Start with the preview
Start here — today's preview. Watch “Quantum Entanglement: Spooky Action at a Distance” from Fermilab before (or after) this session. The lab will wait. Mostly.
Quantum Entanglement: Spooky Action at a Distance
Fermilab's Dr. Don Lincoln explains what the phrase 'quantum entanglement' means and how two objects can be linked by quantum effects. As you watch, keep two questions in mind: what exactly is correlated, and could anything in the setup carry a message? Part 5 of the lesson settles the second question with a two-line calculation.
Watch on YouTubeMore from the video vault
Lecture 24: Entanglement: QComputing, EPR, and Bell's Theorem
A full MIT 8.04 lecture by Allan Adams. The first part previews quantum computing (the no-cloning theorem, met briefly in Part 5 and fully in Chapter 24, and the Deutsch–Jozsa algorithm of Chapter 23); the last part is devoted to the EPR experiment and Bell's inequality, the ideal bridge from this chapter to the next. Best watched after the lesson.
Watch on YouTubeWhy Can't You Use Quantum Mechanics To Communicate Faster Than Light?
A short, careful argument for why entangled particles cannot carry messages, using the same Alice-and-Bob setup as Part 5. The video speaks of the particles 'affecting' each other; treat that as one way of talking (Part 5 explains why it is interpretation-dependent) and focus on the proof that Bob's results stay random.
Watch on YouTube- Quantum Entanglement: Spooky Action at a Distance — Fermilab — https://www.youtube.com/watch?v=JFozGfxmi8A
- Lecture 24: Entanglement: QComputing, EPR, and Bell's Theorem — MIT OpenCourseWare — https://www.youtube.com/watch?v=awpnsGl08bc
- Why Can't You Use Quantum Mechanics To Communicate Faster Than Light? — Looking Glass Universe — https://www.youtube.com/watch?v=0xI2oNEc1Sw
Today's mission
Dr. Q · cold openPsigor, kill the lights and fire the violet laser! Inside this little crystal, every so often, a single photon splits into two, and the twins race to opposite ends of my laboratory. Ask either photon a question and its answer is a perfect coin toss. Ask both the same question and they agree every single time, though no wire, wave or whisper connects them. Einstein called it spooky action at a distance and remained convinced for the rest of his life that the theory was incomplete. Today you will learn exactly what an entangled state is, why its correlations swing with the angle between two detectors, how my crystal manufactures such pairs, and why not even I can use them to send a message faster than light. I'm mad, not wrong.
By the end of this session you will be able to:
- Define an entangled state and prove that the Bell state |Φ+⟩ cannot be written as a product of single-particle states.
- Explain how entangled pairs combine perfect correlation at matched settings with complete randomness in each local outcome, and distinguish this from classical correlation.
- Reconstruct the 1935 EPR argument and define a local hidden-variable theory.
- Calculate correlations as a function of analyser angle: coincidences following cos²θ for entangled photons and E = −cos θ for spin singlets.
- Show why entanglement cannot transmit messages, and describe how spontaneous parametric down-conversion makes entangled photons.
- Describe how teleportation, cryptography and quantum computing use entanglement as a resource.
Read it — or listen along
7 parts. Press play on any part and the paragraph being read lights up as Dr. Q speaks.
One State, Two Particles
Last session you wrote joint wavefunctions for identical particles as sums of products. Today the particles can be told apart, because they sit in different laboratories. Take two qubits, where a qubit is any quantum system with two perfectly distinguishable states labelled 0 and 1: spin up or down, or a photon polarised horizontally (H) or vertically (V). The pair has four basis states, |00⟩, |01⟩, |10⟩ and |11⟩, the first digit for Alice's particle and the second for Bob's. A product state, also called separable, is one that can be written as a definite state of Alice's particle times a definite state of Bob's.
Now consider |Φ+⟩ = (1/√2)(|00⟩ + |11⟩), read 'phi-plus'. Suppose Alice's particle were in a|0⟩ + b|1⟩ and Bob's in c|0⟩ + d|1⟩. Multiplying out gives a·c|00⟩ + a·d|01⟩ + b·c|10⟩ + b·d|11⟩. To match |Φ+⟩, a·d and b·c must vanish while a·c and b·d both equal 1/√2. But if a·d is zero, then a or d is zero, which destroys a·c or b·d. No assignment works, and that is the definition: a state of two systems is entangled when it cannot be written as a product of states of the individual systems. The quick test: α|00⟩ + β|01⟩ + γ|10⟩ + δ|11⟩ is a product exactly when αδ − βγ = 0; for |Φ+⟩ it is one half.
Pause on what this means. The pair is in a pure state, the most complete description quantum mechanics allows, yet neither particle has a state of its own. Erwin Schrödinger, who coined the word entanglement in 1935, called it 'not one but rather the characteristic trait of quantum mechanics, the one that enforces its entire departure from classical lines of thought'. Know everything about two dice and you know each die; in an entangled pair, the information lives in the relationship.
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Perfect Agreement, Perfect Randomness
Make the qubits photons, 0 for horizontal and 1 for vertical, and give Alice and Bob each a polarisation analyser, a polarising beam splitter that sends every photon to one of two detectors: 'pass' if it is found along the analyser's axis, 'blocked' if found perpendicular to it. With both analysers horizontal, the Born rule (Chapter 9) gives one half for both pass, one half for both blocked and zero for a mismatch. They agree on every pair, yet neither can predict a single result: each sees a sequence as random as fair coin tosses.
Now rotate both analysers to the same new angle, say 30 degrees. The agreement does not suffer, because |Φ+⟩ has the same form in every basis of linear polarisation: it equals (1/√2)(|θ⟩|θ⟩ + |θ + 90°⟩|θ + 90°⟩) for any angle θ, an equal superposition of 'both along θ' and 'both perpendicular to θ'. Matched analysers at any angle give perfect correlation, while each local outcome stays perfectly random. The correlation is not stored in either photon. It belongs to the pair.
Ordinary correlations are different. In his 1981 essay 'Bertlmann's socks and the nature of reality', John Bell described his colleague Reinhold Bertlmann, who always wore socks of different colours: see one pink sock and you know the other is not pink, because the colours were fixed when he dressed. The quantum version of the socks is a mixture, a source emitting |HH⟩ or |VV⟩ at random. It agrees perfectly at matched horizontal settings, but at matched 45-degree settings each photon passes with probability one half independently of its partner, so pairs agree only half the time, while |Φ+⟩ still agrees every time. Superposition is not ignorance (Chapter 15).
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Einstein's Challenge: Is Quantum Mechanics Complete?
On 15 May 1935 Physical Review published a four-page paper by Albert Einstein and his younger associates Boris Podolsky and Nathan Rosen of the Institute for Advanced Study in Princeton: 'Can Quantum-Mechanical Description of Physical Reality Be Considered Complete?' EPR demanded that a complete theory contain a counterpart for every element of physical reality, and offered a test for one: if, without in any way disturbing a system, we can predict with certainty the value of a physical quantity, then there exists an element of physical reality corresponding to it.
Their thought experiment used two particles that interact and fly apart with perfectly correlated positions and perfectly anticorrelated momenta, which is allowed because the relative position x₁ − x₂ and the total momentum p₁ + p₂ are compatible observables: in their commutator, particle 1's iħ cancels particle 2's. Measure particle 1's position and you can predict particle 2's with certainty; measure its momentum instead and you can predict particle 2's. If nothing done here can disturb a particle far away, an assumption called locality, then particle 2 must have a definite position and a definite momentum together. No quantum state assigns both (Chapter 8), so, EPR concluded, the quantum description is incomplete.
The natural completion is a hidden-variable theory: extra properties, fixed when the pair is created and carried by each particle, that settle in advance what every measurement will give. It is local if each outcome depends only on that particle's hidden variables and its own detector's setting, never on a distant one, exactly like Bertlmann's socks. Niels Bohr replied that October, under the same title, that the EPR criterion of reality is ambiguous. In 1951 David Bohm recast the argument with two spin-one-half particles of total spin zero, the two-outcome form that later experiments, usually with photon polarisation, put to the test. Einstein's famous phrase came in a 1947 letter to Max Born: physics, he insisted, should be free of 'spooky actions at a distance'.
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Turning the Dials: Correlation Versus Angle
To handle mismatched settings, score each result +1 (pass, or spin up) or −1 (blocked, or spin down), and define the correlation E as the average product of Alice's and Bob's scores: the probability that they agree minus the probability that they disagree. E = 1 is perfect agreement, E = −1 perfect disagreement, and E = 0 means no more relation than two independent coins.
For photons in |Φ+⟩, put Alice's analyser at angle α and Bob's at β. The amplitude for both to pass is cos(α − β) divided by √2, so both pass with probability one half times cos²(α − β), and both are blocked equally often: coincidences follow the cosine squared of the relative angle θ = α − β. Agreement has probability cos²θ, and the correlation is the cosine of twice the angle, E = cos 2θ: 1 at 0 degrees, 0.71 at 22.5, 0.5 at 30, zero at 45 and −1 at 90. It is Malus's law of 1809, the rule that a polariser passes a fraction cos²θ of polarised light, reborn as a law about pairs.
Bohm's spin version adds one twist. In the singlet |Ψ−⟩ = (1/√2)(|↑↓⟩ − |↓↑⟩), Stern–Gerlach magnets along the same axis always give opposite results. Tilt Bob's magnet by θ, and Chapter 17's rule for spin at an angle, cos²(θ/2), gives the probability of opposite results, so the correlation is minus the cosine of the angle, E = −cos θ. Spins use half-angles because two spin states are mutually exclusive when their axes are 180 degrees apart, while two polarisation states are mutually exclusive at only 90 degrees. A polariser turned by θ behaves like a magnet turned by 2θ.
Could hidden variables mimic these curves? In the simplest local model, drawn beside the quantum curve in the lab, each pair carries a shared, randomly chosen hidden polarisation angle, and each analyser outputs 'pass' if its axis lies within 45 degrees of it. Each side alone sees fifty-fifty, and the model matches quantum mechanics at 0, 45 and 90 degrees, but in between its correlation falls along a straight line, E = 1 − 4θ/π with θ in radians: 0.50 at 22.5 degrees, where quantum mechanics predicts 0.71 and experiments agree. In 1964 John Bell proved that no local model can match the quantum predictions for every combination of settings.
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Why You Cannot Text Through Entanglement
Here is the scheme every first-year student pitches to me. Alice and Bob share entangled pairs a light-year apart, and Alice encodes a message by switching her analyser between two angles. With her analyser at angle θ to Bob's, his photon passes either together with hers, with probability one half times cos²θ, or while hers is blocked, with probability one half times sin²θ. Since cos²θ + sin²θ = 1, the total is exactly one half whatever θ is, and still one half if Alice measures nothing at all. This is no-signalling, and the no-communication theorem guarantees it for every entangled state and any operation Alice performs on her own particle.
The correlations are real, but they live only in the comparison. Each list alone looks like noise, and the cosine law emerges only when the lists are lined up pair by pair, which needs an ordinary channel at or below the speed of light. Nor can Alice choose her outcomes: she chooses the question, never the answer. If she could force her photon to pass, she would force Bob's, and relativity would be in ruins. Nature's randomness is the bodyguard of causality.
Does Alice's measurement at least push Bob's photon into line? Textbook quantum mechanics updates the joint state once Alice records 'pass' at angle α, describing Bob's photon as polarised along α. Whether that update is a physical change or a revision of information depends on interpretation (Chapter 22): pilot-wave theory posits a nonlocal influence that can never be harnessed to signal, many-worlds denies collapse altogether, and information-based views call it bookkeeping. All agree that Bob's own statistics never change, so no energy is delivered and no message crosses. And when the measurements are too far apart for light to link them, relativity lets observers disagree about which came first, so 'Alice pushed Bob' and 'Bob pushed Alice' fit the data equally well, and no experiment can single out a pusher.
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Manufacturing Entanglement: Parametric Down-Conversion
Entangled pairs arise when two systems are born together under a shared conservation law. Early sources were atomic cascades, in which an excited calcium atom emits two photons in quick succession with correlated polarisations, measured by Carl Kocher and Eugene Commins at Berkeley in 1967. Since the late 1980s the workhorse has been spontaneous parametric down-conversion, or SPDC, in a nonlinear crystal such as beta-barium borate, whose response to light is not strictly proportional to the field, letting light waves mix. Occasionally a pump photon vanishes and two lower-energy photons, the signal and the idler, are born at the same instant.
Spontaneous: no input beam triggers the split; it is seeded by vacuum fluctuations. Parametric: the crystal ends exactly as it began, keeping no energy. Down-conversion: each daughter has a lower frequency than its parent. Energy conservation makes the reciprocals of the wavelengths add, 1/λ_pump = 1/λ_signal + 1/λ_idler, so a violet pump photon of wavelength 405 nm and energy 3.06 eV can become two photons of wavelength 810 nm and energy 1.53 eV each. Momentum conservation, called phase matching, sends the pair out on opposite sides of the pump beam. The process is feeble: even optimised waveguide sources convert only a few pump photons per million, and bulk crystals far fewer.
Polarisation entanglement needs one more trick. In type-II down-conversion, one daughter emerges horizontally polarised and the other vertically, along two cones of light tilted away from the pump. Where the cones intersect, a photon could be the horizontal one from the first cone or the vertical one from the second, and nothing records which. As in the double-slit experiment of Chapter 7, indistinguishable alternatives add as amplitudes, so the pair emerges in a superposition of 'H here, V there' and 'V here, H there', which birefringent plates can turn into any Bell state, including |Φ+⟩. Paul Kwiat, Anton Zeilinger and colleagues reported this bright source in December 1995.
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Entanglement as a Resource
Since the 1990s entanglement has been treated as a resource, counted in ebits, one ebit being one maximally entangled pair. Teleportation, proposed in 1993 by Charles Bennett and five colleagues, transfers an unknown quantum state from Alice to Bob: Alice makes a joint measurement on the particle carrying the state and her half of a shared pair, and sends Bob two ordinary bits; Bob applies one of four corrections, and his particle takes on the original state while Alice's measurement erases it from her particle, so no copy is made. Until the bits arrive, Bob's particle is pure noise. Zeilinger's group in Innsbruck demonstrated teleportation with photons in 1997.
In 1991 Artur Ekert proposed entanglement-based cryptography: Alice and Bob measure shared pairs at random settings, turn the matched results into a shared secret key, and use the rest to test the correlations, which an eavesdropper cannot touch without degrading them detectably. In 2017 the satellite Micius distributed entangled photon pairs to two ground stations 1,203 kilometres apart. In computing, the Hadamard and CNOT gates of Chapter 23 turn |00⟩ into |Φ+⟩ in two steps, and large-scale entanglement is an essential ingredient of quantum algorithms, though by itself it guarantees no speed-up.
Two properties make the resource precious. Entanglement is monogamous: a particle maximally entangled with one partner cannot be entangled with any other, which is why an eavesdropper cannot share the correlations. And it is fragile: stray interactions with the environment spread it away, the decoherence of Chapter 22, so protecting entanglement is the central engineering challenge of quantum technology.
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Go deeper on video
28 more videos for this chapter, 24 of them from universities, research institutes and Nobel lectures. The clips under “Watch this part” in the lesson start at the moment that matters.
Key equations
The Bell state phi-plus
An equal superposition of 'both qubits 0' and 'both qubits 1'. It cannot be factored into a state for each particle, so the pair has a definite joint state while neither particle has a state of its own.
| Symbol | Meaning | Unit |
|---|---|---|
| |00⟩, |11⟩ | both qubits 0 (for photons, both horizontal) and both qubits 1 (both vertical); first digit Alice's, second Bob's | dimensionless (state vectors) |
| 1/√2 | amplitude of each term; its square, one half, is the probability of each outcome when both measure in the 0/1 basis | dimensionless |
Say it: “ket phi plus equals one over root two, times ket zero zero plus ket one one”
Product test and concurrence
For a normalised pure state of two qubits, a vanishing αδ − βγ means the state factorises. The concurrence C measures how entangled it is, from 0 for a product state to 1 for a maximally entangled state such as any Bell state.
| Symbol | Meaning | Unit |
|---|---|---|
| α, β, γ, δ | complex amplitudes of the four basis states, with |α|² + |β|² + |γ|² + |δ|² = 1 | dimensionless |
| C | concurrence, a measure of two-qubit entanglement | dimensionless, 0 to 1 |
Say it: “alpha ket zero zero plus beta ket zero one plus gamma ket one zero plus delta ket one one is a product state exactly when alpha delta minus beta gamma equals zero; the concurrence C equals twice the magnitude of alpha delta minus beta gamma”
Polarisation correlation of entangled photons
For photon pairs in the phi-plus state, the probability that Alice and Bob get the same result follows the cosine squared of the angle between their analysers. The correlation is 1 at 0 degrees, 0 at 45 degrees and −1 at 90 degrees.
| Symbol | Meaning | Unit |
|---|---|---|
| α, β | angles of Alice's and Bob's polarisation analysers | degrees or rad |
| θ | relative angle between the analysers | degrees or rad |
| E | correlation: average of the product of the ±1 results | dimensionless, −1 to 1 |
Say it: “P same equals cosine squared theta; the correlation E of theta equals P same minus P different, which equals cosine of two theta, where theta is alpha minus beta”
Spin singlet correlation
Two spin-one-half particles with total spin zero. Along the same axis their results are always opposite; with Stern–Gerlach axes θ apart, opposite results have probability cos²(θ/2), so the correlation is minus the cosine of θ.
| Symbol | Meaning | Unit |
|---|---|---|
| |↑↓⟩ | Alice's particle spin up, Bob's spin down, along the measurement axis | dimensionless |
| θ | angle between the two Stern–Gerlach axes | degrees or rad |
Say it: “ket psi minus equals one over root two, times ket up down minus ket down up; its correlation E of theta equals minus cosine theta”
No-signalling
Bob's photon passes either with Alice's or while Alice's is blocked. The two routes always sum to one half, whatever angle Alice chooses, so Bob's own data carry no trace of her choice.
| Symbol | Meaning | Unit |
|---|---|---|
| P_B(pass) | probability that Bob's photon passes his analyser, ignoring Alice's results | dimensionless |
| θ | angle between Alice's and Bob's analysers | degrees or rad |
Say it: “Bob's probability of pass equals one half cosine squared theta, plus one half sine squared theta, which equals one half”
Energy and momentum in down-conversion
Energy conservation, written with wavelengths because photon energy is hc divided by λ, and momentum conservation (phase matching) inside the crystal. Together they fix the colours and directions of the photon pairs.
| Symbol | Meaning | Unit |
|---|---|---|
| λ_p, λ_s, λ_i | vacuum wavelengths of the pump, signal and idler photons | m (often nm) |
| k_p, k_s, k_i | wave vectors inside the crystal; momentum is ħ times k | rad/m |
Say it: “one over lambda p equals one over lambda s plus one over lambda i, and the pump wave vector equals the signal wave vector plus the idler wave vector”
Real numbers, step by step
Cover the steps, try the problem yourself, then reveal the solution one step at a time.
Entangled or not?
Classify each two-qubit state as a product state or an entangled one, and find its concurrence C, which is twice the magnitude of αδ − βγ. (a) (1/2)(|00⟩ + |01⟩ + |10⟩ + |11⟩). (b) (1/2)(|00⟩ + |01⟩ + |10⟩ − |11⟩). (c) √0.9 |00⟩ + √0.1 |11⟩.
Step 1: (a) All four amplitudes are one half, so αδ − βγ = 0.25 − 0.25 = 0. It is a product state, C = 0: each qubit is separately in (1/√2)(|0⟩ + |1⟩).
Step 2: (b) Now δ = −0.5, so αδ − βγ = −0.25 − 0.25 = −0.5, and C = 2 × 0.5 = 1. One minus sign makes it maximally entangled; it is |Φ+⟩ with a Hadamard gate applied to the first qubit.
Step 3: (c) Here β = γ = 0, so αδ − βγ = √0.9 × √0.1 = √0.09 = 0.3, and C = 0.6. The state is entangled, but less than maximally.
(a) product, C = 0; (b) maximally entangled, C = 1; (c) partially entangled, C = 0.6
Why it matters: Entanglement lives in the relationships among amplitudes, not in any single one: flipping one sign turned a product state into a Bell state in disguise.
Counting coincidences at 30 degrees
A source sends 10,000 photon pairs in the state |Φ+⟩. Alice's analyser is at 0 degrees and Bob's at 30 degrees. Predict the four tallies, the correlation E, and Alice's own pass count, then compare with the straight-line local hidden-variable model.
Step 1: Both pass: (1/2)cos²30° = 0.5 × 0.75 = 0.375, about 3,750 pairs. Both blocked: also 0.375, about 3,750.
Step 2: Mismatches: (1/2)sin²30° = 0.5 × 0.25 = 0.125 each way, about 1,250 pass-block and 1,250 block-pass.
Step 3: Correlation: E = (7,500 − 2,500) ÷ 10,000 = 0.50, which matches cos(2 × 30°) = cos 60° = 0.5.
Step 4: Alice alone passes 3,750 + 1,250 = 5,000 times: exactly half, as random as a coin.
Step 5: Local model: E = 1 − 4θ/π with θ = π/6 gives 1 − 2/3 ≈ 0.33, so it predicts agreement in a fraction (1 + E)/2 ≈ 0.667, about 6,667 pairs.
About 7,500 agreements and 2,500 disagreements, so E = 0.50; each side alone passes half the time; the straight-line local model predicts only about 6,667 agreements (E ≈ 0.33)
Why it matters: The difference of 833 agreements in 10,000 pairs is about 18 standard errors, far beyond chance. Real experiments match the quantum prediction, allowing for imperfect equipment.
Spin singlets at 60 and 120 degrees
1,000 spin-singlet pairs are measured with Stern–Gerlach axes 60 degrees apart, and another 1,000 with axes 120 degrees apart. How many pairs give opposite results in each run, and what is E?
Step 1: At 60 degrees, P(opposite) = cos²(30°) = 0.75 and P(same) = sin²(30°) = 0.25, so about 750 pairs are opposite and E = 0.25 − 0.75 = −0.50 = −cos 60°.
Step 2: At 120 degrees, P(opposite) = cos²(60°) = 0.25 and P(same) = sin²(60°) = 0.75, so about 250 pairs are opposite and E = +0.50 = −cos 120°.
Step 3: Each particle alone is still spin up half the time in both runs.
About 750 opposite pairs and E = −0.5 at 60 degrees; about 250 opposite pairs and E = +0.5 at 120 degrees
Why it matters: Halve the spin angle and you get the photon story: 60 degrees between magnets behaves like 30 degrees between polarisers, with the sign flipped because the singlet favours opposite results.
Designing a down-conversion source
A laser of wavelength 405 nm pumps a nonlinear crystal. (a) What wavelength do the photons of a degenerate pair (equal energies) have? (b) If the signal photon is at 780 nm, where is the idler? (c) How many pump photons per second does a 1.0 milliwatt beam deliver?
Step 1: Pump photon energy: E = 1239.84 eV·nm ÷ 405 nm ≈ 3.061 eV.
Step 2: (a) Equal shares give 1.531 eV each, so λ = 1239.84 ÷ 1.531 ≈ 810 nm, exactly twice the pump wavelength.
Step 3: (b) 1/λ_idler = 1/405 − 1/780 per nanometre, so λ_idler = (405 × 780) ÷ (780 − 405) = 315,900 ÷ 375 ≈ 842.4 nm. Check: 1.590 eV + 1.472 eV = 3.061 eV.
Step 4: (c) One pump photon carries hc ÷ λ = (6.626×10⁻³⁴ × 2.998×10⁸) ÷ 4.05×10⁻⁷ ≈ 4.90×10⁻¹⁹ joules, so 1.0×10⁻³ watts ÷ 4.90×10⁻¹⁹ joules ≈ 2.0×10¹⁵ photons per second.
(a) 810 nm; (b) about 842 nm; (c) about 2.0×10¹⁵ pump photons per second
Why it matters: Energy bookkeeping fixes the colours exactly; the pair's polarisation entanglement comes from erasing which-cone information, not from the energy split.
What everyone gets wrong
Read the myth, decide whether you believed it, then bust it.
- Myth #1
Entanglement lets you send messages faster than light.
TruthEach party's own results are perfectly random, with the same statistics whatever the other party does or whether they measure at all; this no-signalling property holds for every entangled state. The correlations show up only when the two records are compared, which needs an ordinary channel no faster than light. Teleportation and entanglement-based cryptography both require such a classical channel.
- Myth #2
Measuring one particle physically pushes or flips the other.
TruthNo energy, signal or other detectable change reaches the far particle: its local statistics are identical whether or not its partner is measured. Textbook quantum mechanics updates the joint state after a measurement, but whether that update is a physical influence is interpretation-dependent, and when the measurements are far apart, relativity lets observers disagree about which came first, so neither can be singled out as the pusher.
- Myth #3
Entangled particles are like a pair of gloves: each had its definite property all along, and measurement just reveals it.
TruthThat is a local hidden-variable picture. It explains perfect agreement at matched settings, but not the full cosine law across all pairs of settings. Pairs that simply leave the source both horizontal or both vertical lose even their agreement when both analysers are turned to 45 degrees, and cleverer pre-set instructions that fix this still fall short at intermediate angles, like the straight line of Part 4. John Bell proved in 1964 that no local hidden-variable model reproduces every quantum prediction, and experiments side with quantum mechanics (Chapter 21).
Your turn at the controls
Welcome to the Entanglement Lab. A source in the middle of the bench fires polarisation-entangled photon pairs in the state |Φ+⟩, one photon to Alice and one to Bob, and you turn both analyser dials. Each side scores +1 when its photon passes and −1 when it is blocked. Live readouts show each side's own pass rate, how often the two agree and the measured correlation E, while a plot builds E against the angle between the analysers beside the quantum curve and the straight line of a local hidden-variable model, and you can swap the source for that model. A separate no-signalling test lets Alice choose her own random angle for every batch, or switch her detector off, while you watch Bob's results.
Your tasks
0/4How it connects to the theory
The perfect agreement at matched settings is |Φ+⟩ keeping the same form in every polarisation basis (Part 2). The curve you trace is E = cos 2θ, built from coincidences that follow cos²θ (Part 4), and the straight line is the simplest local hidden-variable model, which matches quantum mechanics only at 0, 45 and 90 degrees. Bob's stubborn one-half is the no-signalling calculation of Part 5. The three settings you hunt for in the game are the maximum, zero and minimum of that cosine, at 0, 45 and 90 degrees apart, and the gap between the two curves in between is the crack that Bell's theorem pries open in Chapter 21.
Entanglement Lab: Alice and Bob's Correlations loads as you scroll down.
Make it stick
Think TWINS, and picture two identical twins raised on opposite sides of the world. T, Together: the pair has one joint state that will not factor into two separate ones. W, Whatever the angle: correlation depends only on the angle between the settings, cos²θ agreement for photons, E = −cos θ for spin singlets. I, Individually random: each twin alone answers like a fair coin. N, No signal: nothing either twin does changes the other's own statistics; the pattern appears only when notes are compared. S, Source: entangled twins are born together, from a down-converting crystal, a calcium cascade or a spin-zero parent. Run any entanglement claim through TWINS and the hype falls out.
Entangled photons are like a pair of magic scratch cards. Alice and Bob each scratch their own card wherever they like; on its own, each card's result looks like a coin flip, but when the two scratch at the same spot, the results always match, and the further apart they scratch, the less often they match. Where it breaks: real scratch cards have their results printed at the factory, a local hidden-variable story, and Bell's theorem shows that no factory printing can reproduce the cosine law for every pair of scratch positions. The quantum outcomes are not written anywhere in advance.
The whole chapter in one lineEntangled pairs share one state: matched settings give perfect correlation, each result alone is random, correlation follows the angle, and no message passes.
Flashcards
Saved on this device. Knew it moves a card up a box; still learning sends it back to box 1. Boxes 4–5 count as mastered.
Play it into long-term memory
Match the vocabulary, then take the Quiz Show. Score 70% or better to tick it off your checklist.
Vocab Match
Match each term to its definition, against the clock.
- 12 pairs in 2 rounds
- 100 points a match, more on a streak
- −25 per mistake · speed bonus each round
- Finish with 3 mistakes or fewer to win
Dr. Q's Quantum Quiz Show
Welcome, contestants! 8 questions, 30 seconds each, and one mad scientist judging you, lovingly. Answer fast for a speed bonus; answer right in a row and your points multiply.
- 100 per answer
- +100 speed bonus
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Prove it on paper
Answer every question, check your work, and read the explanations — the stretch challenge is for the truly mad.
Work through these questions with the lesson closed first, then check yourself against it. For calculations, show every step and keep three significant figures. Use cos²θ for the agreement of photon pairs in |Φ+⟩, E = −cos θ for spin singlets, hc = 1239.84 eV·nm, h = 6.626×10⁻³⁴ J·s and c = 2.998×10⁸ m/s.
Part A
Vocabulary
- Entanglement
- A property of a joint quantum state of two or more systems that cannot be written as a product of states of the individual systems.
- Product state
- A joint state that factorises into a definite state for each part; also called a separable state.
- Bell states
- The four maximally entangled two-qubit states, Φ+, Φ−, Ψ+ and Ψ−, such as |Φ+⟩ = (1/√2)(|00⟩ + |11⟩).
- Spin singlet
- The two-particle spin state of total spin zero, (1/√2)(|↑↓⟩ − |↓↑⟩), which gives opposite results along any common axis.
- Correlation coefficient
- The average product of two ±1 measurement results, equal to P(same) minus P(different); it runs from −1 to +1.
- EPR argument
- The 1935 argument of Einstein, Podolsky and Rosen that, if locality holds, quantum mechanics is an incomplete description of reality.
- Element of reality
- In the EPR paper, a physical quantity whose value can be predicted with certainty without in any way disturbing the system.
- Local hidden-variable theory
- A theory in which pre-set properties carried by each particle determine its results, with no dependence on distant detector settings.
- No-signalling
- The fact that one party's local measurement statistics cannot be changed by anything done to a distant entangled partner.
- Spontaneous parametric down-conversion
- Splitting of one pump photon into a signal and an idler photon inside a nonlinear crystal, conserving energy and momentum.
- Ebit
- One unit of entanglement: a single maximally entangled pair of qubits, such as a Bell state.
- Monogamy of entanglement
- The rule that a qubit maximally entangled with one partner cannot be entangled with any other system.
Part B
Questions
Auto-checked except short answers, which you mark yourself.
- Question 1.Multiple choice
Which of these two-qubit states is entangled?
- Question 2.True or false
With matched analysers on |Φ+⟩ photon pairs, Alice can predict her own next result because she knows the pairs always agree.
- Question 3.Fill in the blank
Einstein, Podolsky and Rosen argued in 1935 that quantum mechanics is , because quantities that can be predicted with certainty are not all assigned definite values.
- Question 4.Multiple choice
In John Bell's essay about Bertlmann's socks, what explains the correlation between the colours of the two socks?
- Question 5.True or false
By looking only at his own list of results, Bob can tell whether Alice has measured her photons yet.
- Question 6.Fill in the blank
In spontaneous parametric down-conversion, one pump photon splits into a signal photon and an photon.
- Question 7.Multiple choice
Why do photons emerging where the two type-II down-conversion cones intersect carry polarisation entanglement?
- Question 8.True or false
Quantum teleportation requires an ordinary classical channel in addition to a shared entangled pair.
- Question 9.Short answer
A source emits either |HH⟩ or |VV⟩ at random. Explain how Alice and Bob can distinguish it experimentally from a source of |Φ+⟩ pairs.
- Question 10.Short answer
State the EPR criterion of reality and explain where the assumption of locality enters their argument.
- Question 11.Calculation
Alice and Bob measure 2,000 |Φ+⟩ photon pairs with analysers 22.5 degrees apart. How many pairs should agree, and what is the correlation E? What does the straight-line local hidden-variable model, E = 1 − 4θ/π, predict instead?
This one asks for more than one value — give each, with its units.
- Question 12.Calculation
Two spin-singlet particles are measured with Stern–Gerlach axes 45 degrees apart. Find the probability of opposite results, the probability of matching results, and the correlation E.
Give a number and units. 6.63×10⁻³⁴, 6.63e-34 and 6.63 x 10^-34 all work.
- Question 13.Calculation
A 532 nm green laser pumps a down-conversion crystal, and the signal photon is detected at 810 nm. At what wavelength is the idler, and how do the photon energies balance?
This one asks for more than one value — give each, with its units.
- Question 14.Calculation
Bob keeps his analyser at 0 degrees. Alice switches hers between 25 degrees and 70 degrees, hoping to send a signal. For each of Alice's settings, find the probability that Bob's photon passes, splitting it into the cases where Alice's photon passes and where it is blocked.
Give a number and units. 6.63×10⁻³⁴, 6.63e-34 and 6.63 x 10^-34 all work.
Part C · optional, dangerous, extremely rewarding
Mad scientist challenge
Build the local hidden-variable model of Part 4 and catch it out. Each photon pair carries a hidden polarisation angle λ, chosen uniformly between 0 and 180 degrees. An analyser at angle α outputs 'pass' if α lies within 45 degrees of λ (counting angles modulo 180 degrees), and 'blocked' otherwise. (a) Show that each side alone passes half the time, whatever its setting. (b) Show that, for analysers θ apart with θ between 0 and 90 degrees, the probability of disagreement is θ ÷ 90°, so E = 1 − θ ÷ 45° (in radians, E = 1 − 4θ/π). (c) Compare with quantum mechanics, E = cos 2θ: at which angles do they agree, at what angle is the gap largest, and how large is it? (d) Using the standard error √((1 − E²) ÷ N) for the model's E, roughly how many pairs at 22.5 degrees would make the gap five standard errors wide?
Recap & sign-off
Key takeaways
- A two-particle state is entangled when it cannot be written as a product of single-particle states; |Φ+⟩ = (1/√2)(|00⟩ + |11⟩) is the standard example, and a nonzero αδ − βγ flags entanglement.
- Entangled pairs give perfect correlation at matched settings in every basis while each local outcome is completely random; no mixture of unentangled pairs, such as |HH⟩ or |VV⟩ at random, can do both.
- The 1935 EPR paper used locality and a criterion of reality to argue that quantum mechanics is incomplete, inviting local hidden variables.
- Correlation depends only on the angle between settings: photon coincidences follow cos²θ with E = cos 2θ, and spin singlets give E = −cos θ.
- No-signalling: Bob's own statistics stay at one half whatever Alice does, and the correlations appear only when records are compared through ordinary channels.
- Spontaneous parametric down-conversion splits a pump photon into a signal and an idler, conserving energy and momentum; erasing which-cone information makes them polarisation-entangled.
- Entanglement is a monogamous, fragile resource that powers teleportation, entanglement-based cryptography and quantum computing.
Dr. Q signs offScience is the only madness with receipts, and today's receipts are coincidence counts. You watched two photons share one state, agree perfectly at matched settings, drift apart along a cosine as the analysers turned, and still refuse to carry a single message. But one question nags: could they have carried hidden instructions all along, like Bertlmann's socks? Next session John Bell turns that question into an inequality, and the experiments of Clauser, Aspect and Zeilinger turn it into a verdict. Chapter 21: Bell's Theorem and the End of Local Realism.
Your chapter checklist
Tick these off in any order. It's a guide, not a law of physics — you can mark the chapter complete whenever you're ready.
- Listen to the whole lesson (not yet)Or read it all — but the voice is more fun.
- Win the lab challenge (not yet)Entanglement Lab: Alice and Bob's CorrelationsGo to the lab
- Score 70% or more on the Quiz Show (not yet)Six to eight questions, no penalties for guessing.Take the quiz
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Sources & further reading
- Stanford Encyclopedia of Philosophy — The Einstein-Podolsky-Rosen Argument in Quantum Theory · plato.stanford.edu
- Stanford Encyclopedia of Philosophy — Quantum Entanglement and Information · plato.stanford.edu
- NobelPrize.org — The Nobel Prize in Physics 2022: popular science background on entangled states · nobelprize.org
- Yin et al. (2017), Satellite-based entanglement distribution over 1200 kilometers (arXiv) · arxiv.org
- MIT OpenCourseWare — 8.04 Quantum Physics I (Allan Adams, Spring 2013), lecture notes and videos · ocw.mit.edu