reflects light, and an electron's wavefunction fades into a barrier in the same way, leaving a small chance of finding it on the far side. As you watch, ask what would happen to that chance if the barrier were twice as thick.
Watch on YouTubeMore from the video vault
What is Quantum Tunnelling?
A forty-minute deep dive that starts from the alpha-decay paradox Rutherford faced, matches the wavefunction and its slope at the barrier edges to reach an explicit tunnelling probability, then approximates the real Coulomb barrier to estimate half-lives. Watch it after Parts 2 and 3, with our transmission formulas and the worksheet's Gamow challenge beside you.
Watch on YouTubeThe 2025 Nobel Prize in Physics (quantum tunnelling) - Sixty Symbols
Physicists from the University of Nottingham unpack the 2025 Nobel Prize in Physics, awarded for macroscopic quantum tunnelling and energy quantisation in a superconducting circuit. Watch it after Part 6 to see how an entire circuit can tunnel.
Watch on YouTube- What is Quantum Tunneling, Exactly? — Up and Atom — https://www.youtube.com/watch?v=WPZLRtyvEqo
- What is Quantum Tunnelling? — Physics Explained — https://www.youtube.com/watch?v=_f8zeEI0oys
- The 2025 Nobel Prize in Physics (quantum tunnelling) - Sixty Symbols — Sixty Symbols — https://www.youtube.com/watch?v=wwJf9ZUuKi8
Today's mission
Dr. Q · cold openPsigor! Roll the bowling ball at the hill. Gently, you magnificent heap of bolts. Up it goes, slower, slower, it stops, and back it comes. Roll it a billion times and it comes back a billion times: that is what lacking the energy to climb means. Now shrink the ball to an electron and the hill to a sliver of insulator one nanometre thick, and listen to the detector on the far side. Click. Click. Great Planck's ghost, it got through! No hole, no ladder, no borrowed energy, and the wall is untouched. Last session our walls were infinitely high. Today they are merely enormous, and the wavefunction learns that a wall is not an ending. It is a fade. That fade lights the Sun, ages uranium, remembers your photos and runs quantum computers.
By the end of this session you will be able to:
- Explain why a wavefunction decays exponentially, rather than stopping, inside a classically forbidden region where V exceeds E, and compute its decay length 1/κ.
- Estimate transmission probabilities with T ≈ e^(−2κL), compare them with the exact rectangular-barrier result, and predict how T responds to changes in barrier width, energy deficit and particle mass.
- Describe how Gamow's 1928 tunnelling model explains alpha decay and its enormous range of half-lives, and why fusion in the Sun's core depends on tunnelling.
- Explain how the scanning tunnelling microscope turns an exponentially sensitive current into images of individual atoms.
- Connect tunnelling to flash memory, tunnel diodes and Josephson junctions, including the macroscopic tunnelling recognized by the 2025 Nobel Prize in Physics.
- Explain why tunnelling drills no holes, lets no person walk through walls, and sends no signal faster than light.
Read it — or listen along
7 parts. Press play on any part and the paragraph being read lights up as Dr. Q speaks.
When the Wall Is Merely Enormous
Last session our electron lived behind walls of infinite height, and the rule was absolute: ψ = 0 at the wall. Real walls are never infinite. The oxide in a transistor, the vacuum gap between two metals, the electric repulsion around a nucleus: each is a potential barrier, a region where the potential energy V rises above the particle's total energy E by a finite amount over a finite distance. Classically, the kinetic energy E − V can never be negative, so a ball rolling toward a hill it cannot climb slows, halts at the turning point where E = V, and rolls back. Everything beyond is a classically forbidden region.
Quantum mechanics reads the same landscape through the Schrödinger equation of chapter 10. Where E exceeds V, the curvature of ψ points back toward the axis and the wavefunction oscillates. Where V exceeds E, the curvature points away from the axis, so ψ grows or decays exponentially. A growing solution could never be normalized in an endless barrier, and even in a thick finite one the decaying part dominates. So the wavefunction does not slam to zero at the edge. It enters, and it fades: ψ(x) ≈ ψ(0)e^(−κx), where x is the distance into the barrier and the Greek letter κ stands for the decay constant.
The decay constant is set by the energy deficit V − E, the particle's shortfall below the top. In words, κ is the square root of twice the mass times the deficit, divided by ħ; in symbols, ħκ = √(2m(V − E)). Its inverse, 1/κ, is the decay length, over which ψ shrinks by a factor of e, about 2.718. For an electron one electron-volt short of the top, κ ≈ 5.12 per nanometre and 1/κ ≈ 0.195 nm, comparable to the radius of an atom. The probability density, |ψ|², fades twice as fast, as e^(−2κx), halving every 0.068 nm. The infinite wall of chapter 11 is the limit in which κ is infinite and the fade is instantaneous.
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Through the Wall: Tunnelling and Its Exponential Toll
Now give the barrier a far side: a rectangle of height V and width L, with free space on either side. An electron wave arrives from the left. Part reflects, part enters and fades, and if the barrier is thin enough the fading tail is still alive at the far edge. Beyond it ψ oscillates again with its original wavelength, and a transmitted wave travels away. Its amplitude was cut by roughly e^(−κL) during the crossing, and probability goes as amplitude squared, so the transmission probability, the chance that a particle sent at the barrier is found beyond it, obeys T ≈ e^(−2κL). Passing through a barrier you lack the energy to climb is called quantum tunnelling.
Matching ψ and its slope at both edges gives the exact result for a rectangle. Once the exponent 2κL exceeds about 4, it simplifies to T ≈ 16(E/V)(1 − E/V)e^(−2κL). The prefactor never exceeds 4, so nearly all the action lives in the exponential. Take an electron with E = 1.0 eV meeting a barrier of height V = 2.0 eV. A barrier 0.5 nm wide transmits about 2.4 percent of electrons; double the width to 1.0 nm and T falls to 0.014 percent, 166 times smaller. Doubling the width squares the exponential factor, and the prefactor barely changes. Whatever is not transmitted is reflected: R + T = 1, where R is the reflection probability.
The exponent also hides the mass, because κ grows as the square root of m. A proton is 1,836 times heavier than an electron, so its κ is larger by a factor of √1836, about 42.85, and through the barrier 0.5 nm wide its transmission is about 10⁻⁹⁵: effectively never. Tunnelling rewards thin barriers, light particles and energies close to the top. Electrons tunnel constantly in electronics and chemistry, hydrogen nuclei tunnel measurably in some chemical reactions, and heavier things almost never do. For smooth barriers, the WKB approximation, introduced in 1926 by Gregor Wentzel, Hendrik Kramers and Léon Brillouin, replaces 2κL by twice the area under the curve of κ(x) across the forbidden region.
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Gamow's Great Escape: Alpha Decay
Tunnelling's first triumph came from the nucleus. Many heavy nuclei decay by emitting an alpha particle, two protons and two neutrons bound together, identical to a helium-4 nucleus. Inside the nucleus the strong nuclear force holds the alpha in; just outside, the electric repulsion of the remaining protons shoves it away. Together they form the Coulomb barrier, roughly 30 MeV high around uranium. Yet uranium-238 emits alpha particles carrying only about 4.2 MeV, while scattering experiments analysed by Ernest Rutherford in 1927 showed that alpha particles with about twice that energy, fired at uranium, were turned back by electric repulsion without ever getting in. How can a particle escape a wall that a projectile with twice its energy cannot climb?
In 1928 George Gamow, and independently Ronald Gurney and Edward Condon, answered: it does not go over, it goes through. The alpha rattles inside the nucleus, striking the barrier about 10²¹ times per second, each strike with a minuscule, fixed chance of tunnelling out. A nucleus therefore has no memory and no clock: decay times are random, and a large sample decays exponentially with a definite half-life, the time in which half the nuclei decay. Because electric repulsion fades as 1/r with distance r from the centre, a uranium-238 alpha must tunnel from the nuclear surface, about 9 fm out, to about 61 fm, where the hill sinks below its energy (a femtometre is 10⁻¹⁵ metres). The WKB recipe gives odds of a few times 10⁻³⁹ per strike: billions of years.
The model's glory is the Geiger–Nuttall law, found by Hans Geiger and John Nuttall in 1911: the more energetic an emitter's alpha particles, the shorter its half-life. Polonium-212 emits alphas of 8.78 MeV and has a half-life of 0.29 μs; uranium-238 emits alphas of 4.20 MeV and lasts 4.47 billion years. Barely a factor of two in energy, a factor of about 5×10²³ in lifetime! The more energetic alpha meets the 1/r wall where it is thinner, needing to tunnel only out to about 26 fm, and because width sits in an exponent, a modest change in energy becomes an astronomical change in lifetime. Bismuth-209, long thought stable, was caught alpha-decaying in 2003; its half-life, 2.0×10¹⁹ years, is over a billion times the age of the universe.
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Why the Sun Can Shine
The Sun fuses hydrogen into helium in its core, and the first step is the hardest: two protons must come within a femtometre or so before the strong force can grab them, and their electric repulsion at that range is a barrier of roughly 1.0 MeV. At a core temperature of about 15.7 million kelvin, the matching thermal energy scale kT, where k is Boltzmann's constant, is just 1.35 keV, and a typical proton carries about 2 keV, some five hundred times too little. The fraction of protons with enough energy to climb the barrier is of order e^(−739), about 10⁻³²¹. Even with about 10⁵⁷ protons in the Sun, classically not one pair would fuse in the age of the universe.
A proton with just a few thousand electron-volts has a tiny but real chance of slipping through, a chance that climbs steeply with energy while the number of protons at each energy falls steeply. Their product peaks in a narrow window, the Gamow peak, near 6 keV in the solar core: most fusing pairs tunnel through a barrier more than a hundred times higher than their energy. Arthur Eddington, who had argued in 1920 that stars burn hydrogen, told critics who said the stars were not hot enough to go and find a hotter place. In 1929 Robert Atkinson and Fritz Houtermans vindicated him with Gamow's tunnelling, and in 1938 and 1939 Hans Bethe, partly with Charles Critchfield, worked out the reaction chains that power the stars, work that won Bethe the 1967 Nobel Prize in Physics.
Even with tunnelling the first step is extraordinarily slow, because it also needs the weak nuclear force to turn a proton into a neutron. That bottleneck is a blessing: the Sun shines steadily for about ten billion years instead of burning out before life could evolve.
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Feeling Atoms with a Tunnelling Current
Exponential sensitivity, a curse for anyone predicting lifetimes, is a gift for anyone measuring distances. In March 1981, at IBM's research laboratory near Zurich, Gerd Binnig and Heinrich Rohrer first measured a controlled tunnelling current across a vacuum gap, the decisive step toward their scanning tunnelling microscope, or STM. A sharp metal tip is held within about a nanometre of a conducting surface, never touching it, and a small voltage is applied. The vacuum gap is a barrier whose height is roughly the work function, the minimum energy needed to pull an electron out of a metal, typically 4 to 5 eV. Electrons tunnel across, giving a current of around a nanoampere that falls as e^(−2κd) with the gap d.
For a barrier of 4.5 eV, κ ≈ 10.9 per nanometre, so retracting the tip by just 0.1 nm cuts the current about ninefold. A feedback loop moves the tip up and down to hold the current constant as it scans, and the record of those movements is a contour map of the surface with height resolution at the picometre level. The same exponential delivers sideways resolution: if the tip ends in a single atom, that atom sits a fraction of a nanometre closer than its neighbours and carries almost all the current. Binnig and Rohrer shared the 1986 Nobel Prize in Physics with Ernst Ruska, the pioneer of the electron microscope.
The STM soon did more than look. In 1989 Donald Eigler and Erhard Schweizer at IBM's Almaden laboratory in California used the tip to slide 35 xenon atoms across a nickel crystal until they spelled the letters IBM, a feat published in 1990. Building with single atoms had begun.
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Tunnelling in Your Pocket and in Quantum Computers
The photos on your phone are stored by tunnelling. Flash memory, invented by Fujio Masuoka's team at Toshiba in the 1980s, keeps each bit as charge trapped on an isolated layer walled in by oxide only several nanometres thick. To write or erase the NAND flash used for mass storage, the chip applies roughly 15 to 20 volts, which tilts the barrier into a thin triangle that electrons tunnel through: Fowler–Nordheim tunnelling. Remove the voltage, the barrier widens again, and the charge stays put for years without power. Tunnelling can also be a nuisance: by the mid-2000s the silicon dioxide layer insulating each transistor's gate was only about 1.2 nm thick, and leakage through it pushed Intel, in 2007, to a physically thicker hafnium-based insulator.
In 1957 Leo Esaki, at the company soon renamed Sony, doped a germanium junction so heavily that the junction was only some ten to twenty nanometres wide. Electrons tunnelled straight across, and over a range of voltages the current fell as the voltage rose, a negative resistance that let tunnel diodes switch extremely fast. In 1962 Brian Josephson, a 22-year-old Cambridge graduate student, predicted that Cooper pairs, the bound electron pairs that carry a superconductor's resistance-free current, would tunnel through a thin insulator between two superconductors, a device now called a Josephson junction. A current then flows with no voltage at all, and a steady voltage makes it oscillate at 483.6 GHz per millivolt, the basis of modern voltage standards. Esaki, Josephson and Ivar Giaever, who used tunnelling to probe superconductors, shared the 1973 Nobel Prize in Physics.
Can something big tunnel? In 1984 and 1985 at the University of California, Berkeley, John Clarke, Michel Devoret and John Martinis tested exactly that with a Josephson junction on a chip about a centimetre across. A current flowed with zero voltage, a state trapped behind an energy barrier. What tunnelled out was not one electron but a single collective variable describing billions of Cooper pairs, and a voltage suddenly appeared. Below a crossover temperature the escape rate stopped depending on temperature, the fingerprint of tunnelling rather than thermal hopping, and microwaves revealed quantized energy levels. The work earned the 2025 Nobel Prize in Physics; its descendants, superconducting qubits built around Josephson junctions, are as of 2026 the heart of quantum processors at Google, IBM and elsewhere.
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What Tunnelling Is Not
A tempting thought: perhaps a tunnelling particle crosses the barrier instantly. In 1962 Thomas Hartman calculated that the delay of a transmitted wave packet stops growing once a barrier is thick, implying ever-faster apparent speeds. In 1993 Aephraim Steinberg, Paul Kwiat and Raymond Chiao at Berkeley timed single photons tunnelling through a multilayer mirror 1.1 μm thick: the transmitted peaks arrived 1.47 fs earlier than those of twin photons crossing the same distance in air, an apparent speed of about 1.7 times the speed of light.
No signal outran light. The barrier reshapes the pulse, transmitting a faint copy built mostly from its leading edge, which was already ahead; the peak shifts forward, but the front, the earliest moment anything can be detected, never outruns light. Nor is tunnelling instantaneous: in 2020 Steinberg's group in Toronto sent rubidium atoms cooled to about two nanokelvin through a barrier of laser light 1.3 μm thick and found that transmitted atoms spent about 0.6 ms inside. What happens in between is interpretation-dependent: standard quantum mechanics assigns no path, while the pilot-wave theory of chapter 22 gives every particle a definite trajectory.
Finally, strolling through your bedroom wall. Treat a person of 70 kg as a single particle, grant a generous energy deficit of one joule and a wall 10 cm thick: 2κL ≈ 2.2×10³⁴, so T is about 1 divided by a number with 10³⁴ digits. Trying once a second for the age of the universe, about 4×10¹⁷ seconds, changes nothing. Worse, you are not one isolated quantum object but about 7×10²⁷ atoms, jostled by air and light, which destroys the coherence any collective tunnelling would need. Mwahaha, measurably: the wall wins.
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Go deeper on video
22 more videos for this chapter, 16 of them from universities, research institutes and Nobel lectures. The clips under “Watch this part” in the lesson start at the moment that matters.
Key equations
Decay constant
How fast the wavefunction fades inside a barrier. A bigger mass or a bigger energy deficit means a larger κ and a faster fade. For an electron one electron-volt short of the top, κ ≈ 5.12 per nanometre.
| Symbol | Meaning | Unit |
|---|---|---|
| κ | decay constant; 1/κ is the decay length | m⁻¹ (often quoted per nanometre) |
| m | mass of the particle | kg |
| V − E | energy deficit: barrier height minus particle energy | J (often quoted in eV) |
| ħ | reduced Planck constant, 1.055×10⁻³⁴ | J·s |
Say it: “kappa equals the square root of two m times the quantity V minus E, all divided by h-bar”
Wavefunction inside the barrier
In a classically forbidden region the wavefunction does not stop; it decays exponentially with distance x into the barrier, and the probability density decays twice as fast.
| Symbol | Meaning | Unit |
|---|---|---|
| ψ(x) | wavefunction at depth x inside the barrier | m⁻¹ᐟ² |
| x | distance into the barrier from its edge | m |
Say it: “psi of x is approximately psi of zero times e to the minus kappa x, so the probability density falls as e to the minus two kappa x”
Thick-barrier transmission
The chance of getting through a barrier of width L falls exponentially with the width, and with the square roots of the mass and of the energy deficit hidden inside κ. Doubling L squares this exponential factor.
| Symbol | Meaning | Unit |
|---|---|---|
| T | transmission probability | dimensionless, between 0 and 1 |
| L | barrier width | m |
Say it: “T is approximately e to the minus two kappa L”
Exact rectangular barrier
The full answer for a rectangular barrier when E is below V, found by matching ψ and its slope at both edges. Once 2κL exceeds about 4 the simple form on the right is accurate to a few percent; its prefactor is never larger than 4.
| Symbol | Meaning | Unit |
|---|---|---|
| V | barrier height | J or eV |
| E | particle energy, below V | J or eV |
| sinh | hyperbolic sine, sinh(y) = (eʸ − e⁻ʸ)/2 | dimensionless |
Say it: “T equals one over the quantity one plus V squared times the hyperbolic sine squared of kappa L, divided by four E times the quantity V minus E. For thick barriers this is approximately sixteen times E over V, times one minus E over V, times e to the minus two kappa L”
Barriers of any shape (WKB)
For a smooth barrier, add up κ(x) slice by slice between the classical turning points x₁ and x₂. This is the recipe Gamow used for the Coulomb barrier in alpha decay.
| Symbol | Meaning | Unit |
|---|---|---|
| V(x) | potential energy, varying with position | J |
| x₁, x₂ | turning points where V(x) = E, the edges of the forbidden region | m |
Say it: “T is approximately e to the power minus two over h-bar times the integral, from x one to x two, of the square root of two m times V of x minus E, d x”
Scanning tunnelling microscope current
The current between tip and surface falls exponentially with the gap d. With a work function near 4.5 eV it drops about ninefold for every 0.1 nm of extra gap, which is what lets an STM feel single atoms.
| Symbol | Meaning | Unit |
|---|---|---|
| I | tunnelling current | A (typically about 1 nA) |
| V_bias | small voltage applied between tip and sample | V |
| d | tip-to-surface gap | m |
| φ | work function, the effective barrier height | eV (typically 4 to 5) |
Say it: “The tunnelling current I is proportional to the bias voltage times e to the minus two kappa d, where kappa is the square root of two times the electron mass times phi, divided by h-bar”
Real numbers, step by step
Cover the steps, try the problem yourself, then reveal the solution one step at a time.
An electron meets a thin barrier
An electron with energy E = 1.00 eV meets a rectangular barrier of height V = 2.00 eV. Find κ, then estimate T for barrier widths of 0.50 nm and 1.00 nm, first with e^(−2κL) alone and then including the thick-barrier prefactor.
Step 1: The deficit is V − E = 1.00 eV = 1.602×10⁻¹⁹ joules. With m = 9.109×10⁻³¹ kilograms, the product 2m(V − E) is 2.919×10⁻⁴⁹ in SI units, and its square root is 5.403×10⁻²⁵. Dividing by ħ = 1.0546×10⁻³⁴ J·s gives κ = 5.123×10⁹ per metre, which is 5.123 per nanometre. Keep the extra digit: in an exponent, small rounding errors grow.
Step 2: For L = 0.50 nm the exponent is 2κL = 2 × 5.123 × 0.50 = 5.123, and e^(−5.123) = 5.96×10⁻³.
Step 3: The prefactor is 16(E/V)(1 − E/V) = 16 × 0.5 × 0.5 = 4, so T ≈ 4 × 5.96×10⁻³ = 0.0238. The exact rectangular-barrier formula gives 0.0235.
Step 4: For L = 1.00 nm the exponent doubles to 10.246, and e^(−10.246) = 3.55×10⁻⁵, so T ≈ 4 × 3.55×10⁻⁵ = 1.42×10⁻⁴, matching the exact value of 1.42×10⁻⁴.
κ ≈ 5.12 per nanometre; T ≈ 2.4 percent for a width of 0.50 nm, and T ≈ 1.4×10⁻⁴, about 0.014 percent, for a width of 1.00 nm
Why it matters: Doubling the width cut the transmission 166-fold. The bare exponential missed the factor of 4 in front, but it captured the dramatic part: how fast T collapses as the barrier thickens.
Swap the electron for a proton
Send a proton with the same energy, 1.00 eV, at the same barrier: height 2.00 eV, width 0.50 nm. Estimate its transmission probability.
Step 1: κ is proportional to the square root of the mass, and the proton is 1,836 times heavier than the electron, so the proton's κ is 5.1232 × √1836 = 5.1232 × 42.849 = 219.52 per nanometre.
Step 2: The exponent is 2κL = 2 × 219.52 × 0.50 = 219.52.
Step 3: Convert to a power of ten by dividing the exponent by the natural logarithm of 10, which is 2.3026: 219.52 ÷ 2.3026 = 95.34, so e^(−219.52) = 10^(−95.34) ≈ 4.6×10⁻⁹⁶.
Step 4: Including the prefactor of 4, T ≈ 1.8×10⁻⁹⁵. Even a barrier only 0.10 nm wide gives the proton just 3.4×10⁻¹⁹, while an electron would cross it 78 percent of the time.
T ≈ 1.8×10⁻⁹⁵ for the proton, against about 2.4×10⁻² for the electron
Why it matters: Mass enters under a square root inside the exponent, so a factor of 1,836 in mass became a factor of about 43 in the exponent, and that turned a few percent into essentially never. Tunnelling is a story about light particles.
The sensitivity of a tunnelling microscope
An STM tip hovers above a metal surface whose effective barrier height, roughly its work function, is 4.5 eV. First, by what factor does the tunnelling current fall when the tip retracts by 0.10 nm? Second, if the electronics can hold the current steady to within 2 percent, what is the smallest change in height the microscope can sense?
Step 1: κ grows as the square root of the deficit, so scale the value for a deficit of one electron-volt: κ = 5.123 × √4.5 = 5.123 × 2.121 = 10.87 per nanometre.
Step 2: The current goes as e^(−2κd). Retracting by Δd = 0.10 nm multiplies it by e^(−2 × 10.87 × 0.10) = e^(−2.174) = 0.114, a drop by a factor of about 8.8.
Step 3: A 2 percent change in current means e^(2κΔd) = 1.02, so 2κΔd equals the natural logarithm of 1.02, which is 0.0198. Then Δd = 0.0198 ÷ 21.74 per nanometre = 9.1×10⁻⁴ nanometres.
Step 4: That is 0.91 pm, a few hundred times smaller than the diameter of a typical atom.
The current falls by a factor of about 8.8, nearly tenfold, and the smallest detectable height change is about 0.9 pm, less than a picometre
Why it matters: No lens is involved: the exponential law itself is the magnifying glass. That is why an STM registers height changes far smaller than an atom.
Knocking to escape a uranium nucleus
Uranium-238 has a half-life of 4.47×10⁹ years and polonium-212 a half-life of 294 ns. Estimate how often an alpha particle strikes the nuclear barrier, then the escape probability per strike for each nucleus.
Step 1: Strike rate: an alpha particle with about 4.2 MeV moves at about 1.4×10⁷ m/s. Crossing a nucleus of radius 7.4 fm from wall to wall, a diameter of 1.48×10⁻¹⁴ metres, takes about 10⁻²¹ seconds, so it strikes the wall roughly 10²¹ times per second. This is a crude, standard estimate.
Step 2: The decay rate λ, the probability of decay per second, is the natural logarithm of 2, which is 0.693, divided by the half-life. For uranium-238 the half-life is 4.47×10⁹ years × 3.156×10⁷ seconds per year = 1.41×10¹⁷ seconds, so λ = 0.693 ÷ 1.41×10¹⁷ = 4.9×10⁻¹⁸ per second.
Step 3: Escape probability per strike: T = λ ÷ (strike rate) = 4.9×10⁻¹⁸ ÷ 10²¹ ≈ 5×10⁻³⁹.
Step 4: For polonium-212, λ = 0.693 ÷ 2.94×10⁻⁷ seconds = 2.4×10⁶ per second, so T ≈ 2.4×10⁶ ÷ 10²¹ ≈ 2×10⁻¹⁵.
About 5×10⁻³⁹ per strike for uranium-238, so a typical alpha knocks about 2×10³⁸ times before escaping, and about 2×10⁻¹⁵ per strike for polonium-212
Why it matters: The alpha energies differ by only a factor of 2.1, 4.20 against 8.78 MeV, yet the escape odds differ by a factor of about 5×10²³. The mad scientist challenge on the worksheet shows that Gamow's WKB integral reproduces both numbers to within a factor of about four.
What everyone gets wrong
Read the myth, decide whether you believed it, then bust it.
- Myth #1
A tunnelling particle drills a hole through the barrier, or squeezes through a gap in it.
TruthNothing is bored, broken or opened. The barrier is identical before and after, ready to transmit or reflect the next particle with exactly the same odds, and for a barrier that does not change in time the particle emerges with the energy it arrived with. Tunnelling is a wave property: the wavefunction fades across the forbidden region without reaching zero, so the probability of finding the particle beyond it is small but not zero.
- Myth #2
A person could walk through a wall by tunnelling, if they only tried often enough.
TruthEven treating a person of 70 kg as a single particle with a generous one-joule energy deficit and a wall 10 cm thick, T is about 1 divided by a number with 10³⁴ digits; one attempt per second for the age of the universe, about 4×10¹⁷ attempts, changes nothing. Worse, a person is about 7×10²⁷ atoms constantly disturbed by air and light, not one isolated quantum object. The macroscopic tunnelling of the 2025 Nobel Prize needed a single collective variable in a carefully isolated circuit cooled to a few hundredths of a kelvin.
- Myth #3
Tunnelling is instantaneous, so it can carry signals faster than light.
TruthTunnelling photons in the 1993 Berkeley experiment had peaks that arrived early, as if moving at 1.7 times the speed of light, but the barrier merely reshaped each pulse from its leading edge; the front of any signal never outruns light, so no message can be sent faster than c. Tunnelling also takes time: in 2020 rubidium atoms were measured spending about 0.6 ms inside a barrier 1.3 μm thick.
- Myth #4
A particle tunnels by borrowing energy from the uncertainty principle and paying it back quickly.
TruthThis popular story misuses the energy-time relation. In the standard calculation the particle's energy is E throughout, and nothing is borrowed. Tunnelling happens because the wavefunction in a forbidden region decays rather than vanishes. If a measurement does catch the particle inside the barrier, that measurement itself supplies the energy.
Your turn at the controls
Welcome to the Tunneling Arcade. In the barrier simulator an electron wave packet races toward a rectangular barrier, and you set the electron's energy E, the barrier height V₀ and the barrier width a, which this chapter calls L; energies are in electron-volts and widths in nanometres. Fire the packet and watch it split: part reflects, a faded remnant leaks through, and the lab measures the fraction that ends up on the far side. Beside that simulated transmission sit the exact rectangular-barrier value and the bare exponential e^(−2κa), which the lab labels the thick-barrier estimate, and a log plot of T against width turns the exponential into a straight line. A second screen holds a scanning tunnelling microscope. The arcade has three levels; clear all three to win.
Your tasks
0/6How it connects to the theory
Every number on screen comes from this chapter. κ uses the real electron mass and ħ, the exact transmission comes from matching ψ and its slope at both edges of the barrier, and e^(−2κa) is the thick-barrier shortcut whose missing prefactor you can watch for yourself. The packet itself moves by the time-dependent Schrödinger equation of chapter 10, solved step by step. Because a real packet carries a spread of energies and its faster components tunnel more easily, the simulated transmission usually sits a little above the single-energy formula; after each run the lab also shows the formula averaged over the packet's energies, which is what the simulation should match. The STM screen runs on the same law, with the current falling as e^(−2κd) under a 4.5 eV work function. The barrier never changes as packets pass, and in a real experiment each electron would be detected whole on one side or the other. Only the odds are shared.
Tunneling Arcade: Get Through the Barrier loads as you scroll down.
Make it stick
Tunnelling loves the THIN, the LIGHT and the NEARLY THERE. Thin: a narrow barrier, small L. Light: a small mass m. Nearly there: an energy just below the top, so the deficit V − E is small. All three sit together in the exponent, 2κL = 2L√(2m(V − E)) divided by ħ, so getting any one of them wrong is punished exponentially. For the applications, remember FAST JS: Flash memory, Alpha decay, the Sun, Tunnel diodes, Josephson junctions, Scanning tunnelling microscope. And remember the joke hidden in the name: tunnelling is never faster than light. To use it: before any tunnelling problem, ask whether the barrier is thin, the particle light and the energy nearly there. A loud no to any of them means a vanishing transmission.
Tunnelling is like light escaping a glass prism at an angle where it should be totally reflected. Just beyond the glass a fading evanescent wave reaches a fraction of a wavelength into the air, and if a second prism is brought almost into contact, light crosses the gap; Isaac Newton noticed the effect three centuries ago. The mathematics is the same exponential fade. Where it breaks: a bright beam's energy is visibly shared between two beams, which tempts you to picture each electron split in two, but a tunnelling electron is never split; it is detected whole on one side or the other, and only the odds are shared. And light fades over hundreds of nanometres, an electron over a fraction of one.
The whole chapter in one lineWhere a particle lacks the energy to climb, its wave fades but never stops; thin, light, nearly-there particles leak through with odds of about e^(−2κL).
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Answer every question, check your work, and read the explanations — the stretch challenge is for the truly mad.
Answer every question with the lesson closed, then check your work. Use ħ = 1.055×10⁻³⁴ J·s, electron mass 9.109×10⁻³¹ kg, 1 eV = 1.602×10⁻¹⁹ J and Boltzmann's constant k = 8.617×10⁻⁵ eV per kelvin. Once you have derived it, you may use the shortcut that an electron's κ is 5.12 per nanometre times the square root of the energy deficit in eV. Show every step in the calculation questions.
Part A
Vocabulary
- Potential barrier
- A region where the potential energy rises above a particle's total energy, over a finite width.
- Classically forbidden region
- A region where V exceeds E, which a classical particle can never enter because its kinetic energy would be negative.
- Turning point
- The position where E = V, at which a classical particle stops and reverses.
- Decay constant
- κ, with ħκ = √(2m(V − E)); the wavefunction in a barrier fades as e^(−κx), and 1/κ is the decay length.
- Transmission probability
- T, the chance that a particle sent at a barrier is found beyond it; with the reflection probability R, R + T = 1.
- Quantum tunnelling
- Passage of a particle through a classically forbidden barrier, possible because its wavefunction fades inside the barrier rather than vanishing.
- WKB approximation
- A method, introduced in 1926 by Wentzel, Kramers and Brillouin, that estimates tunnelling through smooth barriers by adding up κ(x) across the forbidden region.
- Coulomb barrier
- The energy hill created by electric repulsion between positively charged nuclear particles, which an alpha particle tunnels out through and fusing protons tunnel in through.
- Gamow peak
- The narrow energy window in which fusion reactions in a star actually occur, where the falling number of fast particles balances their rising tunnelling probability; near 6 keV in the Sun's core.
- Work function
- The minimum energy needed to remove an electron from a metal surface; it sets the barrier height in a scanning tunnelling microscope.
- Josephson junction
- Two superconductors separated by a thin insulating barrier through which Cooper pairs tunnel; the heart of superconducting qubits and voltage standards.
- Macroscopic quantum tunnelling
- Tunnelling of a collective variable describing enormous numbers of particles, such as the state of a whole superconducting circuit; recognized by the 2025 Nobel Prize in Physics.
Part B
Questions
Auto-checked except short answers, which you mark yourself.
- Question 1.Multiple choice
A thick barrier transmits a tiny fraction of the particles that hit it. Which single change raises the transmission probability the most?
- Question 2.Multiple choice
What does the wavefunction of a particle with E below V do inside a wide barrier?
- Question 3.Multiple choice
An STM operates with κ = 10 per nanometre, and its tunnelling current suddenly doubles. What happened to the tip-surface gap?
- Question 4.True or false
A particle that tunnels through a barrier that does not change in time emerges with less energy than it had before.
- Question 5.True or false
Without quantum tunnelling, hydrogen fusion in the Sun's core would essentially stop.
- Question 6.True or false
The 2020 Toronto experiment found that rubidium atoms cross a tunnelling barrier in zero time.
- Question 7.Fill in the blank
The distance 1/κ over which ψ shrinks by a factor of e inside a barrier is called the length.
- Question 8.Fill in the blank
In 1928 George Gamow explained decay as tunnelling through the Coulomb barrier of the nucleus.
- Question 9.Short answer
Alpha energies of common emitters differ by only about a factor of two, yet their half-lives differ by more than twenty orders of magnitude. Explain why in two or three sentences.
- Question 10.Short answer
A popular explanation says a tunnelling particle briefly borrows the energy it needs from the uncertainty principle. In two or three sentences, explain what is wrong with this and what actually makes tunnelling possible.
- Question 11.Calculation
An electron with E = 2.0 eV meets a rectangular barrier of height 5.0 eV and width 0.40 nm. Find κ, the bare exponential e^(−2κL), and the transmission probability including the thick-barrier prefactor.
This one asks for more than one value — give each, with its units.
- Question 12.Calculation
Barrier design: an electron with E = 1.0 eV meets a 2.0 eV barrier. Using the thick-barrier formula, what width gives a transmission probability of exactly 1 percent?
Give a number and units. 6.63×10⁻³⁴, 6.63e-34 and 6.63 x 10^-34 all work.
- Question 13.Calculation
The Sun's core is at 1.571×10⁷ K. Find the thermal energy scale kT in keV, the ratio of a 1 MeV Coulomb barrier to kT, and the Boltzmann factor e^(−1 MeV/kT) as a power of ten.
This one asks for more than one value — give each, with its units.
- Question 14.Calculation
Treat a 70 kg person as a single particle facing a wall 0.10 m thick with an energy deficit of just 1.0 J. Estimate 2κL and express T as a power of ten.
Give a number and units. 6.63×10⁻³⁴, 6.63e-34 and 6.63 x 10^-34 all work.
Part C · optional, dangerous, extremely rewarding
Mad scientist challenge
Reproduce Gamow's 1928 triumph. For an alpha particle of energy Q escaping a daughter nucleus of charge number Z, the barrier runs from the nuclear radius R out to the turning point b = 2Z × 1.440 MeV·fm ÷ Q, and the WKB exponent is G = (2b/ħ)√(2μQ) × [arccos√(R/b) − √((R/b)(1 − R/b))], with T = e^(−G). Use an alpha mass of 6.645×10⁻²⁷ kg, reduced mass μ = (alpha mass) × A ÷ (A + 4) for a daughter of mass number A, 1 MeV = 1.602×10⁻¹³ J, and a strike rate of 10²¹ per second. (a) Uranium-238: Q = 4.27 MeV, Z = 90, A = 234, R = 9.3 fm. Find b, G, T and the predicted half-life. (b) Polonium-212: Q = 8.95 MeV, Z = 82, A = 208, R = 9.0 fm. (c) Compare both with the measured half-lives, 4.47×10⁹ years and 294 ns.
Recap & sign-off
Key takeaways
- Where the potential V exceeds a particle's energy E, classical physics forbids entry, but ψ decays exponentially, as e^(−κx) with ħκ = √(2m(V − E)), instead of stopping.
- If the barrier has a far side, the faded tail emerges as a transmitted wave: T ≈ e^(−2κL), with an exact prefactor never larger than 4, and R + T = 1.
- The exponent punishes width directly and mass and energy deficit through square roots: doubling the width squares the exponential factor, and a proton facing a barrier that an electron crosses 2.4 percent of the time gets through with a probability of about 10⁻⁹⁵.
- Gamow, and independently Gurney and Condon, explained alpha decay in 1928 as tunnelling through the Coulomb barrier; because width sits in an exponent, a factor of two in alpha energy spans about 24 orders of magnitude in half-life.
- Protons in the Sun's core carry about 2 keV against a barrier near 1.0 MeV; fusion happens only because they tunnel, mostly near the Gamow peak at about 6 keV.
- Exponential sensitivity is a tool: the STM (1981) maps single atoms, flash memory writes by Fowler–Nordheim tunnelling, tunnel diodes switch fast, and Josephson junctions underpin voltage standards and superconducting qubits; macroscopic tunnelling in such a circuit won the 2025 Nobel Prize in Physics.
- Tunnelling drills no holes, borrows no energy, sends no signal faster than light, and offers no hope of walking through walls.
Dr. Q signs offAnd that, my fearless barrier-breachers, is how a wave that refuses to stop at a wall lights the stars, ages rocks, guards your photos and runs quantum chips. Next session we trade the wall for a valley: a particle in a parabolic bowl, the quantum harmonic oscillator, the universe's favourite spring. Its energies form a perfectly even ladder, its lowest rung is never zero, and yes, its wavefunction leaks past the classical turning points too. Psigor, oil the springs. Chapter 13 awaits.
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Sources & further reading
- HyperPhysics: Barrier Penetration (quantum tunnelling) · hyperphysics.phy-astr.gsu.edu
- HyperPhysics: Alpha Particle Tunneling · hyperphysics.phy-astr.gsu.edu
- NobelPrize.org: Popular information, Nobel Prize in Physics 2025 (macroscopic quantum tunnelling) · nobelprize.org
- NobelPrize.org: Press release, Nobel Prize in Physics 1986 (scanning tunnelling microscope) · nobelprize.org
- NobelPrize.org: Nobel Prize in Physics 1973 (Esaki, Giaever, Josephson) · nobelprize.org