Unit 4 · Atoms, Spin & IdentityChapter 17 of 25

Spin & the Stern–Gerlach Experiment

A tiny magnet that refuses to point anywhere in between

  • 22 min read
  • 32 min listen
  • 21 videos
01Video briefing

Start with the preview

Start here — today's preview. Watch “The First Quantum Spin Detector (Stern-Gerlach Experiment)” from The Science Asylum before (or after) this session. The lab will wait. Mostly.

Today's preview

The First Quantum Spin Detector (Stern-Gerlach Experiment)

The Science Asylum9 min

Nick Lucid of The Science Asylum retells the 1922 experiment at an ideal pace for a first look, including the twist that the experimenters had detected spin years before anyone knew spin existed. As you watch, hold the classical expectation in mind, a continuous smear of deflected atoms, and ask yourself why two clean stripes were such a shock.

Watch on YouTube

More from the video vault

Deep dive

4. Spin One-half, Bras, Kets, and Operators

MIT OpenCourseWare85 min

Lecture 4 of MIT's 8.05 Quantum Physics II (Fall 2013), in which Barton Zwiebach builds the machinery of spin one-half: its states and operators, the properties of the Pauli matrices, and spin states along an arbitrary direction, the general form of this session's cos²(θ/2) rule. Best watched after the lesson; it assumes the bra-ket notation of chapter 14.

Watch on YouTube
Bonus

Electrons DO NOT Spin

PBS Space Time18 min

Matt O'Dowd dismantles the spinning-ball picture and follows spin into the stranger geometry underneath it, with Jason Hise's animations of objects that need two full turns to return to their starting state. A companion to this lesson's spinning-ball myth and its 720-degree electron.

Watch on YouTube
  • The First Quantum Spin Detector (Stern-Gerlach Experiment) — The Science Asylum — https://www.youtube.com/watch?v=y7tEacBelmk
  • 4. Spin One-half, Bras, Kets, and Operators — MIT OpenCourseWare — https://www.youtube.com/watch?v=BWM0RXg-uvI
  • Electrons DO NOT Spin — PBS Space Time — https://www.youtube.com/watch?v=pWlk1gLkF2Y
02Cold open

Today's mission

Dr. Q · cold open

Psigor, fire up the oven! Silver, one thousand degrees Celsius, and fetch me the cheapest cigar you can find; I will explain the cigar later. Last session the hydrogen atom handed you three quantum numbers, n, l and mₗ, and I promised that a fourth, the spin number mₛ, would get a night of its own. This is that night. We shall fire atoms between the poles of a lopsided magnet, where common sense says they must smear into a continuous band, and watch them land in exactly two stripes with nothing in between. Then we chain magnets together, ask the atoms rude questions, and catch them forgetting their answers. By midnight you will know why an electron must turn around twice to come home. I'm mad, not wrong.

By the end of this session you will be able to:

  1. Describe the 1922 Stern-Gerlach experiment and explain why two separated beams, rather than a smear, show that a component of an atom's angular momentum is quantized.
  2. Explain what spin is, why the electron cannot be a tiny spinning ball, and why a spin-one-half particle measured along any axis gives only +ħ/2 or −ħ/2.
  3. Predict the outcomes of chained Stern-Gerlach measurements, Z then Z, Z then X, and Z then X then Z, using the states |↑⟩, |↓⟩ and |+x⟩ = (1/√2)(|↑⟩ + |↓⟩).
  4. Calculate probabilities, expected counts and average spin components for a magnet tilted at any angle, using P(up) = cos²(θ/2).
  5. Explain why a 360-degree rotation reverses the sign of a spin-one-half state, and how neutron interferometers detected that sign.
  6. Compute magnetic resonance frequencies for electrons and protons, and explain how MRI and electron spin resonance put spin to work.
03The lesson

Read it — or listen along

7 parts. Press play on any part and the paragraph being read lights up as Dr. Q speaks.

Part 1

Magnets That Feel the Slope

Last session named a fourth quantum number, the spin number mₛ, without explaining it. Its story begins with magnetism. Circulating charge produces a magnetic moment, a measure of how strongly something behaves like a bar magnet, written μ and measured in joules per tesla. An electron with orbital angular momentum is a tiny current loop, so atoms should behave like miniature compass needles. The natural unit is the Bohr magneton, μB = eħ/2mₑ, about 9.27×10⁻²⁴ joules per tesla, the moment of an electron orbit carrying one unit, ħ, of angular momentum.

In a uniform magnetic field a compass needle feels a torque, a twist toward alignment, but no net push: its two poles are pulled equally hard in opposite directions. To push a magnet sideways you need a field gradient, a field that changes from place to place, so that one pole sits in a stronger field than the other. If the field strengthens along a direction we call z, the force is the moment's component along z, μz, times the gradient. A magnet pointing up the slope is pulled toward the stronger field, one pointing down is pushed away, and one lying sideways feels nothing. A beam of atomic magnets is sorted by μz.

That makes a decisive test. Atoms leaving a hot oven point every which way, so classically μz takes every value between −μ and +μ, and the beam should merely broaden into a single continuous smear, with no gap anywhere. The old quantum theory of Bohr and Sommerfeld disagreed: its rule of space quantization let an orbit take only certain orientations relative to a field, so the beam should break into separate stripes. In 1921 Otto Stern, then working at Max Born's institute in Frankfurt, saw that an atomic beam could decide between the two. The idea, he later recalled, came to him early one morning in a bed too cold to leave.

Part 2

Frankfurt, 1922: Two Stripes and a Cigar

Walther Gerlach, an experimenter in the neighbouring institute, built the apparatus with Stern; it took more than a year to work. Silver vapour from an oven at about 1,000 degrees Celsius was trimmed into a narrow beam by slits 0.03 millimetres wide, then flew 3.5 centimetres between shaped magnet poles producing a field of about 0.1 tesla that changed by roughly 10 tesla per centimetre. The expected splitting was a fraction of a millimetre, so a misalignment of 0.01 millimetres could spoil a run, and the apparatus rarely ran more than a few hours between breakdowns.

The silver deposits were about one atom thick and invisible to the eye. In Stern's telling, an early plate showed nothing until he peered at it closely: his cheap cigars were rich in sulfur, his breath turned the silver into jet-black silver sulfide, and the trace emerged like a developing photograph. When Friedrich and Herschbach re-enacted the scene in 2002, breath alone did nothing but cigar smoke blackened the film, so the smoke probably did the work. Early in 1922 the two men met in Göttingen and agreed to give up. Then a railway strike stranded Gerlach on the way home; he spent the day rethinking every detail, improved the alignment, and soon the beam split. A postcard to Niels Bohr, dated 8 February 1922, carried a photograph of the result: 'Attached is the experimental proof of directional quantization. We congratulate you on the confirmation of your theory.'

The plate looked like a pair of lips. Where the gradient was strongest, the trace divided into two separate bands with an empty gap between them, merging only at the ends, where the gradient weakened. No atom arrived undeflected. Each was pushed up or down by an amount set by its speed, and from the size of the split Stern and Gerlach found the silver atom's moment to be one Bohr magneton, within about 10 percent. Not a smear but two stripes: a component of an atom's magnetism, and therefore of its angular momentum, takes only discrete values.

Watch this part

Part 3

Spin: Angular Momentum With Nothing Spinning

The answer came from spectroscopy. In late 1924 Wolfgang Pauli, puzzling over the anomalous Zeeman effect, in which spectral lines in a magnetic field split into more components than any orbit allowed, concluded that the electron carries a 'two-valuedness not describable classically'. Early in 1925 Ralph Kronig proposed that the electron rotates about its own axis, and Pauli's scorn kept him from publishing. That autumn in Leiden, George Uhlenbeck and Samuel Goudsmit had the same idea, and their mentor Paul Ehrenfest sent it to a journal. As Goudsmit remembered it, Ehrenfest told them the idea might be wrong, but with no reputation yet they had nothing to lose.

The spinning ball did not survive; the name did. Spin is intrinsic angular momentum: angular momentum that belongs to a particle itself, like its charge or mass, rather than to any motion through space. Electrons, protons, neutrons and quarks all have spin quantum number s = ½. Measured along any axis, the spin component is mₛħ with mₛ = ±½, that is, +ħ/2 or −ħ/2, about 5.27×10⁻³⁵ J·s. The rule that gives orbital motion 2l + 1 orientations gives spin 2s + 1 = 2, hence two stripes. In silver, 46 of the 47 electrons pair off, their spins and orbits cancelling for reasons that are next chapter's business, leaving one outer electron in the fifth shell's s orbital, with l = 0. Magnetically, a silver atom is a single electron spin.

Why not a spinning ball? Three fatal reasons. Size: the electron behaves as a point in every experiment so far, and even a ball as large as the classical electron radius, 2.8×10⁻¹⁵ metres, would need a surface speed above a hundred times the speed of light to carry ħ/2. Magnetism: a ball with charge and mass spread alike has a g-factor, the ratio of magnetism to angular momentum in natural units, of 1; electron spin has a g-factor of 2.0023, which is why a silver atom's moment is a full Bohr magneton. Counting: orbital angular momentum always has whole-number l and an odd number of orientations. Two stripes demand a half-integer.

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Part 4

Z, Then X, Then Z: Questions That Erase Answers

Treat a Stern-Gerlach magnet as a question. A magnet whose gradient points along z asks 'up or down along z?', and its two exits are the two answers, the states |↑⟩ and |↓⟩. In the language of chapter 14 they are eigenstates of the z-spin operator, with eigenvalues +ħ/2 and −ħ/2. Turn the magnet 90 degrees about the beam and it asks the same question along x, with answers |+x⟩ and |−x⟩. Written in the z language these are equal-weight superpositions: |+x⟩ = (1/√2)(|↑⟩ + |↓⟩) and |−x⟩ = (1/√2)(|↑⟩ − |↓⟩). Block one exit with a stop and the magnet becomes a filter passing a single answer.

Now chain the magnets, in the idealized experiments that open Sakurai's textbook and anchor Feynman's Lectures. Z then Z: send the up atoms from one Z magnet through another, and every one exits up; asking again changes nothing. Z then X: send them into an X magnet instead, and they split fifty-fifty, because |↑⟩ = (1/√2)(|+x⟩ + |−x⟩) and each amplitude squared is one half. Perhaps each atom carries two hidden labels, one for z and one for x. Z then X then Z: send only the +x atoms into a final Z magnet. Hidden labels would bring every atom out up, since we filtered for up at the start. Instead, half come out down.

The X magnet did not read a pre-existing label. It measured, leaving each atom in |+x⟩, a state with no definite z value, so the final magnet tosses fresh quantum dice. As chapter 15 showed, z and x spin are incompatible observables: their operators do not commute, so no state has a definite value of both. A spinning top has a definite component along every axis at once. An atom has a definite answer to one spin question at a time, and a new question wipes out the old answer.

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Part 5

Tilted Magnets and the Half-Angle Rule

Tilt a magnet by an angle θ from z, in the plane across the beam, and it asks 'up or down along this axis?' Its up state is |↑θ⟩ = cos(θ/2)|↑⟩ + sin(θ/2)|↓⟩. Check: at θ = 0 it is |↑⟩; at θ = 90°, cos 45° = sin 45° = 1/√2, giving |+x⟩; at θ = 180° it is |↓⟩, since up along minus z is down along z. The Born rule of chapter 9 then gives the odds for an atom known to be up along z: P(up along θ) = cos²(θ/2). At 0, 60, 90, 120 and 180 degrees the chance of up is 1, three-quarters, one half, one quarter and 0.

Why half the angle? Up and down are opposite directions in space, yet they are perfectly distinguishable states, and perfectly distinguishable states must have zero overlap, like perpendicular arrows. A 180-degree turn in space must therefore be a 90-degree turn between state arrows, so every angle in space is halved in the space of states. Photon polarization, by contrast, obeys Malus's cos²θ with no halving, because its perfectly distinguishable pair, horizontal and vertical, is only 90 degrees apart.

This rule settles the myth that spin can point in any direction when measured. A spin can be prepared along any direction you like: atoms leaving a tilted magnet's up exit are in |↑θ⟩. But a measurement along any axis returns only +ħ/2 or −ħ/2, never an in-between value. What varies smoothly is the average: the expected component along the tilted axis is (ħ/2)(cos²(θ/2) − sin²(θ/2)) = (ħ/2)cos θ, exactly the projection a classical arrow would give. Single atoms answer in clicks, and only crowds trace out the smooth classical curve. Nor can the spin vector lie exactly along any axis, since its length, √(s(s + 1))·ħ ≈ 0.87ħ, exceeds its largest component, ħ/2.

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Part 6

Turn Twice to Come Home: The 720-Degree Electron

The half angle hides a stranger consequence. Rotating a spin state through an angle α multiplies its amplitudes by cosines and sines of α/2, so a full 360-degree turn, which returns every arrow, top and teapot to its starting position, turns |↑⟩ into −|↑⟩; only after 720 degrees does the state come back to itself. Two-component objects with this property are called spinors; Pauli built them into quantum mechanics in 1927, with the matrices you met in chapter 14. A minus sign in front of a whole state changes no probability, so a lone rotated beam looks untouched. To see the sign you must compare the rotated state with an unrotated copy of itself.

Neutron interferometers do exactly that. A neutron is a spin-one-half particle with a small magnetic moment, and a perfect silicon crystal can split its wave into two paths that later recombine. In 1975 a team led by Helmut Rauch in Vienna, with a young Anton Zeilinger among the authors, and an American team led by Samuel Werner sent one path through a magnetic field that made the neutron's spin precess, wheeling round the field like a tilted top, a motion called Larmor precession. As the field grew, the interference signal rose and fell with a period of 720 degrees of precession, not 360; Rauch's team measured 704 ± 38 degrees. A 360-degree turn on one path turned bright into dark.

No rigid object behaves like this, yet the geometry of rotations permits it. Balance a cup on your flat palm and turn it through one full circle without letting go: your arm ends up twisted. Keep turning the same way through a second circle, sweeping the cup over your head, and your arm comes back untwisted. A belt fixed at one end agrees: after one full turn of the free end, no way of moving that end without turning it removes the twist, while after two full turns one does. Spin-one-half particles carry this two-turn memory of rotation, and in chapter 19 the same sign helps sort every particle into fermions and bosons.

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Part 7

Spin at Work: MRI and Electron Spin Resonance

Because spin carries a magnetic moment, a magnetic field B gives its two states different energies. For an electron the gap is ΔE = g·μB·B, and a photon of exactly that energy, frequency f = ΔE/h, can flip the spin. This is magnetic resonance. Free electrons resonate at about 28.0 GHz per tesla, so near 0.35 tesla the resonance sits at 9.8 GHz, in the microwave band. Yevgeny Zavoisky discovered electron spin resonance in Kazan in 1944. Only unpaired electrons respond, which makes it a sensitive detector of free radicals and crystal defects; its descendants include the diamond quantum sensors of chapter 24.

Protons have spin one-half too, but are about 658 times less magnetic than electrons, so they resonate at radio frequencies, 42.58 MHz per tesla. In 1938 Isidor Rabi, a veteran of Stern's Hamburg laboratory, detected nuclear magnetic resonance in molecular beams; in 1946 Felix Bloch and Edward Purcell found it in ordinary liquids and solids. Magnetic resonance imaging adds an idea Stern and Gerlach would recognize, a field gradient: when the field varies across the body, so does the resonance frequency, and a signal's frequency reveals where it came from. Paul Lauterbur proposed gradient imaging in 1973 and Peter Mansfield made it fast; they shared the 2003 Nobel Prize in Physiology or Medicine.

A 3-tesla hospital scanner therefore works at 127.7 MHz, just above the FM radio band. The energy gap, about 5×10⁻⁷ electron-volts, is tiny beside the thermal energy at body temperature, 0.027 eV, so the lower-energy orientation wins by only about 10 parts per million. But a millilitre of water holds 6.7×10²² hydrogen nuclei, so the imbalance is still about 7×10¹⁷ spins; tipped by a radio pulse, their combined magnetization precesses and induces a voltage in the scanner's coils. That signal is the smooth average of an enormous crowd, the (ħ/2)cos θ curve of the tilted magnets; each nucleus, measured alone, would still answer only up or down.

Watch this part

04Video shelf

Go deeper on video

18 more videos for this chapter, 13 of them from universities, research institutes and Nobel lectures. The clips under “Watch this part” in the lesson start at the moment that matters.

18 videos · 7 h 8 min

  • Lecture · MIT

    The Stern-Gerlach Experiment (ESI College Physics Film Program 1967)

    MIT Physics Instructional Resources Lab · Jerrold R. Zacharias

    A 1967 college physics film featuring MIT's Jerrold Zacharias, a molecular-beam physicist who co-authored Rabi's 1938 magnetic-resonance paper. As you watch, compare the apparatus with section 2's: an oven, collimating slits, shaped magnet poles and a record of where the atoms land.

  • Explainer · YouTube

    Discovery of spin... but missed (Stern-Gerlach experiment, part 2)

    Dr. Jorge S. Diaz

    The second half of physicist Jorge Diaz's two-part history: the experiment had detected spin, and nobody saw it at first. Set it beside section 3's account, from Pauli's 'two-valuedness' to Uhlenbeck and Goudsmit, and section 2's callout on a result that was right for the wrong reason.

  • Demo · University of Göttingen

    Experimental physics IV: 17 - Einstein de Haas effect

    Lehrportal Uni Göttingen

    A short film of the Einstein–de Haas experiment as it is presented in the University of Göttingen's Experimental Physics IV course: the effect in section 3's callout. Watch for the sample's twist when its magnetization flips, the sign that spin is real angular momentum that can be traded for the ordinary kind.

  • Explainer · YouTube

    Superposition of Quantum States

    Up and Atom

    Jade Tan-Holmes of Up and Atom explains quantum superposition through the Stern-Gerlach experiment: the gentlest way into section 4. Watch with the section's puzzle in mind: if an atom from a z magnet's up exit is an equal mix of +x and −x, why does an x magnet split the beam fifty-fifty, and why does the atom then forget its z answer?

  • Explainer · YouTube

    Spinors for Beginners 4: Quantum Spin States (Stern-Gerlach Experiment)

    eigenchris

    This link starts at eigenchris's chapter on the z-oriented Stern-Gerlach experiment, followed by the x-oriented (12:34) and y-oriented (16:01) versions and the Bloch sphere (18:37). These are section 4's z and x questions written as amplitudes, with the y axis as a bonus; the bra-ket and Born-rule chapters at 5:34 and 7:55 are the warm-up.

  • Lecture · MIT

    More on superposition. General state of a photon and spin states

    MIT OpenCourseWare · Barton Zwiebach

    A 17-minute 8.04 segment in which Barton Zwiebach treats a photon's general polarization state and spin states. Keep section 5's contrast in mind: polarization follows Malus's cos²θ, but spin odds follow cos²(θ/2), because opposite spin directions are perpendicular state arrows.

  • Explainer · YouTube

    Dirac's Belt Trick: Why a 2π rotation twists space but a 4π rotation fixes it

    Dr. Trefor Bazett

    Mathematician Trefor Bazett opens with Dirac's belt trick, then explains it with the space of 3D rotations, modelled as a solid ball whose opposite surface points are the same rotation (3:24 and 5:31). The payoff is the 'Deforming the 4π path' chapter at 9:49: why two full turns can be undone and one cannot, as with section 6's belt and cup.

  • Lecture · Institut Laue-Langevin

    25 - Neutron interferometry by Wenke Müller

    Institut Laue Langevin · Wenke Müller

    This link starts at the lecture's chapter on the perfect silicon-crystal interferometer, the kind of device in which section 6's 720-degree sign was first seen. Later chapters cover a historical neutron experiment (15:05), the quantum Cheshire cat (19:03) and the ILL's S18 interferometer instrument (27:15).

  • Lecture · Yale

    22. Medical MRI and Chemical NMR

    YaleCourses · J. Michael McBride

    The lecture's first chapter, up to 16:16, covers tomography, field gradients and magnetic resonance imaging, which is section 7's key idea: a gradient makes the resonance frequency reveal where a signal came from. The next chapter traces how NMR spectroscopy developed.

  • Explainer · YouTube

    I got my quantum spin measured in an MRI

    Looking Glass Universe

    Looking Glass Universe gets her own protons' spins measured in an MRI scanner and explains how the machine uses that spin information to make an image. An easy companion to section 7's closing point: the scanner reads the smooth average of an enormous crowd of spins, yet each one, measured alone, would still answer only up or down.

  • Lecture · MIT

    Lecture 23: More on Spin

    MIT OpenCourseWare · Allan Adams · 2013

    The lecture from MIT 8.04 Quantum Physics I (Allan Adams, 2013) that goes with Chapter 17. The whole course is in the Lecture Hall.

  • Lecture · MIT

    3. Wave Mechanics (continued) and Stern-Gerlach Experiment

    MIT OpenCourseWare · Barton Zwiebach · 2013

    The lecture from MIT 8.05 Quantum Physics II (Barton Zwiebach, 2013) that goes with Chapter 17. The whole course is in the Lecture Hall.

  • Lecture · Oxford

    023 Spin 1/2 , Stern - Gerlach Experiment and Spin 1

    University of Oxford · James Binney · 2009–10

    The lecture from University of Oxford Quantum Mechanics (James Binney, 2009–10) that goes with Chapter 17. The whole course is in the Lecture Hall.

  • Course · MIT

    Quantum Physics I

    MIT OpenCourseWare · Allan Adams · 2013

    Allan Adams' celebrated course starts from superposition and the experimental facts, builds the wavefunction, operators and the Schrödinger equation, then tours scattering, hydrogen, identical particles and band structure before closing on entanglement and Bell's theorem. Calculus and a little linear algebra are enough to keep up.

  • Course · Oxford

    Quantum Mechanics

    University of Oxford · James Binney · 2009–10

    James Binney's Oxford course, given over Michaelmas Term 2009 and Hilary Term 2010 and built on probability amplitudes and Dirac notation from the very first lecture. Highlights: tunnelling and radioactive decay, the EPR argument and Bell's inequality, spin and the Stern–Gerlach experiment, and a full treatment of hydrogen.

  • Course · MIT

    Quantum Physics II

    MIT OpenCourseWare · Barton Zwiebach · 2013

    The sequel: vector spaces and Dirac notation, the uncertainty principle done properly, the Heisenberg picture, two-state systems, tensor products and the addition of angular momentum. The natural next step once Unit 3 of this course feels comfortable.

  • Course · Stanford

    The Theoretical Minimum: Quantum Mechanics

    Stanford · Leonard Susskind · 2012

    Leonard Susskind's course for curious adults, the basis of his book with Art Friedman. It starts from a single spin, builds states, operators and measurement from scratch, then reaches entanglement — one of the cleanest routes from zero to the real formalism.

  • Course · Stanford

    Quantum Entanglements, Part 1

    Stanford · Leonard Susskind · 2006

    Nine evenings on the strangest resource in physics — spin, density matrices, entangled states and Bell's theorem — taught by Susskind to a room of non-specialists. Pairs naturally with Unit 5.

Every video for Chapter 17 in the Video Library

05To the blackboard

Key equations

Equation 1

Spin one-half: the allowed components

Sz=ms ℏ,ms=±12  ⇒  Sz=±ℏ2,∣S⃗∣=s(s+1) ℏ=32 ℏS_z = m_s\,\hbar, \quad m_s = \pm\tfrac{1}{2} \;\Rightarrow\; S_z = \pm\frac{\hbar}{2}, \qquad |\vec{S}| = \sqrt{s(s+1)}\,\hbar = \frac{\sqrt{3}}{2}\,\hbar

Along whichever axis you measure, a spin-one-half particle shows one of exactly two components, plus or minus h-bar over two. The spin vector's length is larger than either component, so it can never lie exactly along the measurement axis. The number of possible components, 2s + 1, equals the number of Stern-Gerlach beams.

What each symbol means
SymbolMeaningUnit
Szcomponent of spin angular momentum along the measurement axisJ·s
mₛspin magnetic quantum number, +½ or −½ for a spin-½ particledimensionless
sspin quantum number, ½ for electrons, protons and neutronsdimensionless
ħreduced Planck constant, 1.055×10⁻³⁴J·s

Say it: “S z equals m s times h-bar, where m s is plus or minus one half, so S z is plus or minus h-bar over two. The length of the spin vector is the square root of s times s plus one, times h-bar, which is root three over two times h-bar”

Equation 2

The Stern-Gerlach force

Fz=μz ∂Bz∂z,μz=−gs e2me Sz=∓ gs2 μB≈∓ μB,μB=eℏ2meF_z = \mu_z\,\frac{\partial B_z}{\partial z}, \qquad \mu_z = -g_s\,\frac{e}{2m_e}\,S_z = \mp\,\frac{g_s}{2}\,\mu_B \approx \mp\,\mu_B, \qquad \mu_B = \frac{e\hbar}{2m_e}

A magnet feels a net sideways force only where the field changes with position, and the force is its moment's component along the gradient times the gradient. Because an electron's spin component has only two values, its magnetic moment component does too, very nearly one Bohr magneton up or down, so a beam splits into two.

What each symbol means
SymbolMeaningUnit
Fzforce along the gradient directionN
μzcomponent of the magnetic moment along zJ/T
∂Bz/∂zfield gradient, about 1,000 T/m in the 1922 magnetT/m
gₛelectron spin g-factor, 2.0023dimensionless
μBBohr magneton, 9.274×10⁻²⁴J/T

Say it: “F z equals mu z times the rate of change of B z along z. For an electron spin, mu z equals minus g s times e over two m e, times S z, which is minus or plus g s over two times the Bohr magneton, approximately minus or plus one Bohr magneton. The Bohr magneton equals e h-bar over two m e”

Equation 3

Spin along x, written in the z basis

∣+x⟩=12(∣↑⟩+∣↓⟩),∣−x⟩=12(∣↑⟩−∣↓⟩)|{+x}\rangle = \frac{1}{\sqrt{2}}\big(|{\uparrow}\rangle + |{\downarrow}\rangle\big), \qquad |{-x}\rangle = \frac{1}{\sqrt{2}}\big(|{\uparrow}\rangle - |{\downarrow}\rangle\big)

A spin with a definite x answer is an equal-weight superposition of up and down along z, so a Z magnet splits it fifty-fifty. Read backwards, up along z is an equal mixture of plus x and minus x, which is why an X magnet splits a Z-filtered beam evenly.

What each symbol means
SymbolMeaningUnit
|↑⟩, |↓⟩spin up and down along z, the eigenstates of the z-spin operatordimensionless
|+x⟩, |−x⟩spin up and down along xdimensionless

Say it: “ket plus x equals one over root two times ket up plus ket down, and ket minus x equals one over root two times ket up minus ket down”

Equation 4

The half-angle rule for a tilted magnet

∣↑θ⟩=cos⁡θ2 ∣↑⟩+sin⁡θ2 ∣↓⟩,P(up along θ)=cos⁡2θ2,⟨Sθ⟩=ℏ2cos⁡θ|{\uparrow_\theta}\rangle = \cos\tfrac{\theta}{2}\,|{\uparrow}\rangle + \sin\tfrac{\theta}{2}\,|{\downarrow}\rangle, \qquad P(\text{up along }\theta) = \cos^2\tfrac{\theta}{2}, \qquad \langle S_\theta\rangle = \frac{\hbar}{2}\cos\theta

For a spin prepared up along one axis and measured along another at angle theta to it, the chance of up is cosine squared of half the angle. Individual results are still only plus or minus h-bar over two; it is the average that follows the smooth classical projection.

What each symbol means
SymbolMeaningUnit
θangle between the axis the spin was prepared along and the axis of the measuring magnetdegrees or rad
P(up along θ)probability of the up result in the tilted magnetdimensionless
⟨Sθ⟩average spin component along the tilted axis over many atomsJ·s

Say it: “ket up theta equals cosine of theta over two times ket up, plus sine of theta over two times ket down. The probability of up along theta equals cosine squared of theta over two, and the average spin component along theta equals h-bar over two times cosine theta”

Equation 5

Rotating a spinor

R^(α)=cos⁡α2 I^−i sin⁡α2 (n⋅σ),R^(360∘)=−I^,R^(720∘)=+I^\hat{R}(\alpha) = \cos\tfrac{\alpha}{2}\,\hat{I} - i\,\sin\tfrac{\alpha}{2}\,(\mathbf{n}\cdot\boldsymbol{\sigma}), \qquad \hat{R}(360^\circ) = -\hat{I}, \qquad \hat{R}(720^\circ) = +\hat{I}

Rotating a spin-one-half state about any axis n involves half the rotation angle. One full turn multiplies every spin state by minus one, a sign that shows up only when the rotated state interferes with an unrotated one; two full turns restore it exactly.

What each symbol means
SymbolMeaningUnit
αrotation angledegrees or rad
nunit vector along the rotation axisdimensionless
σthe three Pauli matrices of chapter 14dimensionless
Îidentity operator, which leaves a state unchangeddimensionless

Say it: “the rotation operator for an angle alpha equals cosine of alpha over two times the identity, minus i times sine of alpha over two times n dot sigma. A rotation by three hundred and sixty degrees equals minus the identity, and a rotation by seven hundred and twenty degrees equals plus the identity”

Equation 6

Magnetic resonance

hf=ΔE=g μ B:fe≈28.0 GHz/T×B,fp≈42.58 MHz/T×Bhf = \Delta E = g\,\mu\,B: \qquad f_e \approx 28.0\ \text{GHz/T} \times B, \qquad f_p \approx 42.58\ \text{MHz/T} \times B

A magnetic field splits the two spin states by an energy proportional to the field, and radiation whose photon energy matches the gap flips spins. Electron spins resonate in the microwave band, the basis of electron spin resonance; proton spins resonate at radio frequencies, the basis of NMR and MRI.

What each symbol means
SymbolMeaningUnit
fresonance frequencyHz
ΔEenergy gap between the two spin statesJ
g·μg-factor times the relevant magneton; for the electron 2.0023 × 9.274×10⁻²⁴; for the proton the gap is twice its moment, 2 × 1.411×10⁻²⁶J/T
Bmagnetic field strengthT

Say it: “h times f equals delta E, which equals g times mu times B. For electrons the resonance frequency is about twenty-eight gigahertz per tesla times B; for protons it is about forty-two point five eight megahertz per tesla times B”

06Worked examples

Real numbers, step by step

Cover the steps, try the problem yourself, then reveal the solution one step at a time.

Example 1

The width of the 1922 split

Problem

Estimate the 1922 splitting. A silver atom (mass 107.87 atomic mass units) with a magnetic moment component of one Bohr magneton, up or down, flies at 600 metres per second through a magnet 3.5 centimetres long whose field gradient is 10 tesla per centimetre, that is, 1,000 tesla per metre. How far is it deflected while in the magnet, and how far apart are the two stripes?

  1. Step 1: Mass: 107.87 × 1.6605×10⁻²⁷ kilograms = 1.791×10⁻²⁵ kilograms.

  2. Step 2: Force: one Bohr magneton times the gradient, 9.274×10⁻²⁴ joules per tesla × 1,000 tesla per metre = 9.27×10⁻²¹ newtons. The atom's weight is 1.791×10⁻²⁵ kilograms × 9.81 m/s² = 1.76×10⁻²⁴ newtons, so the magnetic push is about 5,300 times stronger than gravity.

  3. Step 3: Acceleration: 9.27×10⁻²¹ newtons ÷ 1.791×10⁻²⁵ kilograms = 5.18×10⁴ m/s².

  4. Step 4: Time in the magnet: 0.035 metres ÷ 600 m/s = 5.83×10⁻⁵ seconds.

  5. Step 5: Deflection: one half × 5.18×10⁴ m/s² × (5.83×10⁻⁵ seconds)² = 8.8×10⁻⁵ metres, or 0.088 mm, upward for one spin value and downward for the other.

Answer

About 0.09 mm each way, so the stripes are about 0.18 mm apart, close to the 0.2 mm Stern and Gerlach observed

Why it matters: The deflection grows as one over the speed squared: atoms at 300 m/s are pushed four times as far, 0.35 mm. The spread of speeds from the oven therefore broadens each stripe, but it cannot fill the gap, because no atom has a moment component of zero. The empty middle is the quantum fingerprint.

Try it yourself first — then check each step.
Example 2

A million atoms through three magnets

Problem

One million silver atoms leave the oven. A Z magnet sorts them and the down exit is blocked. The survivors pass an X magnet whose −x exit is blocked, then a final Z magnet. How many atoms leave each exit of the final magnet? Compare with the hidden-label prediction. Then replace the X magnet with one tilted 120 degrees from z, keeping its up exit, and repeat.

  1. Step 1: Oven atoms are unpolarized, so the first Z magnet splits them evenly: 500,000 leave up, in the state |↑⟩.

  2. Step 2: X magnet: |↑⟩ = (1/√2)(|+x⟩ + |−x⟩), so each exit has probability one half; 250,000 continue in |+x⟩, give or take about 350, since √(500,000 × 0.5 × 0.5) ≈ 354.

  3. Step 3: Final Z magnet: |+x⟩ = (1/√2)(|↑⟩ + |↓⟩), so 125,000 leave up and 125,000 leave down.

  4. Step 4: Hidden labels would predict 250,000 up and none down, since every atom passed the first up filter. The 125,000 down atoms refute that picture.

  5. Step 5: Tilted version: the 120-degree magnet passes cos²60° = one quarter of the 500,000 up atoms, so 125,000 continue in |↑θ⟩ with θ = 120°. Measured along z, which is 120 degrees from their spin axis, they give up with probability cos²60° = one quarter: 31,250 up and 93,750 down.

Answer

With the X magnet, 125,000 up and 125,000 down; with the 120-degree magnet, 125,000 pass it and the final magnet gives 31,250 up and 93,750 down

Why it matters: Each magnet answers only its own question and leaves the atom in the matching state; the next magnet's odds depend only on the angle between consecutive axes. That is the whole bookkeeping of this chapter's lab.

Try it yourself first — then check each step.
Example 3

Odds and averages at 60 degrees

Problem

2,000 atoms, all up along z, enter a magnet tilted 60 degrees from z. How many leave its up exit, with what typical scatter, and what is the average spin component along the tilted axis?

  1. Step 1: Probability of up: cos²(60°/2) = cos²30° = 0.75.

  2. Step 2: Expected count: 2,000 × 0.75 = 1,500. Binomial scatter: √(2,000 × 0.75 × 0.25) = √375 ≈ 19, so a real run lands near 1,500 ± 19.

  3. Step 3: Average component: up results give +ħ/2 and down results −ħ/2, so the average is (ħ/2)(0.75 − 0.25) = ħ/4.

  4. Step 4: Check with the formula: (ħ/2)cos 60° = (ħ/2) × 0.5 = ħ/4, about 2.64×10⁻³⁵ J·s.

Answer

About 1,500 ± 19 atoms leave up; the average spin component along the tilted axis is ħ/4

Why it matters: No single atom ever reports ħ/4; each reports +ħ/2 or −ħ/2, and the classical-looking projection appears only in the average. Because cos²(θ/2) drops below 0.75 for any tilt beyond 60 degrees, 60 degrees is the largest tilt that still lets at least three-quarters of the atoms through the up exit.

Try it yourself first — then check each step.
Example 4

Proton spins in a 3-tesla MRI scanner

Problem

Find the proton resonance frequency and its wavelength in a 3.0-tesla scanner, the energy gap in electron-volts, the fractional excess of protons in the lower-energy spin state at body temperature, 310 kelvin, and the size of that excess in 1 millilitre of water.

  1. Step 1: Frequency: 42.58 MHz per tesla × 3.0 tesla = 127.7 MHz. Wavelength in vacuum: 2.998×10⁸ m/s ÷ 1.277×10⁸ hertz = 2.35 metres.

  2. Step 2: Energy gap: hf = 6.626×10⁻³⁴ J·s × 1.277×10⁸ hertz = 8.46×10⁻²⁶ joules, which is 5.3×10⁻⁷ electron-volts.

  3. Step 3: Thermal energy: kT = 1.381×10⁻²³ joules per kelvin × 310 kelvin = 4.28×10⁻²¹ joules, or 0.027 eV, about 50,000 times larger than the gap.

  4. Step 4: Fractional excess: about ΔE ÷ 2kT = 8.46×10⁻²⁶ ÷ 8.56×10⁻²¹ = 9.9×10⁻⁶, roughly 10 per million.

  5. Step 5: Hydrogen nuclei in 1 millilitre of water: 2 × (1 gram ÷ 18.015 grams per mole) × 6.022×10²³ per mole = 6.69×10²². Excess: 6.69×10²² × 9.9×10⁻⁶ = 6.6×10¹⁷.

Answer

127.7 MHz, a wavelength of 2.35 metres; a gap of 5.3×10⁻⁷ electron-volts; an excess of about 10 parts per million, which is about 6.6×10¹⁷ protons per millilitre

Why it matters: Magnetic resonance is a game of tiny imbalances in enormous crowds. Doubling the field doubles both the frequency and the imbalance, which is one reason many hospitals now run 3-tesla scanners alongside 1.5-tesla ones.

Try it yourself first — then check each step.
07Myth busters

What everyone gets wrong

Read the myth, decide whether you believed it, then bust it.

  • Myth #1

    Electrons are tiny spinning balls, and spin is just their rotation.

    Truth

    Spin is intrinsic angular momentum with no classical counterpart. The electron behaves as a point in every experiment so far; a ball even as large as the classical electron radius would need a surface speed above a hundred times the speed of light to carry ħ/2; its magnetism is twice what a spinning ball of charge would give for that angular momentum (a g-factor of about 2, not 1); and any rotation through space has whole-number l and an odd number of orientations, while electrons produce two beams. No rotating object needs 720 degrees to return to its starting state, yet a spin-one-half state does.

  • Myth #2

    Spin can point in any direction when measured, so a measurement along a tilted axis gives some in-between value.

    Truth

    A spin can be prepared pointing along any direction, but a measurement along any axis returns only +ħ/2 or −ħ/2. The direction of preparation sets only the odds, cos²(θ/2) for up. The smooth value (ħ/2)cos θ is an average over many atoms, never a single result, and the spin vector's length, about 0.87ħ, is larger than ħ/2, so it never lies exactly along any axis.

  • Myth #3

    Stern and Gerlach discovered electron spin in 1922.

    Truth

    They discovered that a component of atomic magnetism is quantized, but they believed they had confirmed the Bohr-Sommerfeld space quantization of orbital motion. Spin was proposed by Uhlenbeck and Goudsmit in 1925, and the two stripes were attributed to it only around 1927, when the ground states of silver, hydrogen and sodium were recognized to have no orbital angular momentum. Right experiment, wrong theory.

08Interactive lab

Your turn at the controls

Welcome to the Stern-Gerlach Sorter, where every magnet is a question and every atom must answer. An oven sprays silver atoms into a chain of up to three magnets. Set each one to Z, to X, or to any angle you like, and block either exit with a stop. Fire the beam and watch atoms land one at a time while the counters at every exit build up, so that single random answers grow into exact fractions.

Your tasks

0/4

How it connects to the theory

Each magnet measures spin along its own axis, and an open exit passes atoms in the matching state, so blocking an exit is preparing a state. The counters follow the rule of this chapter: an atom leaving one magnet's up exit leaves the next magnet's up exit with probability cos²(Δθ/2), where Δθ is the angle between the two magnets' axes. That gives 100 percent for Z then Z, 50 percent for Z then X, a fresh 50 percent at the end of Z then X then Z, 75 percent at a 60-degree tilt and 25 percent at 120 degrees. Each atom's answer is random, so the count from a run of N atoms scatters by about √(N·p·(1 − p)), a fraction of about √(p(1 − p)/N); long runs converge on the exact fractions, just as silver atoms did on Stern and Gerlach's plate.

Stern–Gerlach Sorter: Chain the Magnets loads as you scroll down.

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09Memory aids

Make it stick

Memory trick

Spell the object itself: SPINOR. S, Split, not smear: a spin-one-half beam makes exactly 2s + 1 = 2 stripes. P, Plus or minus ħ/2 along whatever axis you choose, and nothing in between. I, In-between angles set only the odds, cos²(θ/2) for up. N, New question, new dice: an X measurement erases the Z answer. O, One full turn flips the sign; two turns bring it home. R, Resonance: a photon whose energy hf matches the spin's energy gap flips it, at 28.0 GHz per tesla for electrons and 42.58 MHz per tesla for protons. For any tilted magnet, chant the half-angle recipe: halve the angle, take the cosine, square it.

Analogy — and where it breaks

Each atom is a witness who answers only yes or no. Ask 'Up along z?' and you get a firm answer; ask again and the answer repeats. Ask 'Up along x?' and the witness answers at random and forgets the first answer; ask about z once more and the reply is a coin toss. Where it breaks: a human witness keeps the full story in mind and merely chooses what to reveal, but the Z then X then Z experiment shows that an atom holds no hidden answer to the x question while it holds a definite z answer. And its odds are not whims but a precise law, cos²(θ/2).

The whole chapter in one line

Spin is built-in angular momentum: along any axis it answers only ±ħ/2, with odds cos²(θ/2), and each new question erases the old answer.

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10Games

Play it into long-term memory

Match the vocabulary, then take the Quiz Show. Score 70% or better to tick it off your checklist.

Vocab match · timed

Vocab Match

Match each term to its definition, against the clock.

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  • Finish with 3 mistakes or fewer to win
Live from the lab

Dr. Q's Quantum Quiz Show

Dr. Q, your host

Welcome, contestants! 8 questions, 30 seconds each, and one mad scientist judging you, lovingly. Answer fast for a speed bonus; answer right in a row and your points multiply.

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11Worksheet

Prove it on paper

Answer every question, check your work, and read the explanations — the stretch challenge is for the truly mad.

14 questions12 terms1 challenge

Work through every question with the lesson closed, then check yourself. Useful facts: a spin-½ component along any axis is +ħ/2 or −ħ/2; |+x⟩ = (1/√2)(|↑⟩ + |↓⟩); a spin prepared up along one axis gives up along an axis at angle θ with probability cos²(θ/2); the binomial scatter of a count is √(N·p·(1 − p)); h = 6.626×10⁻³⁴ J·s, c = 2.998×10⁸ m/s, 1 eV = 1.602×10⁻¹⁹ joules, μB = 9.274×10⁻²⁴ joules per tesla, the electron g-factor is 2.0023, and protons resonate at 42.58 MHz per tesla. Show every step in the calculation questions.

0/14 answered · saved on this device

Part A

Vocabulary

Spin
Intrinsic angular momentum carried by a particle itself rather than by its motion through space; for an electron, s = ½.
Spin quantum number
The number s fixing a particle's spin; its component along any axis takes the 2s + 1 values mₛħ, from −sħ to +sħ in whole steps.
Magnetic moment
A measure of how strongly something acts as a magnet, setting both the torque in a uniform field and the force in a non-uniform one; unit joules per tesla.
Bohr magneton
The natural unit of electron magnetism, μB = eħ/2mₑ ≈ 9.274×10⁻²⁴ joules per tesla.
Field gradient
The rate at which a magnetic field changes with position; only a gradient exerts a net force on a magnetic moment.
Stern-Gerlach apparatus
A magnet with a strong field gradient that sorts particles into separate beams according to their spin component along its axis.
Space quantization
The restriction of an angular momentum's component along a chosen axis to discrete values.
g-factor
The ratio of a particle's magnetic moment to its angular momentum, in natural units; about 2.0023 for electron spin, 1 for orbital motion.
Spinor
A two-component quantum state, such as a spin-½ state, that changes sign under a 360-degree rotation and returns to itself only after 720 degrees.
Larmor precession
The wheeling of a magnetic moment's direction around a magnetic field, at a rate proportional to the field.
Magnetic resonance
The absorption of radiation whose photon energy matches the energy gap between spin states in a magnetic field, flipping spins; the basis of NMR and MRI.
Electron spin resonance
Magnetic resonance of unpaired electron spins, near 28.0 GHz per tesla; discovered by Yevgeny Zavoisky in 1944.

Part B

Questions

Auto-checked except short answers, which you mark yourself.

  1. Question 1.Multiple choice

    Why did Stern and Gerlach need a strongly non-uniform magnetic field rather than simply a very strong uniform one?

  2. Question 2.Multiple choice

    Which feature of the result shows most directly that spin cannot be ordinary orbital angular momentum?

  3. Question 3.Multiple choice

    Atoms that left the up exit of a Z magnet pass a second magnet tilted 90 degrees (an X magnet). Its −x exit is blocked, and the survivors meet a third magnet, also an X magnet. What fraction of the atoms entering the third magnet leave its +x exit?

  4. Question 4.True or false

    A spin prepared up along z and measured along an axis 45 degrees away can return the result (ħ/2)cos 45°.

  5. Question 5.True or false

    After a Z magnet and then an X magnet, an atom leaving the +x exit has no definite z-spin.

  6. Question 6.True or false

    Rotating an electron's spin state through a full 360 degrees leaves the state exactly unchanged.

  7. Question 7.Fill in the blank

    A particle of spin s is split by a Stern-Gerlach magnet into beams.

  8. Question 8.Fill in the blank

    The natural unit of electron magnetism, eħ/2mₑ ≈ 9.274×10⁻²⁴ joules per tesla, is called the .

  9. Question 9.Short answer

    Explain how the Z then X then Z experiment rules out the idea that each atom carries fixed, hidden values of both its z-spin and its x-spin.

  10. Question 10.Short answer

    In what sense was the Stern-Gerlach experiment a case of 'right experiment, wrong theory'?

  11. Question 11.Calculation

    4,000 atoms, all up along z, enter a magnet tilted 45 degrees from z. How many leave its up exit, and what is the typical scatter? What is the average spin component along the tilted axis, as a multiple of ħ?

    Give a number and units. 6.63×10⁻³⁴, 6.63e-34 and 6.63 x 10^-34 all work.

  12. Question 12.Calculation

    8,000 atoms, all up along z, enter a magnet tilted 60 degrees from z; its down exit is blocked. The survivors then pass a Z magnet. How many atoms leave each exit of the Z magnet?

    This one asks for more than one value — give each, with its units.

  13. Question 13.Calculation

    A hospital MRI scanner has a 1.5-tesla magnet. Find the proton resonance frequency, the wavelength of radio waves at that frequency, and the photon energy in electron-volts.

    This one asks for more than one value — give each, with its units.

  14. Question 14.Calculation

    An electron spin resonance spectrometer works at 0.35 tesla. Find the resonance frequency of a free electron spin, and compare it with the proton resonance frequency in the same field.

    This one asks for more than one value — give each, with its units.

Part C · optional, dangerous, extremely rewarding

Mad scientist challenge

The 720-degree neutron. In a neutron interferometer, one path passes through a magnetic field that makes the neutron spin precess by an angle α, while the other path is left alone. When the paths recombine, the intensity in one output is I(α) = (I₀/2)(1 + cos(α/2)). (a) Find I(α) for α = 0, 180, 360, 540 and 720 degrees. (b) What would the same formula give at 360 degrees if spin states behaved like ordinary arrows, with cos α in place of cos(α/2)? (c) Thermal neutrons at 2,200 m/s cross a field region 2.0 centimetres long. The precession angle is α = γ·B·t, where t is the time spent in the field and γ = 1.832×10⁸ radians per second per tesla. What field gives α = 720 degrees? (d) A minus sign in front of a whole state is unobservable, yet this experiment sees it. Explain why there is no contradiction.

12Wrap-up

Recap & sign-off

Key takeaways

  • In 1922 Stern and Gerlach sent silver atoms through a strongly non-uniform magnetic field and found two separate stripes, not a smear: a component of atomic angular momentum is quantized.
  • The cause, recognized by 1927, is electron spin: intrinsic angular momentum with s = ½, whose component along any axis is only +ħ/2 or −ħ/2.
  • The electron is not a spinning ball: it behaves as a point, its spin g-factor is about 2, and two beams require a half-integer that no rotation through space can supply.
  • Chained magnets show that measurement changes the state: Z then Z repeats, Z then X splits fifty-fifty, and Z then X then Z erases the original z answer.
  • In the z basis, |+x⟩ = (1/√2)(|↑⟩ + |↓⟩); for a magnet tilted by θ, P(up) = cos²(θ/2), and only the average, (ħ/2)cos θ, varies smoothly.
  • A 360-degree rotation reverses the sign of a spin-one-half state and 720 degrees restores it, as neutron interferometers confirmed in 1975.
  • Spin magnetism powers magnetic resonance: electron spins resonate near 28.0 GHz per tesla, protons at 42.58 MHz per tesla, and MRI uses field gradients to turn frequency into position.
Dr. Q signs off

Back to the blackboard, and then back to the beam line! Tonight silver atoms refused to smear, magnets asked questions that erased each other's answers, and an electron needed two full turns to come home. Hold on to that humble two-valuedness, up or down and nothing in between, because next session it builds the periodic table. Wolfgang Pauli will forbid any two electrons from sharing a state, and from that single prohibition come shells, chemistry, and the solidity of the chair beneath you.

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